In the previous article we have discussed Java Program to Compute (b+c)(c+a)(a+b) where Value of a, b and c are Given
In this program we are going to see how to compute (a+b+c)(b+c-a)(c+a-b)(a+b-c) where value of a, b, and c are given by using Java Programming language.
Java Program to Compute (a+b+c)(b+c-a)(c+a-b)(a+b-c) where Value of a, b, and c are Given
The formula of (a+b+c)(b+c-a)(c+a-b)(a+b-c) is given below.
(a+b+c)(b+c-a)(c+a-b)(a+b-c) = 2a2b2 + 2b2c2 + 2c2a2 – a4 – b4 – c4
Now we will convert this into a valid Java expression.
Let x= (a+b+c)(b+c-a)(c+a-b)(a+b-c)
= 2a2b2 + 2b2c2 + 2c2a2 – a4 – b4 – c4
= (2*a*a*b*b)+( 2*b*b*c*c)+( 2*c*c*a*a)-(a*a*a*a)-(b*b*b*b)-(c*c*c*c)
Or, (2*Math.pow(a,2)* Math.pow(b,2)) + (2*Math.pow(b,2)* Math.pow(c,2)) + (2*Math.pow(c,2)* Math.pow(a,2)) – (Math.pow(a,4)) – (Math.pow(b,4)) – (Math.pow(c,4))
Example:
Suppose a=4, b=2 and c= 3, Then (a+b+c)(b+c-a)(c+a-b)(a+b-c) = (2*a*a*b*b)+( 2*b*b*c*c)+( 2*c*c*a*a)-(a*a*a*a)-(b*b*b*b)-(c*c*c*c) = (2*4*4*2*2)+( 2*2*2*3*3)+( 2*3*3*4*4)-(4*4*4*4)-(2*2*2*2)-(3*3*3*3) = 135
Now let’s see different ways to compute (a+b+c)(b+c-a)(c+a-b)(a+b-c)
Method-1: Java Program to Compute (a+b+c)(b+c-a)(c+a-b)(a+b-c) where Value of a, b, and c are Given By Using Static Input Value
Approach:
- Declare and initialize two integer variables say
a
,b
, andc
. - By using the formula compute (a+b+c)(b+c-a)(c+a-b)(a+b-c)
- Print the result.
Program:
class Main { public static void main(String[] args) { //declare the first integer variable with a integer value int a= 4; System.out.println("a= " +a); //declare the second integer variable with a integer value int b= 2; System.out.println("b= "+b); //declare the second integer variable with a integer value int c= 3; System.out.println("c= "+c); //declare another integer variable and assigned the formulated value to it. int d= (2*a*a*b*b)+( 2*b*b*c*c)+( 2*c*c*a*a)-(a*a*a*a)-(b*b*b*b)-(c*c*c*c); System.out.println("(a+b+c)(b+c-a)(c+a-b)(a+b-c)= "+d); } }
Output: a= 4 b= 2 c= 3 (a+b+c)(b+c-a)(c+a-b)(a+b-c)= 135
Method-2: Java Program to Compute (a+b+c)(b+c-a)(c+a-b)(a+b-c) where Value of a, b, and c are Given y Using User Input Value and Pow()
Approach:
- Declare three integer variables say
a
,b
, andc
. - Take the value of
a
,b
, andc
as user input by using Scanner class. - Then By using the formula compute (a+b+c)(b+c-a)(c+a-b)(a+b-c)
- Print the result.
Program:
import java.lang.Math; import java.util.Scanner; class Main { public static void main(String[] args) { //create object of scanner class. Scanner sc=new Scanner(System.in); System.out.print("a= "); //Take the first input from the user. int a= sc.nextInt(); System.out.print("b= "); //Take the second input from the user. int b= sc.nextInt(); System.out.print("c= "); //Take the first input from the user. int c= sc.nextInt(); //declare another integer variable and assigned the formulated value to it. double d= (2*Math.pow(a,2)* Math.pow(b,2)) + (2*Math.pow(b,2)* Math.pow(c,2)) + (2*Math.pow(c,2)* Math.pow(a,2)) - (Math.pow(a,4)) - (Math.pow(b,4)) - (Math.pow(c,4)); System.out.println("(a+b+c)(b+c-a)(c+a-b)(a+b-c)= "+(int)d); } }
Output: a= 34 b= 45 c= 56 (a+b+c)(b+c-a)(c+a-b)(a+b-c)= 9361575
Method-3: Java Program to Compute (a+b+c)(b+c-a)(c+a-b)(a+b-c) where Value of a, b, and c are Given By Using User Defined Method
Approach:
- Declare two integer variables say
a
,b
, andc
- Take the value of
a
,b
, andc
as user input by using Scanner class. - Then call a user defined method say
computeValue()
and pass a, b, and c as parameter. - Then inside method by using the formula compute (a+b+c)(b+c-a)(c+a-b)(a+b-c)
- Print the result.
Program:
import java.util.Scanner; class Main { public static void main(String[] args) { //create object of scanner class. Scanner sc=new Scanner(System.in); System.out.print("a= "); //Take the first input from the user. int a= sc.nextInt(); System.out.print("b= "); //Take the second input from the user. int b= sc.nextInt(); System.out.print("c= "); //Take the first input from the user. int c= sc.nextInt(); //call the function computeValue(a,b,c); } //define the method public static void computeValue(int a, int b,int c) { //declare another integer variable and assigned the formulated value to it. int d= (2*a*a*b*b)+( 2*b*b*c*c)+( 2*c*c*a*a)-(a*a*a*a)-(b*b*b*b)-(c*c*c*c); System.out.println("(a+b+c)(b+c-a)(c+a-b)(a+b-c)= "+d); } }
Output: a= 12 b= 34 c= 32 (a+b+c)(b+c-a)(c+a-b)(a+b-c)= 589680
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