Java Program to Compute (a+b+c)(bc+ca+ab)-abc where Value of a, b and c are Given

In the previous article we have discussed Java Program to Compute (a+b+c)(b+c-a)(c+a-b)(a+b-c) where Value of a, b and c are Given

In this program we are going to see how to compute (a+b+c)(bc+ca+ab)-abc where value of a, b, and c are given.

Java Program to Compute (a+b+c)(bc+ca+ab)-abc where Value of a, b and c are Given

The formula of (a+b+c)(bc+ca+ab)-abc is given below.

(a+b+c)(bc+ca+ab)-abc = (a+b)(b+c)(c+a)

Now we will convert this into a valid Java expression.

Let x= (a+b+c)(bc+ca+ab)-abc

=(a+b)(b+c)(c+a)

=((a+b)*(b+c)*(c+a))

Example:

Suppose a=4, b=2 and c= 3 ,Then

(a+b+c)(bc+ca+ab)-abc 
= ((a+b)*(b+c)*(c+a))
=((4+2)*(2+3)*(3+4))
= 210

Now let’s see different ways to compute (a+b+c)(bc+ca+ab)-abc

By Using Static Input Value
By Using User Input Value
By Using User Defined Method

Method-1: Java Program to Compute (a+b+c)(bc+ca+ab)-abc where Value of a, b and c are Given By Using Static Input Value

Approach:

Declare and initialize three integer variables say a, b and c
By using the formula compute (a+b+c)(bc+ca+ab)-abc .
Print the result.

Program:

class Main
{
    public static void main(String[] args)
    {
        //declare the first integer variable with a integer value
        int a= 4;
        System.out.println("a= " +a);
        //declare the second integer variable with a integer value
        int b= 2;
        System.out.println("b= "+b);
        //declare the third integer variable with a integer value
        int c= 3;
        System.out.println("c= "+c); 
        //declare another integer variable and assigned the formulated value to it.
        int d=((a+b)*(b+c)*(c+a));
        System.out.println("(a+b+c)(bc+ca+ab)-abc= "+d);
    }
}

Output:

a= 4
b= 2
c= 3
(a+b+c)(bc+ca+ab)-abc= 210

Method-2: Java Program to Compute (a+b+c)(bc+ca+ab)-abc where Value of a, b and c are Given By Using User Input Value

Approach:

Declare three integer variables say a, b and c
Prompt the user to enter the values to the corresponding variables.
Then By using the formula compute (a+b+c)(bc+ca+ab)-abc .
Print the result.

Program:

import java.util.Scanner;
class Main
{
    public static void main(String[] args)
    {
        //create object of scanner class.
        Scanner sc=new Scanner(System.in);
        System.out.print("a= ");
        //Take the first input from the user.
        int a= sc.nextInt();
        System.out.print("b= ");
        //Take the second input from the user.
        int b= sc.nextInt();
        System.out.print("c= ");
        //Take the third input from the user.
        int c= sc.nextInt();
        //declare another integer variable and assigned the formulated value to it.
        int d=((a+b)*(b+c)*(c+a));
        System.out.println("(a+b+c)(bc+ca+ab)-abc= "+d);
    }
}

Output:

a= 12
b= 23
c= 34
(a+b+c)(bc+ca+ab)-abc= 91770

Method-3: Java Program to Compute (a+b+c)(bc+ca+ab)-abc where Value of a, b and c are Given By Using User Defined Method

Approach:

Declare three integer variables say a, b and c
Prompt the user to enter the values to the corresponding variables.
Then call the user defined method say computeValue() and pass a, b and c as parameter.
Then inside that method by using the formula compute (a+b+c)(bc+ca+ab)-abc.
Print the result.

Program:

import java.util.Scanner;
class Main
{
    public static void main(String[] args)
    {
        //create object of scanner class.
        Scanner sc=new Scanner(System.in);
        System.out.print("a= ");
        //Take the first input from the user.
        int a= sc.nextInt();
        System.out.print("b= ");
        //Take the second input from the user.
        int b= sc.nextInt();
        System.out.print("c= ");
        //Take the third input from the user.
        int c= sc.nextInt();
        //call the function
        computeValue(a,b,c);
    }
    
    //define the method
    public static void computeValue(int a, int b,int c)
    {
        //declare another integer variable and assigned the formulated value to it.
        int d=((a+b)*(b+c)*(c+a));
        System.out.println("(a+b+c)(bc+ca+ab)-abc= "+d);
    }
}

Output:

a= 11
b= 22
c= 33
(a+b+c)(bc+ca+ab)-abc= 79860

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