# Java Program to Compute (a+b+c)(bc+ca+ab)-abc where Value of a, b and c are Given

In the previous article we have discussed Java Program to Compute (a+b+c)(b+c-a)(c+a-b)(a+b-c) where Value of a, b and c are Given

In this program we are going to see how to compute (a+b+c)(bc+ca+ab)-abc where value of a, b, and c are given.

## Java Program to Compute (a+b+c)(bc+ca+ab)-abc where Value of a, b and c are Given

The formula of (a+b+c)(bc+ca+ab)-abc is given below.

(a+b+c)(bc+ca+ab)-abc = (a+b)(b+c)(c+a)

Now we will convert this into a valid Java expression.

Let x= (a+b+c)(bc+ca+ab)-abc

=(a+b)(b+c)(c+a)

=((a+b)*(b+c)*(c+a))

Example:

Suppose a=4, b=2 and c= 3 ,Then

(a+b+c)(bc+ca+ab)-abc
= ((a+b)*(b+c)*(c+a))
=((4+2)*(2+3)*(3+4))
= 210

Now let’s see different ways to compute (a+b+c)(bc+ca+ab)-abc

### Method-1: Java Program to Compute (a+b+c)(bc+ca+ab)-abc where Value of a, b and c are Given By Using Static Input Value

Approach:

• Declare and initialize three integer variables say a, b and c
• By using the formula compute (a+b+c)(bc+ca+ab)-abc .
• Print the result.

Program:

class Main
{
public static void main(String[] args)
{
//declare the first integer variable with a integer value
int a= 4;
System.out.println("a= " +a);
//declare the second integer variable with a integer value
int b= 2;
System.out.println("b= "+b);
//declare the third integer variable with a integer value
int c= 3;
System.out.println("c= "+c);
//declare another integer variable and assigned the formulated value to it.
int d=((a+b)*(b+c)*(c+a));
System.out.println("(a+b+c)(bc+ca+ab)-abc= "+d);
}
}

Output:

a= 4
b= 2
c= 3
(a+b+c)(bc+ca+ab)-abc= 210

### Method-2: Java Program to Compute (a+b+c)(bc+ca+ab)-abc where Value of a, b and c are Given By Using User Input Value

Approach:

• Declare three integer variables say a, b and c
• Prompt the user to enter the values to the corresponding variables.
• Then By using the formula compute (a+b+c)(bc+ca+ab)-abc .
• Print the result.

Program:

import java.util.Scanner;
class Main
{
public static void main(String[] args)
{
//create object of scanner class.
Scanner sc=new Scanner(System.in);
System.out.print("a= ");
//Take the first input from the user.
int a= sc.nextInt();
System.out.print("b= ");
//Take the second input from the user.
int b= sc.nextInt();
System.out.print("c= ");
//Take the third input from the user.
int c= sc.nextInt();
//declare another integer variable and assigned the formulated value to it.
int d=((a+b)*(b+c)*(c+a));
System.out.println("(a+b+c)(bc+ca+ab)-abc= "+d);
}
}

Output:

a= 12
b= 23
c= 34
(a+b+c)(bc+ca+ab)-abc= 91770

### Method-3: Java Program to Compute (a+b+c)(bc+ca+ab)-abc where Value of a, b and c are Given By Using User Defined Method

Approach:

• Declare three integer variables say a, b and c
• Prompt the user to enter the values to the corresponding variables.
• Then call the user defined method say computeValue() and pass a, b and c as parameter.
• Then inside that method by using the formula compute (a+b+c)(bc+ca+ab)-abc.
• Print the result.

Program:

import java.util.Scanner;
class Main
{
public static void main(String[] args)
{
//create object of scanner class.
Scanner sc=new Scanner(System.in);
System.out.print("a= ");
//Take the first input from the user.
int a= sc.nextInt();
System.out.print("b= ");
//Take the second input from the user.
int b= sc.nextInt();
System.out.print("c= ");
//Take the third input from the user.
int c= sc.nextInt();
//call the function
computeValue(a,b,c);
}

//define the method
public static void computeValue(int a, int b,int c)
{
//declare another integer variable and assigned the formulated value to it.
int d=((a+b)*(b+c)*(c+a));
System.out.println("(a+b+c)(bc+ca+ab)-abc= "+d);
}
}

Output:

a= 11
b= 22
c= 33
(a+b+c)(bc+ca+ab)-abc= 79860

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