# Java Program to Compute a3(b-c)+b3(c-a)+c3(a-b) where Value of a, b, and c are Given

In the previous article we have discussed Java Program to Compute a(b2-c2)+b(c2-a2)+c(a2-b2) where Value of a, b and c are Given

In this program we are going to see how to compute  a3(b-c)+b3(c-a)+c3(a-b) where value of a, b, and c are given by using Java Programming language.

## Java Program to Compute a3(b-c)+b3(c-a)+c3(a-b) where Value of a, b, and c are Given

The formula of a3(b-c)+b3(c-a)+c3(a-b) is given below.

a3(b-c)+b3(c-a)+c3(a-b) = (a-b)(b-c)(a-c)(a+b+c)

Now we will convert this into a valid Java expression.

Let x= a3(b-c)+b3(c-a)+c3(a-b)

=(a-b)(b-c)(a-c)(a+b+c)

=  (a-b)*(b-c)* (a-c)*(a+b+c)

Example:

Suppose a=4, b=2 and c= 3, Then

a3(b-c)+b3(c-a)+c3(a-b)
= (a-b)*(b-c)* (a-c)*(a+b+c)
= (4-2)*(2-3)*(4-3)*(4+2+3)
= -18

Now let’s see different ways to compute a3(b-c)+b3(c-a)+c3(a-b)

### Method-1: Java Program to Compute a3(b-c)+b3(c-a)+c3(a-b) where Value of a, b, and c are Given By Using Static Input Value

Approach:

• Declare and initialize three integer variables say a, b, and c.
• By using the formula compute a3(b-c)+b3(c-a)+c3(a-b)
• Print the result.

Program:

class Main
{
public static void main(String[] args)
{
//declare the first integer variable with an integer value
int a= 4;
System.out.println("a= " +a);
//declare the second integer variable with an integer value
int b= 2;
System.out.println("b= "+b);
//declare the second integer variable with an integer value
int c= 3;
System.out.println("c= "+c);

//declare another integer variable and assigned the formulated value to it.
int d=(a-b)*(b-c)* (a-c)*(a+b+c);
System.out.println("a3(b-c)+b3(c-a)+c3(a-b)= "+d);
}
}

Output:

a= 4
b= 2
c= 3
a3(b-c)+b3(c-a)+c3(a-b)= -18

### Method-2: Java Program to Compute a3(b-c)+b3(c-a)+c3(a-b) where Value of a, b, and c are Given By Using User Input Value

Approach:

• Declare three integer variables say a, b, and c.
• Take the value of a, b, and c as user input by using Scanner class.
• Then By using the formula compute a3(b-c)+b3(c-a)+c3(a-b)
• Print the result.

Program:

import java.util.Scanner;
class Main
{
public static void main(String[] args)
{
//create object of scanner class.
Scanner sc=new Scanner(System.in);
System.out.print("a= ");
//Take the first input from the user.
int a= sc.nextInt();
System.out.print("b= ");
//Take the second input from the user.
int b= sc.nextInt();
System.out.print("c= ");
//Take the first input from the user.
int c= sc.nextInt();
//declare another integer variable and assigned the formulated value to it.
int d=(a-b)*(b-c)* (a-c)*(a+b+c);
System.out.println("a3(b-c)+b3(c-a)+c3(a-b)= "+d);
}
}

Output:

a= 23
b= 45
c= 65
a3(b-c)+b3(c-a)+c3(a-b)= -2457840

### Method-3: Java Program to Compute a3(b-c)+b3(c-a)+c3(a-b) where Value of a, b, and c are Given By Using User Defined Method

Approach:

• Declare three integer variables say a, b, and c.
• Take the value of a, b, and c as user input by using Scanner class.
• Then call a user defined method say computeValue() and pass a, b, and c as parameter.
• Then inside method by using the formula compute a3(b-c)+b3(c-a)+c3(a-b)
• Print the result.

Program:

import java.util.Scanner;
class Main
{
public static void main(String[] args)
{
//create object of scanner class.
Scanner sc=new Scanner(System.in);
System.out.print("a= ");
//Take the first input from the user.
int a= sc.nextInt();
System.out.print("b= ");
//Take the second input from the user.
int b= sc.nextInt();
System.out.print("c= ");
//Take the first input from the user.
int c= sc.nextInt();
//call the function
computeValue(a,b,c);
}

//computeValue() user defined method
public static void computeValue(int a, int b, int c)
{
//declare another integer variable and assigned the formulated value to it.
int d=(a-b)*(b-c)* (a-c)*(a+b+c);
System.out.println("a3(b-c)+b3(c-a)+c3(a-b)= "+d);
}
}

Output:

a= 12
b= 23
c= 21
a3(b-c)+b3(c-a)+c3(a-b)= 11088

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