In the previous article we have discussed Java Program to Compute a3(b-c)+b3(c-a)+c3(a-b) where Value of a, b and c are Given
In this program we are going to see how to compute (a+b)(b+c)(c+a) where value of a, b, and c are given by using Java Programming language.
Java Program to Compute (a+b)(b+c)(c+a) where Value of a, b, and c are Given
The formula of (a+b)(b+c)(c+a) is given below.
(a+b)(b+c)(c+a) = ab(a+b) + bc(b+c) + ca(c+a) + 2abc
Now we will convert this into a valid Java expression.
Let x= (a+b)(b+c)(c+a)
= ab(a+b) + bc(b+c) + ca(c+a) + 2abc
= a*b*(a+b) + b*c*(b+c) + c*a*(c+a) + 2*a*b*c
Example:
Suppose a=4, b=2 and c= 3, Then (a+b)(b+c)(c+a) = a*b*(a+b) + b*c*(b+c) + c*a*(c+a) + 2*a*b*c = 4*2*(4+2) + 2*3*(2+3) + 3*4*(3+4) + 2*4*2*3 = 210
Now let’s see different ways to compute (a+b)(b+c)(c+a).
Method-1: Java Program to Compute (a+b)(b+c)(c+a) where Value of a, b, and c are Given By Using Static Input Value
Approach:
- Declare three integer variables say
a
,b
, andc
. - By using the formula compute (a+b)(b+c)(c+a)
- Print the result.
Program:
class Main { public static void main(String[] args) { //declare the first integer variable with an integer value int a= 4; System.out.println("a= " +a); //declare the second integer variable with an integer value int b= 2; System.out.println("b= "+b); //declare the second integer variable with an integer value int c= 3; System.out.println("c= "+c); //declare another integer variable and assigned the formulated value to it. int d= a*b*(a+b) + b*c*(b+c) + c*a*(c+a) + 2*a*b*c; System.out.println("(a+b)(b+c)(c+a)= "+d); } }
Output: a= 4 b= 2 c= 3 (a+b)(b+c)(c+a)= 210
Method-2: Java Program to Compute (a+b)(b+c)(c+a) where Value of a, b, and c are Given By Using User Input Value
Approach:
- Declare three integer variables say
a
,b
, andc
. - Take the value of a, b, and c as user input by using Scanner class.
- Then By using the formula compute (a+b)(b+c)(c+a)
- Print the result.
Program:
import java.util.Scanner; class Main { public static void main(String[] args) { //create object of scanner class. Scanner sc=new Scanner(System.in); System.out.print("a= "); //Take the first input from the user. int a= sc.nextInt(); System.out.print("b= "); //Take the second input from the user. int b= sc.nextInt(); System.out.print("c= "); //Take the third input from the user. int c= sc.nextInt(); //declare another integer variable and assigned the formulated value to it. int d= a*b*(a+b) + b*c*(b+c) + c*a*(c+a) + 2*a*b*c; System.out.println("(a+b)(b+c)(c+a)= "+d); } }
Output: a= 8 b= 9 c= 10 (a+b)(b+c)(c+a)= 5814
Method-3: Java Program to Compute (a+b)(b+c)(c+a) where Value of a, b, and c are Given By Using User Defined Method
Approach:
- Declare three integer variables say
a
,b
, andc
. - Take the value of
a
,b
andc
as user input by using Scanner class. - Then call a user defined method say
computeValue()
and pass a, b, and c as parameter. - Then inside method by using the formula compute (a+b)(b+c)(c+a)
- Print the result.
Program:
import java.util.Scanner; class Main { public static void main(String[] args) { //create object of scanner class. Scanner sc=new Scanner(System.in); System.out.print("a= "); //Take the first input from the user. int a= sc.nextInt(); System.out.print("b= "); //Take the second input from the user. int b= sc.nextInt(); System.out.print("c= "); //Take the third input from the user. int c= sc.nextInt(); //call the function computeValue(a,b,c); } //define the method public static void computeValue(int a, int b,int c) { //declare another integer variable and assigned the formulated value to it. int d= a*b*(a+b) + b*c*(b+c) + c*a*(c+a) + 2*a*b*c; System.out.println("(a+b)(b+c)(c+a)= "+d); } }
Output: a= 5 b= 6 c= 7 (a+b)(b+c)(c+a)= 1716
Guys who are serious about learning the concepts of the java programming language should practice this list of programs in java and get a good grip on it for better results in exams or interviews.
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