Java Program to Compute (a+b)(b+c)(c+a) where Value of a, b, and c are Given

In the previous article we have discussed Java Program to Compute a3(b-c)+b3(c-a)+c3(a-b) where Value of a, b and c are Given

In this program we are going to see how to compute  (a+b)(b+c)(c+a) where value of a, b, and c are given by using Java Programming language.

Java Program to Compute (a+b)(b+c)(c+a) where Value of a, b, and c are Given

The formula of (a+b)(b+c)(c+a) is given below.

(a+b)(b+c)(c+a) = ab(a+b) + bc(b+c) + ca(c+a) + 2abc

Now we will convert this into a valid Java expression.

Let x= (a+b)(b+c)(c+a)

= ab(a+b) + bc(b+c) + ca(c+a) + 2abc

=  a*b*(a+b) + b*c*(b+c) + c*a*(c+a) + 2*a*b*c

Example:

Suppose a=4, b=2 and c= 3, Then

(a+b)(b+c)(c+a) = a*b*(a+b) + b*c*(b+c) + c*a*(c+a) + 2*a*b*c
= 4*2*(4+2) + 2*3*(2+3) + 3*4*(3+4) + 2*4*2*3
= 210

Now let’s see different ways to compute (a+b)(b+c)(c+a).

Method-1: Java Program to Compute (a+b)(b+c)(c+a) where Value of a, b, and c are Given By Using Static Input Value

Approach:

• Declare three integer variables say a, b, and c.
• By using the formula compute (a+b)(b+c)(c+a)
• Print the result.

Program:

class Main
{
public static void main(String[] args)
{
//declare the first integer variable with an integer value
int a= 4;
System.out.println("a= " +a);
//declare the second integer variable with an integer value
int b= 2;
System.out.println("b= "+b);
//declare the second integer variable with an integer value
int c= 3;
System.out.println("c= "+c);

//declare another integer variable and assigned the formulated value to it.
int d= a*b*(a+b) + b*c*(b+c) + c*a*(c+a) + 2*a*b*c;
System.out.println("(a+b)(b+c)(c+a)= "+d);
}
}

Output:

a= 4
b= 2
c= 3
(a+b)(b+c)(c+a)= 210

Method-2: Java Program to Compute (a+b)(b+c)(c+a) where Value of a, b, and c are Given By Using User Input Value

Approach:

• Declare three integer variables say a, b, and c.
• Take the value of a, b, and c as user input by using Scanner class.
• Then By using the formula compute (a+b)(b+c)(c+a)
• Print the result.

Program:

import java.util.Scanner;
class Main
{
public static void main(String[] args)
{
//create object of scanner class.
Scanner sc=new Scanner(System.in);
System.out.print("a= ");
//Take the first input from the user.
int a= sc.nextInt();
System.out.print("b= ");
//Take the second input from the user.
int b= sc.nextInt();
System.out.print("c= ");
//Take the third input from the user.
int c= sc.nextInt();
//declare another integer variable and assigned the formulated value to it.
int d= a*b*(a+b) + b*c*(b+c) + c*a*(c+a) + 2*a*b*c;
System.out.println("(a+b)(b+c)(c+a)= "+d);
}
}

Output:

a= 8
b= 9
c= 10
(a+b)(b+c)(c+a)= 5814

Method-3: Java Program to Compute (a+b)(b+c)(c+a) where Value of a, b, and c are Given By Using User Defined Method

Approach:

• Declare three integer variables say a, b, and c.
• Take the value of a, b and c as user input by using Scanner class.
• Then call a user defined method say computeValue() and pass a, b, and c as parameter.
• Then inside method by using the formula compute (a+b)(b+c)(c+a)
• Print the result.

Program:

import java.util.Scanner;
class Main
{
public static void main(String[] args)
{
//create object of scanner class.
Scanner sc=new Scanner(System.in);
System.out.print("a= ");
//Take the first input from the user.
int a= sc.nextInt();
System.out.print("b= ");
//Take the second input from the user.
int b= sc.nextInt();
System.out.print("c= ");
//Take the third input from the user.
int c= sc.nextInt();
//call the function
computeValue(a,b,c);
}

//define the method
public static void computeValue(int a, int b,int c)
{
//declare another integer variable and assigned the formulated value to it.
int d= a*b*(a+b) + b*c*(b+c) + c*a*(c+a) + 2*a*b*c;
System.out.println("(a+b)(b+c)(c+a)= "+d);
}
}

Output:

a= 5
b= 6
c= 7
(a+b)(b+c)(c+a)= 1716

Guys who are serious about learning the concepts of the java programming language should practice this list of programs in java and get a good grip on it for better results in exams or interviews.

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