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A binary search is an algorithm for finding a specific element in a list. Assume we have a list of a thousand elements and we need to find the index location of a specific element. Using the binary search algorithm, we can quickly determine the index location of an element.
There are several search algorithms, but binary search is the most widely used.
To use the binary search algorithm, the elements in the list must be sorted. If the elements are not already sorted, sort them first.
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given_elements =[2, 7, 3, 4, 9, 15] key= 9
Element 9 is found at index 4
Binary Search Algorithm in Python
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- We write a function that takes two arguments, the first of which is of which is the list and the second of which is the objective to be found.
- We declare two variables start and end, which point to the list’s start (0) and end (length – 1), respectively.
- Since the algorithm would not accept items outside of this range, these two variables are responsible for removing items from the quest.
- The next loop will continue to locate and delete items as long as the start is less than or equal to the end, since the only time the start exceeds the end is if the item is not on the list.
- We find the integer value of the mean of start and end within the loop and use it as the list’s middle object.
Below is the implementation of linear search:
# function which return index if element is present else return -1 def binarySearch(given_list, key): lowindex = 0 highindex = len(given_list) - 1 midindex = 0 # loop till lowindex is less than or equal to highindex while lowindex <= highindex: # Modify midindex with average of high index and lowindex midindex = (highindex + lowindex) // 2 # If key is greater than mid element ignore left half side of list if given_list[midindex] < key: lowindex = midindex + 1 # If key is less than mid element ignore right half side of list elif given_list[midindex] > key: highindex = midindex - 1 # Else the element is present at mid index else: return midindex # if any value is not returned then element is not present in list return -1 # given_list given_list = [2, 7, 3, 4, 9, 15] # given key key = 9 # sort the list given_list.sort() # passing the given_list and key to binarySearch function res = binarySearch(given_list, key) # if result is equal to -1 then element is not present in list if(res == -1): print("Given element(key) is not found in list") else: print("Element", key, "is found at index", res)
Element 9 is found at index 4
Consider a basic searching algorithm such as linear search, in which we must go through each element one by one before we find what we’re looking for. This means that for larger input sizes, the time it takes to find an element grows in lockstep with the input size. Its time complexity is O measurably (n).
The term “time complexity” refers to the measurement of how quick or efficient an algorithm is. The time complexity of Binary Search is “O(log2n),” which means that if we double the size of the input list, the algorithm can only perform one additional iteration.
In the same way, if the input size is multiplied by a thousand, the loop would only need to run 10 times more.
Remember that half of the list is removed with each iteration, so eliminating the entire list won’t take long.
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