Java Program to Compute a2(b-c)+b2(c-a)+c2(a-b) where Value of a, b, and c are Given

In the previous article we have discussed Java Program to Compute (b-c)2+(c-a)2+(a-b)2 where Value of a, b and c are Given

In this program we are going to see how to compute a²(b-c)+b²(c-a)+c²(a-b) where value of a, b, and c are given by using Java Programming language.

Java Program to Compute a2(b-c)+b2(c-a)+c2(a-b) where Value of a, b, and c are Given

The formula of a²(b-c)+b²(c-a)+c²(a-b) is given below.

a²(b-c)+b²(c-a)+c²(a-b) = (a-b)(b-c)(a-c)

Now we will convert this into a valid Java expression.

Let x= (a-b)(b-c)(a-c)

= (a-b)*(b-c)*(a-c)

Example:

Suppose a=4, b=2 and c= 3, Then

a2(b-c)+b2(c-a)+c2(a-b)
= (a-b)*(b-c)*(a-c)
=(4-2)*(2-3)*(4-3)
= -2

Now let’s see different ways to compute a²(b-c)+b²(c-a)+c²(a-b)

By Using Static Input Value
By Using User Input Value
By Using User Defined Method

Method-1: Java Program to Compute a2(b-c)+b2(c-a)+c2(a-b) where Value of a, b, and c are Given By Using Static Input Value

Approach:

Declare and initialize three integer variables say a, b, and c.
By using the formula compute a²(b-c)+b²(c-a)+c²(a-b)
Print the result.

Program:

class Main
{
    public static void main(String[] args)
    {
        //declare the first integer variable with a integer value
        int a= 4;
        System.out.println("a= " +a);
        //declare the second integer variable with a integer value
        int b= 2;
        System.out.println("b= "+b);
        //declare the second integer variable with a integer value
        int c= 3;
        System.out.println("c= "+c);

        //declare another integer variable and assigned the formulated value to it.
        int d=(a-b)*(b-c)*(a-c);
        System.out.println("a2(b-c)+b2(c-a)+c2(a-b)= "+d);
    }
}

Output:

a= 4
b= 2
c= 3
a2(b-c)+b2(c-a)+c2(a-b)= -2

Method-2: Java Program to Compute a2(b-c)+b2(c-a)+c2(a-b) where Value of a, b, and c are Given By Using User Input Value

Approach:

Declare three integer variables say a, b, and c.
Take the value of a, b, and c as user input by using Scanner class.
Then By using the formula compute a²(b-c)+b²(c-a)+c²(a-b)
Print the result.

Program:

import java.util.Scanner;
class Main
{
    public static void main(String[] args)
    {
        //create object of scanner class.
        Scanner sc=new Scanner(System.in);
        System.out.print("a= ");
        //Take the first input from the user.
        int a= sc.nextInt();
        System.out.print("b= ");
        //Take the second input from the user.
        int b= sc.nextInt();
        System.out.print("c= ");
        //Take the first input from the user.
        int c= sc.nextInt();
        //declare another integer variable and assigned the formulated value to it.
        int d=(a-b)*(b-c)*(a-c);
        System.out.println("a2(b-c)+b2(c-a)+c2(a-b)= "+d);
    }
}

Output:

a= 30
b= 40
c= 50
a2(b-c)+b2(c-a)+c2(a-b)= -2000

Method-3: Java Program to Compute a2(b-c)+b2(c-a)+c2(a-b) where Value of a, b, and c are Given By Using User Defined Method

Approach:

Declare three integer variables say a, b, and c.
Take the value of a, b, and c as user input by using Scanner class.
Then call a user defined method say computeValue() and pass a, b, and c as parameter.
Then inside method by using the formula compute a²(b-c)+b²(c-a)+c²(a-b)
Print the result.

Program:

import java.util.Scanner;
class Main
{
    public static void main(String[] args)
    {
        //create object of scanner class.
        Scanner sc=new Scanner(System.in);
        System.out.print("a= ");
        //Take the first input from the user.
        int a= sc.nextInt();
        System.out.print("b= ");
        //Take the second input from the user.
        int b= sc.nextInt();
        System.out.print("c= ");
        //Take the first input from the user.
        int c= sc.nextInt();
        //call the function
        computeValue(a,b,c);
    }
    
    //define the method
    public static void computeValue(int a, int b,int c)
    {
        //declare another integer variable and assigned the formulated value to it.
        int d=(a-b)*(b-c)*(a-c);
        System.out.println("a2(b-c)+b2(c-a)+c2(a-b)= "+d);
    }
}

Output:

a= 100
b= 30
c= 56
a2(b-c)+b2(c-a)+c2(a-b)= -80080

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