Python Program to Print Square Number Pattern

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Given the number of rows and a number, the task is to print a square number pattern in C, C++, and Python.

Examples:

Example1:

Input:

given number of sides = 5
given element of square =3

Output:

3 3 3 3 3 
3 3 3 3 3 
3 3 3 3 3 
3 3 3 3 3 
3 3 3 3 3

Example2:

Input:

given number of sides = 7
given element of square =9

Output:

9 9 9 9 9 9 9 
9 9 9 9 9 9 9 
9 9 9 9 9 9 9 
9 9 9 9 9 9 9 
9 9 9 9 9 9 9 
9 9 9 9 9 9 9 
9 9 9 9 9 9 9

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Program to Print Square Number Pattern in C, C++, and Python

Below are the ways to print square number pattern in C, C++, and Python.

• Using For loop (Element is of static input)
• Using For loop (Element is of User input)

Method #1: Using For loop (Element is of static input)

Approach:

• Give the number of sides of the square as static input and store it in a variable.
• Using Nested For loops print the square pattern.
• The Exit of the Program.

1) Python Implementation

Below is the implementation:

# Give the number of sides of the square as static input and store it in a variable.
sidesnum = 10
# Using Nested For loops print the square pattern.
for m in range(sidesnum):
    for n in range(sidesnum):
        print('1', end=' ')
    print()

Output:

1 1 1 1 1 1 1 1 1 1 
1 1 1 1 1 1 1 1 1 1 
1 1 1 1 1 1 1 1 1 1 
1 1 1 1 1 1 1 1 1 1 
1 1 1 1 1 1 1 1 1 1 
1 1 1 1 1 1 1 1 1 1 
1 1 1 1 1 1 1 1 1 1 
1 1 1 1 1 1 1 1 1 1 
1 1 1 1 1 1 1 1 1 1 
1 1 1 1 1 1 1 1 1 1

2) C++ Implementation

Below is the implementation:

#include <iostream>
using namespace std;

int main(void)
{
    // Give the number of sides of the square as static
    // input
    // and store it in a variable.
    int sidesnum = 7;
    // Using Nested For loops print the square pattern.
    for (int m = 1; m <= sidesnum; m++) {
        for (int n = 1; n <= sidesnum; n++) {
            cout << "1 ";
        }
        cout << endl;
    }

    return 0;
}

Output:

1 1 1 1 1 1 1 
1 1 1 1 1 1 1 
1 1 1 1 1 1 1 
1 1 1 1 1 1 1 
1 1 1 1 1 1 1 
1 1 1 1 1 1 1 
1 1 1 1 1 1 1

3) C Implementation

Below is the implementation:

#include<stdio.h>
 
int main()
{
    // Give the number of sides of the square as static input
    // and store it in a variable.
    int sidesnum = 7, m, n;
   // Using Nested For loops print the square pattern.
    for(m = 0; m < sidesnum; m++)
    {
    	for(n = 0; n < sidesnum; n++)
        {
           	printf("1 ");
        }
        printf("\n");
    }
    return 0;
}

Output:

1 1 1 1 1 1 1 
1 1 1 1 1 1 1 
1 1 1 1 1 1 1 
1 1 1 1 1 1 1 
1 1 1 1 1 1 1 
1 1 1 1 1 1 1 
1 1 1 1 1 1 1 

Method #2: Using For loop (Element is of User input)

Approach:

• Give the number of sides of the square as user input and store it in a variable.
• Give the Element as user input and store it in another variable.
• Using Nested For loops print the square pattern.
• The Exit of the Program.

1) Python Implementation

• Give the number of sides of the square as user input using int(input()) and store it in a variable.
• Give the Element as user input using int(input()) and store it in another variable.

Below is the implementation:

# Give the number of sides of the square as user input using int(input()) and store it in a variable.
# Give the Element as user input using int(input()) and store it in another variable.
sidesnum = int(input('Enter some random number of sides = '))
eleme = int(input('Enter some random element = '))
# Using Nested For loops print the square pattern.
for m in range(sidesnum):
    for n in range(sidesnum):
        print(eleme, end=' ')
    print()

Output:

Enter some random number of sides = 11
Enter some random element = 23
23 23 23 23 23 23 23 23 23 23 23 
23 23 23 23 23 23 23 23 23 23 23 
23 23 23 23 23 23 23 23 23 23 23 
23 23 23 23 23 23 23 23 23 23 23 
23 23 23 23 23 23 23 23 23 23 23 
23 23 23 23 23 23 23 23 23 23 23 
23 23 23 23 23 23 23 23 23 23 23 
23 23 23 23 23 23 23 23 23 23 23 
23 23 23 23 23 23 23 23 23 23 23 
23 23 23 23 23 23 23 23 23 23 23 
23 23 23 23 23 23 23 23 23 23 23

2) C++Implementation

• Give the number of sides of the square as user input using cin and store it in a variable.
• Give the Element as user input using cin and store it in another variable.

Below is the implementation:

#include <iostream>
using namespace std;

int main(void)
{
    int sidesnum, eleme;
    // Give the number of sides of the square as user input
    // using cin and
    // store it in a variable.
    cin >> sidesnum;
    // Give the Element as user input using cin and store it
    // in another variable.
    cin >> eleme;

    // Using Nested For loops print the square pattern.
    for (int m = 1; m <= sidesnum; m++) {
        for (int n = 1; n <= sidesnum; n++) {
            cout << eleme << " ";
        }
        cout << endl;
    }

    return 0;
}

3) C Implementation

• Give the number of sides of the square as user input using scanf and store it in a variable.
• Give the Element as user input using scanf and store it in another variable.

Below is the implementation:

#include<stdio.h>
 
int main()
{  int sidesnum, eleme;
    // Give the number of sides of the square as user input
    // using cin and
    // store it in a variable.
    scanf("%d",&sidesnum);
    // Give the Element as user input using cin and store it
    // in another variable.
   scanf("%d",&eleme);
    // Using Nested For loops print the square pattern.
    for (int m = 1; m <= sidesnum; m++) {
        for (int n = 1; n <= sidesnum; n++) {
            printf("%d ",eleme);
        }
        printf("\n");
    }

}

Output:

22
5
5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 
5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 
5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 
5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 
5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 
5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 
5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 
5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 
5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 
5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 
5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 
5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 
5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 
5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 
5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 
5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 
5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 
5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 
5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 
5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 
5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 
5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5

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