# Number pattern programs in python – Python Program to Print Reverse Number Pattern

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Given the number of rows, the task is to print Reverse Number Pattern in C, C++, and Python.

Examples:

Example1:

Input:

Given number of rows = 7

Output:

7 6 5 4 3 2 1
6 5 4 3 2 1
5 4 3 2 1
4 3 2 1
3 2 1
2 1
1

Example2:

Input:

Given number of rows = 10

Output:

10 9 8 7 6 5 4 3 2 1
9 8 7 6 5 4 3 2 1
8 7 6 5 4 3 2 1
7 6 5 4 3 2 1
6 5 4 3 2 1
5 4 3 2 1
4 3 2 1
3 2 1
2 1
1

## Program to Print Reverse Number Pattern in C, C++, and Python

### Method #1: Using For Loop (Static Input)

Approach:

• Give the number of rows as static input and store it in a variable.
• Loop from 0 to the number of rows using For loop.
• Loop from the number of rows – iterator value of the first parent For loop to 0 in decreasing order using another For loop(Nested For loop).
• Print the iterator value of the inner for loop.
• Print the Newline character after the end of the inner loop.
• The Exit of the Program.

1) Python Implementation

Below is the implementation:

# Give the number of rows as static input and store it in a variable.
numbrrows = 7
# Loop from 0 to the number of rows using For loop.
for m in range(0, numbrrows+1):
# Loop from the number of rows - iterator value of the first parent For loop to 0
# in decreasing order using another For loop(Nested For loop).
for n in range(numbrrows - m, 0, -1):
# Print the iterator value of the inner for loop.
print(n, end=' ')
# Print the Newline character after the end of the inner loop.
print()


Output:

7 6 5 4 3 2 1
6 5 4 3 2 1
5 4 3 2 1
4 3 2 1
3 2 1
2 1
1

2) C++ Implementation

Below is the implementation:

#include <iostream>
using namespace std;

int main()
{

// Give the number of rows as static input and store it
// in a variable.
int numbrrows=10;
// Loop from 0 to the number of rows using For loop.
for (int m = 0; m <= numbrrows; m++) {
// Loop from the number of rows - iterator value of
// the first parent For loop to 0 in decreasing
// order using another For loop(Nested For loop).
for (int n = numbrrows - m; n > 0; n--) {
// Print the iterator value of the inner for
// loop.
cout << n << " ";
}
// Print the Newline character after the end of the
// inner loop.
cout << endl;
}
return 0;
}

Output:

10 9 8 7 6 5 4 3 2 1
9 8 7 6 5 4 3 2 1
8 7 6 5 4 3 2 1
7 6 5 4 3 2 1
6 5 4 3 2 1
5 4 3 2 1
4 3 2 1
3 2 1
2 1
1

3) C Implementation

Below is the implementation:

#include <stdio.h>

int main()
{

// Give the number of rows as static input and store it
// in a variable.
int numbrrows = 10;
// Loop from 0 to the number of rows using For loop.
for (int m = 0; m <= numbrrows; m++) {
// Loop from the number of rows - iterator value of
// the first parent For loop to 0 in decreasing
// order using another For loop(Nested For loop).
for (int n = numbrrows - m; n > 0; n--) {
// Print the iterator value of the inner for
// loop.
printf("%d ", n);
}
// Print the Newline character after the end of the
// inner loop.
printf("\n");
}
return 0;
}

Output:

10
10 9 8 7 6 5 4 3 2 1
9 8 7 6 5 4 3 2 1
8 7 6 5 4 3 2 1
7 6 5 4 3 2 1
6 5 4 3 2 1
5 4 3 2 1
4 3 2 1
3 2 1
2 1
1

### Method #2: Using For Loop (User Input)

1) Python Implementation

Give the number of rows as user input using int(input()) and store it in a variable.

Below is the implementation:

# Give the number of rows as user input using int(input()) and store it in a variable.
numbrrows = int(input('Enter some random number of rows = '))
# Loop from 0 to the number of rows using For loop.
for m in range(0, numbrrows+1):
# Loop from the number of rows - iterator value of the first parent For loop to 0
# in decreasing order using another For loop(Nested For loop).
for n in range(numbrrows - m, 0, -1):
# Print the iterator value of the inner for loop.
print(n, end=' ')
# Print the Newline character after the end of the inner loop.
print()


Output:

Enter some random number of rows = 11
11 10 9 8 7 6 5 4 3 2 1
10 9 8 7 6 5 4 3 2 1
9 8 7 6 5 4 3 2 1
8 7 6 5 4 3 2 1
7 6 5 4 3 2 1
6 5 4 3 2 1
5 4 3 2 1
4 3 2 1
3 2 1
2 1
1

2) C++ Implementation

Give the number of rows as user input using cin and store it in a variable.

Below is the implementation:

#include <iostream>
using namespace std;

int main()
{

// Give the number of rows as user input using
// int(input()) and store it in a variable.
int numbrrows;
cin >> numbrrows;
// Loop from 0 to the number of rows using For loop.
for (int m = 0; m <= numbrrows; m++) {
// Loop from the number of rows - iterator value of
// the first parent For loop to 0 in decreasing
// order using another For loop(Nested For loop).
for (int n = numbrrows - m; n > 0; n--) {
// Print the iterator value of the inner for
// loop.
cout << n << " ";
}
// Print the Newline character after the end of the
// inner loop.
cout << endl;
}

return 0;
}

Output:

10
10 9 8 7 6 5 4 3 2 1
9 8 7 6 5 4 3 2 1
8 7 6 5 4 3 2 1
7 6 5 4 3 2 1
6 5 4 3 2 1
5 4 3 2 1
4 3 2 1
3 2 1
2 1
1

3) C Implementation

Give the number of rows as user input using scanf and store it in a variable.

Below is the implementation:

#include <stdio.h>

int main()
{

// Give the number of rows as user input using scanf and
// store it in a variable.
int numbrrows;
scanf("%d", &numbrrows);
// Loop from 0 to the number of rows using For loop.
for (int m = 0; m <= numbrrows; m++) {
// Loop from the number of rows - iterator value of
// the first parent For loop to 0 in decreasing
// order using another For loop(Nested For loop).
for (int n = numbrrows - m; n > 0; n--) {
// Print the iterator value of the inner for
// loop.
printf("%d ", n);
}
// Print the Newline character after the end of the
// inner loop.
printf("\n");
}
return 0;
}

Output:

10
10 9 8 7 6 5 4 3 2 1
9 8 7 6 5 4 3 2 1
8 7 6 5 4 3 2 1
7 6 5 4 3 2 1
6 5 4 3 2 1
5 4 3 2 1
4 3 2 1
3 2 1
2 1
1

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