Number pattern programs in python – Python Program to Print Reverse Number Pattern

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Given the number of rows, the task is to print Reverse Number Pattern in C, C++, and Python.

Examples:

Example1:

Input:

Given number of rows = 7

Output:

7 6 5 4 3 2 1 
6 5 4 3 2 1 
5 4 3 2 1 
4 3 2 1 
3 2 1 
2 1 
1

Example2:

Input:

Given number of rows = 10

Output:

10 9 8 7 6 5 4 3 2 1 
9 8 7 6 5 4 3 2 1 
8 7 6 5 4 3 2 1 
7 6 5 4 3 2 1 
6 5 4 3 2 1 
5 4 3 2 1 
4 3 2 1 
3 2 1 
2 1 
1

Program to Print Reverse Number Pattern in C, C++, and Python

Method #1: Using For Loop (Static Input)

Approach:

  • Give the number of rows as static input and store it in a variable.
  • Loop from 0 to the number of rows using For loop.
  • Loop from the number of rows – iterator value of the first parent For loop to 0 in decreasing order using another For loop(Nested For loop).
  • Print the iterator value of the inner for loop.
  • Print the Newline character after the end of the inner loop.
  • The Exit of the Program.

1) Python Implementation

Below is the implementation:

# Give the number of rows as static input and store it in a variable.
numbrrows = 7
# Loop from 0 to the number of rows using For loop.
for m in range(0, numbrrows+1):
    # Loop from the number of rows - iterator value of the first parent For loop to 0
    # in decreasing order using another For loop(Nested For loop).
    for n in range(numbrrows - m, 0, -1):
        # Print the iterator value of the inner for loop.
        print(n, end=' ')
    # Print the Newline character after the end of the inner loop.
    print()

Output:

7 6 5 4 3 2 1 
6 5 4 3 2 1 
5 4 3 2 1 
4 3 2 1 
3 2 1 
2 1 
1

2) C++ Implementation

Below is the implementation:

#include <iostream>
using namespace std;

int main()
{

    // Give the number of rows as static input and store it
    // in a variable.
    int numbrrows=10;
    // Loop from 0 to the number of rows using For loop.
    for (int m = 0; m <= numbrrows; m++) {
        // Loop from the number of rows - iterator value of
        // the first parent For loop to 0 in decreasing
        // order using another For loop(Nested For loop).
        for (int n = numbrrows - m; n > 0; n--) {
            // Print the iterator value of the inner for
            // loop.
            cout << n << " ";
        }
        // Print the Newline character after the end of the
        // inner loop.
        cout << endl;
    }
    return 0;
}

Output:

10 9 8 7 6 5 4 3 2 1 
9 8 7 6 5 4 3 2 1 
8 7 6 5 4 3 2 1 
7 6 5 4 3 2 1 
6 5 4 3 2 1 
5 4 3 2 1 
4 3 2 1 
3 2 1 
2 1 
1

3) C Implementation

Below is the implementation:

#include <stdio.h>

int main()
{

    // Give the number of rows as static input and store it
    // in a variable.
    int numbrrows = 10;
    // Loop from 0 to the number of rows using For loop.
    for (int m = 0; m <= numbrrows; m++) {
        // Loop from the number of rows - iterator value of
        // the first parent For loop to 0 in decreasing
        // order using another For loop(Nested For loop).
        for (int n = numbrrows - m; n > 0; n--) {
            // Print the iterator value of the inner for
            // loop.
            printf("%d ", n);
        }
        // Print the Newline character after the end of the
        // inner loop.
        printf("\n");
    }
    return 0;
}

Output:

10
10 9 8 7 6 5 4 3 2 1 
9 8 7 6 5 4 3 2 1 
8 7 6 5 4 3 2 1 
7 6 5 4 3 2 1 
6 5 4 3 2 1 
5 4 3 2 1 
4 3 2 1 
3 2 1 
2 1 
1

Method #2: Using For Loop (User Input)

1) Python Implementation

Give the number of rows as user input using int(input()) and store it in a variable.

Below is the implementation:

# Give the number of rows as user input using int(input()) and store it in a variable.
numbrrows = int(input('Enter some random number of rows = '))
# Loop from 0 to the number of rows using For loop.
for m in range(0, numbrrows+1):
    # Loop from the number of rows - iterator value of the first parent For loop to 0
    # in decreasing order using another For loop(Nested For loop).
    for n in range(numbrrows - m, 0, -1):
        # Print the iterator value of the inner for loop.
        print(n, end=' ')
    # Print the Newline character after the end of the inner loop.
    print()

Output:

Enter some random number of rows = 11
11 10 9 8 7 6 5 4 3 2 1 
10 9 8 7 6 5 4 3 2 1 
9 8 7 6 5 4 3 2 1 
8 7 6 5 4 3 2 1 
7 6 5 4 3 2 1 
6 5 4 3 2 1 
5 4 3 2 1 
4 3 2 1 
3 2 1 
2 1 
1

2) C++ Implementation

Give the number of rows as user input using cin and store it in a variable.

Below is the implementation:

#include <iostream>
using namespace std;

int main()
{

    // Give the number of rows as user input using
    // int(input()) and store it in a variable.
    int numbrrows;
    cin >> numbrrows;
    // Loop from 0 to the number of rows using For loop.
    for (int m = 0; m <= numbrrows; m++) {
        // Loop from the number of rows - iterator value of
        // the first parent For loop to 0 in decreasing
        // order using another For loop(Nested For loop).
        for (int n = numbrrows - m; n > 0; n--) {
            // Print the iterator value of the inner for
            // loop.
            cout << n << " ";
        }
        // Print the Newline character after the end of the
        // inner loop.
        cout << endl;
    }

    return 0;
}

Output:

10
10 9 8 7 6 5 4 3 2 1 
9 8 7 6 5 4 3 2 1 
8 7 6 5 4 3 2 1 
7 6 5 4 3 2 1 
6 5 4 3 2 1 
5 4 3 2 1 
4 3 2 1 
3 2 1 
2 1 
1

3) C Implementation

Give the number of rows as user input using scanf and store it in a variable.

Below is the implementation:

#include <stdio.h>

int main()
{

    // Give the number of rows as user input using scanf and
    // store it in a variable.
    int numbrrows;
    scanf("%d", &numbrrows);
    // Loop from 0 to the number of rows using For loop.
    for (int m = 0; m <= numbrrows; m++) {
        // Loop from the number of rows - iterator value of
        // the first parent For loop to 0 in decreasing
        // order using another For loop(Nested For loop).
        for (int n = numbrrows - m; n > 0; n--) {
            // Print the iterator value of the inner for
            // loop.
            printf("%d ", n);
        }
        // Print the Newline character after the end of the
        // inner loop.
        printf("\n");
    }
    return 0;
}

Output:

10
10 9 8 7 6 5 4 3 2 1 
9 8 7 6 5 4 3 2 1 
8 7 6 5 4 3 2 1 
7 6 5 4 3 2 1 
6 5 4 3 2 1 
5 4 3 2 1 
4 3 2 1 
3 2 1 
2 1 
1

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