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Given the number of rows, the task is to print Number Reduction Pattern in C, C++, and Python
Examples:
Example1:
Input:
Given number of rows = 4
Output:
1 2 3 4 2 3 4 3 4 4
Example2:
Input:
Given number of rows = 14
Output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 2 3 4 5 6 7 8 9 10 11 12 13 14 3 4 5 6 7 8 9 10 11 12 13 14 4 5 6 7 8 9 10 11 12 13 14 5 6 7 8 9 10 11 12 13 14 6 7 8 9 10 11 12 13 14 7 8 9 10 11 12 13 14 8 9 10 11 12 13 14 9 10 11 12 13 14 10 11 12 13 14 11 12 13 14 12 13 14 13 14 14
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Program to Print Number Reduction Pattern in C, C++, and Python
Below are the ways to print Number Reduction Pattern in C, C++, and Python
Method #1: Using For Loop (Static Input)
Approach:
- Give the number of rows as static input and store it in a variable.
- Loop from 0 to the number of rows using For loop.
- Loop from iterator value of the parent For loop +1 to the number of rows using another for loop(Nested For loop).
- Print the iterator value of the inner for loop.
- Print the Newline character after the end of the inner loop.
- The Exit of the Program.
1) Python Implementation
Below is the implementation:
# Give the number of rows as static input and store it in a variable.
numbrrows = 9
# Loop from 0 to the number of rows using For loop.
for m in range(0, numbrrows+1):
# Loop from iterator value of the parent For loop +1 to
# the number of rows using another for loop(Nested For loop).
for n in range(m + 1, numbrrows+1):
# Print the iterator value of the inner for loop.
print(n, end=' ')
# Print the Newline character after the end of the inner loop.
print()
Output:
1 2 3 4 5 6 7 8 9 2 3 4 5 6 7 8 9 3 4 5 6 7 8 9 4 5 6 7 8 9 5 6 7 8 9 6 7 8 9 7 8 9 8 9 9
2) C++ Implementation
Below is the implementation:
#include <iostream>
using namespace std;
int main()
{
// Give the number of rows as static input and store it
// in a variable.
int numbrrows = 10;
// Loop from 0 to the number of rows using For loop.
for (int m = 0; m <= numbrrows; m++) {
/* Loop from iterator value of the parent For loop+1
to the number of rows using another for
loop(Nested For loop).*/
for (int n = m + 1; n <= numbrrows; n++) {
// Print the iterator value of the inner for
// loop.
cout << n << " ";
}
// Print the Newline character after the end of the
// inner loop.
cout << endl;
}
return 0;
}
Output:
1 2 3 4 5 6 7 8 9 10 2 3 4 5 6 7 8 9 10 3 4 5 6 7 8 9 10 4 5 6 7 8 9 10 5 6 7 8 9 10 6 7 8 9 10 7 8 9 10 8 9 10 9 10 10
3) C Implementation
Below is the implementation:
#include <stdio.h>
int main()
{
// Give the number of rows as static input and store it
// in a variable.
int numbrrows = 14;
// Loop from 0 to the number of rows using For loop.
for (int m = 0; m <= numbrrows; m++) {
/* Loop from iterator value of the parent For loop+1
to the number of rows using another for
loop(Nested For loop).*/
for (int n = m + 1; n <= numbrrows; n++) {
// Print the iterator value of the inner for
// loop.
printf("%d ", n);
}
// Print the Newline character after the end of the
// inner loop.
printf("\n");
}
return 0;
}
Output:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 2 3 4 5 6 7 8 9 10 11 12 13 14 3 4 5 6 7 8 9 10 11 12 13 14 4 5 6 7 8 9 10 11 12 13 14 5 6 7 8 9 10 11 12 13 14 6 7 8 9 10 11 12 13 14 7 8 9 10 11 12 13 14 8 9 10 11 12 13 14 9 10 11 12 13 14 10 11 12 13 14 11 12 13 14 12 13 14 13 14 14
Method #2: Using For Loop (User Input)
Approach:
- Give the number of rows as user input and store it in a variable.
- Loop from 0 to the number of rows using For loop.
- Loop from iterator value of the parent For loop +1 to the number of rows using another for loop(Nested For loop).
- Print the iterator value of the inner for loop.
- Print the Newline character after the end of the inner loop.
- The Exit of the Program.
1) Python Implementation
Give the number of rows as user input using int(input()) and store it in a variable.
Below is the implementation:
# Give the number of rows as user input using int(input()) and store it in a variable.
numbrrows = int(input('Enter some random number of rows = '))
# Loop from 0 to the number of rows using For loop.
for m in range(0, numbrrows+1):
# Loop from iterator value of the parent For loop +1 to
# the number of rows using another for loop(Nested For loop).
for n in range(m + 1, numbrrows+1):
# Print the iterator value of the inner for loop.
print(n, end=' ')
# Print the Newline character after the end of the inner loop.
print()
Output:
Enter some random number of rows = 6 1 2 3 4 5 6 2 3 4 5 6 3 4 5 6 4 5 6 5 6 6
2) C++ Implementation
Give the number of rows as user input using cin and store it in a variable.
Below is the implementation:
#include <iostream>
using namespace std;
int main()
{
// Give the number of rows as user input using
// int(input()) and store it in a variable.
int numbrrows;
cin >> numbrrows;
// Loop from 0 to the number of rows using For loop.
for (int m = 0; m <= numbrrows; m++) {
/* Loop from iterator value of the parent For loop+1
to the number of rows using another for
loop(Nested For loop).*/
for (int n = m + 1; n <= numbrrows; n++) {
// Print the iterator value of the inner for
// loop.
cout << n << " ";
}
// Print the Newline character after the end of the
// inner loop.
cout << endl;
}
return 0;
}
Output:
4 1 2 3 4 2 3 4 3 4 4
3) C Implementation
Give the number of rows as user input using scanf and store it in a variable.
Below is the implementation:
#include <math.h>
#include <stdio.h>
int main()
{
// Give the number of rows as user input using scanf and
// store it in a variable.
int numbrrows;
scanf("%d", &numbrrows);
// Loop from 0 to the number of rows using For loop.
for (int m = 0; m <= numbrrows; m++) {
/* Loop from iterator value of the parent For loop+1
to the number of rows using another for
loop(Nested For loop).*/
for (int n = m + 1; n <= numbrrows; n++) {
// Print the iterator value of the inner for
// loop.
printf("%d ", n);
}
// Print the Newline character after the end of the
// inner loop.
printf("\n");
}
return 0;
}
Output:
4 1 2 3 4 2 3 4 3 4 4
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