Program to Count the Number of Alphabets in a String

Python Program to Count the Number of Alphabets in a String

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In the previous article, we have discussed Python Program to Count the Number of Null elements in a List.

Given a string, the task is to count the Number of Alphabets in a given String.

isalpha() Method:

The isalpha() method is a built-in method for string-type objects. If all of the characters are alphabets from a to z, the isalpha() method returns true otherwise, it returns False.

Examples:

Example1:

Input:

Given String = hello btechgeeks

Output:

The Number of Characters in a given string { hello btechgeeks } =  15

Example 2:

Input:

Given String = good morning btechgeeks

Output:

The Number of Characters in a given string { good morning btechgeeks } =  21

Program to Count the Number of Alphabets in a String

Below are the ways to Count the Number of Alphabets in a String.

Method #1: Using isalpha() Method (Static input)

Approach:

  • Give the String as static input and store it in a variable.
  • Take a variable to say ‘count’ and initialize its value with ‘0’
  • Loop from 0 to the length of the above-given String using For Loop.
  • Inside the loop, check whether if the value of the iterator is an alphabet or using the built-in isalpha() method inside the if conditional statement.
  • If the given condition is true, then increment the above-initialized count value by ‘1’.
  • Print the number of Alphabets in a given string by printing the above count value.
  • The Exit of the program.

Below is the implementation:

# Give the String as static input and store it in a variable.
gvn_str = "hello btechgeeks"
# Take a variable say 'count' and initialize it's value with '0'
count_no = 0
# Loop from 0 to the length of the above given String using For Loop.
for itrtor in gvn_str:
    # Inside the loop, check whether  if the value of iterator is alphabet or
    # using built-in isalpha() method inside the if conditional statement.
    if(itrtor.isalpha()):
     # If the given condition is true ,then increment the above initialized count value by '1'.
    	count_no = count_no+1
# Print the number of Alphabets in a given string by printing the above count value.
print(
    "The Number of Characters in a given string {", gvn_str, "} = ", count_no)

Output:

The Number of Characters in a given string { hello btechgeeks } =  15

Method #2: Using isalpha() Method (User input)

Approach:

  • Give the String as user input using the input() function and store it in the variable.
  • Take a variable to say ‘count’ and initialize its value with ‘0’
  • Loop from 0 to the length of the above-given String using For Loop.
  • Inside the loop, check whether if the value of the iterator is an alphabet or using the built-in isalpha() method inside the if conditional statement.
  • If the given condition is true, then increment the above-initialized count value by ‘1’.
  • Print the number of Alphabets in a given string by printing the above count value.
  • The Exit of the program.

Below is the implementation:

# Give the String as user input using the input()function and store it in the variable.
gvn_str = input("Enter some random String = ")
# Take a variable say 'count' and initialize it's value with '0'
count_no = 0
# Loop from 0 to the length of the above given String using For Loop.
for itrtor in gvn_str:
    # Inside the loop, check whether  if the value of iterator is alphabet or
    # using built-in isalpha() method inside the if conditional statement.
    if(itrtor.isalpha()):
     # If the given condition is true ,then increment the above initialized count value by '1'.
    	count_no = count_no+1
# Print the number of Alphabets in a given string by printing the above count value.
print(
    "The Number of Characters in a given string {", gvn_str, "} = ", count_no)

Output:

Enter some random String = good morning btechgeeks
The Number of Characters in a given string { good morning btechgeeks } = 21

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