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Given the sides of the square, the task is to print the hollow Square star pattern with diagonals in C, C++, and Python.
Examples:
Example1:
Input:
given number of sides of square =10
Output:
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
Example2:
Input:
given number of sides of square =10 given character to print =$
Output:
$ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $
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Program to Print Hollow Square Star Pattern with Diagonals in C, C++, and Python
Below are the ways to print the hollow square star with Diagonals pattern in C, C++, and Python.
Method #1: Using For loop (Star Character)
Approach:
- Give the side of the square as static input and store it in a variable.
- Loop till the side length of the square using For loop.
- Loop till the side length of the square using another nested For loop.
- We use the If Else statement to check If the side length is 0 or maximum – 1. (For the Outer Boundary of the square)
- We can say it is diagonal if a row equals a column, or a row equals N-i+1 (where i is the current row number).
- We merge these two conditions using if and or operator.
- We have or operator in Python,|| operator in C, C++, and Java
- If it is true then print * else print space.
- The Exit of the Program.
1) Python Implementation
Below is the implementation:
# Give the side of the square as static input and store it in a variable.
squareside = 10
# Loop till the side length of the square using For loop.
for m in range(squareside):
# Loop till the side length of the square using another nested For loop.
for n in range(squareside):
# We use the If Else statement to check If the side length is 0 or maximum – 1. (For the Outer Boundary of the square)
# We can say it is diagonal if a row equals a column, or a row equals N-i+1 (where i is the current row number).
# We merge these two conditions using if and or operator.
# We have or operator in Python,|| operator in C, C++, and Java
# If it is true then print * else print space.
if(m == 0 or m == squareside - 1 or n == 0 or n == squareside - 1 or m == n or n == (squareside - 1 - m)):
print('*', end=' ')
else:
print(' ', end=' ')
print()
Output:
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
2) C++Implementation
Below is the implementation:
#include <iostream>
using namespace std;
int main()
{
// Give the side of the square as static input and store
// it in a variable.
int squareside = 10;
// Loop till the side length of the square using For
// loop.
for (int m = 0; m < squareside; m++) {
// Loop till the side length of the square using
// another nested For loop.
for (int n = 0; n < squareside; n++) {
// We use the If Else statement to check If the
// side length is 0 or maximum – 1.
if (m == 0 || m == squareside - 1 || n == 0
|| n == squareside - 1)
cout << "* ";
else
cout << " ";
}
cout << endl;
}
return 0;
}
Output:
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
3) C Implementation
Below is the implementation:
#include <stdio.h>
int main()
{
// Give the side of the square as static input and store
// it in a variable.
int squareside = 10;
// Loop till the side length of the square using For
// loop.
for (int m = 0; m < squareside; m++) {
// Loop till the side length of the square using
// another nested For loop.
for (int n = 0; n < squareside; n++) {
/*We use the If Else statement to check If the
side length is 0 or maximum – 1. (For the
Outer Boundary of the square) We can say it
is diagonal if a row equals a column, or a
row equals N-i+1 (where i is the current row
number). We merge these two conditions using
if and or operator. We have or operator in
Python,|| operator in C,
C++, and Java If it is true then print *
else print space.*/
if (m == 0 || m == squareside - 1 || n == 0
|| n == squareside - 1 || m == n
|| n == (squareside - 1 - m))
printf("* ");
else
printf(" ");
}
printf("\n");
}
}
Output:
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
Method #2: Using For Loop (User Character)
Approach:
- Give the side of the square as user input and store it in a variable.
- Scan the character to print as user input and store it in a variable.
- Loop till the side length of the square using For loop.
- Loop till the side length of the square using another nested For loop.
- We use the If Else statement to check If the side length is 0 or maximum – 1.
- We can say it is diagonal if a row equals a column, or a row equals N-i+1 (where i is the current row number).
- We merge these two conditions using if and or operator.
- We have or operator in Python,|| operator in C, C++, and Java
- If it is true then print given character else print space.
- The Exit of the Program.
1) Python Implementation
- Give the number of sides of the square as user input using int(input()) and store it in a variable.
- Give the Character as user input using input() and store it in another variable.
Below is the implementation:
# Give the side of the square as user input and store it in a variable.
squareside = int(input('Enter some random number of sides of square = '))
# Scan the character to print as user input and store it in a variable.
characte = input('Enter some random character to print = ')
# Loop till the side length of the square using For loop.
for m in range(squareside):
# Loop till the side length of the square using another nested For loop.
for n in range(squareside):
# We use the If Else statement to check If the side length is 0 or maximum – 1. (For the Outer Boundary of the square)
# We can say it is diagonal if a row equals a column, or a row equals N-i+1 (where i is the current row number).
# We merge these two conditions using if and or operator.
# We have or operator in Python,|| operator in C, C++, and Java
# If it is true then print * else print space.
if(m == 0 or m == squareside - 1 or n == 0 or n == squareside - 1 or m == n or n == (squareside - 1 - m)):
print(characte, end=' ')
else:
print(' ', end=' ')
print()
Output:
Enter some random number of sides of square = 10 Enter some random character to print = $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $
2) C++Implementation
- Give the number of sides of the square as user input using cin and store it in a variable.
- Create a character variable.
- Give the character as user input using cin and store it in another variable.
Below is the implementation:
#include <iostream>
using namespace std;
int main(void)
{
int sidesnum;
char characte;
// Give the number of sides of the square as user input
// using cin and
// store it in a variable.
cout << "Enter some random number of sides of the "
"square = "
<< endl;
cin >> sidesnum;
// Create a character variable.
// Give the character as user input using cin and store
// it in another variable.
cout << "Enter some random character to print = "
<< endl;
cin >> characte;
cout << endl;
// Using Nested For loops print the square pattern.
for (int m = 0; m < sidesnum; m++) {
for (int n = 0; n < sidesnum; n++) {
/*We use the If Else statement to check If the
side length is 0 or maximum – 1. (For the
Outer Boundary of the square) We can say it
is diagonal if a row equals a column, or a
row equals N-i+1 (where i is the current row
number). We merge these two conditions using
if and or operator. We have or operator in
Python,|| operator in C,
C++, and Java If it is true then print *
else print space.*/
if (m == 0 || m == sidesnum - 1 || n == 0
|| n == sidesnum - 1 || m == n
|| n == (sidesnum - 1 - m))
cout << characte << " ";
else
cout << " ";
}
cout << endl;
}
return 0;
}
Output:
Enter some random number of sides of the square = 10 Enter some random character to print = $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $
3) C Implementation
- Give the number of sides of the square as user input using scanf and store it in a variable.
- Create a character variable.
- Give the character as user input using scanf and store it in another variable.
Below is the implementation:
#include <stdio.h>
int main()
{
int sidesnum;
char characte;
// Give the number of sides of the square as user input
// using scanf and
// store it in a variable.
// Create a character variable.
// Give the character as user input using scanf and
// store it in another variable.
// Using Nested For loops print the square pattern.
scanf("%d%c", &sidesnum, &characte);
printf("\n");
for (int m = 0; m < sidesnum; m++) {
for (int n = 0; n < sidesnum; n++) {
/*We use the If Else statement to check If the
side length is 0 or maximum – 1. (For the
Outer Boundary of the square) We can say it
is diagonal if a row equals a column, or a
row equals N-i+1 (where i is the current row
number). We merge these two conditions using
if and or operator. We have or operator in
Python,|| operator in C,
C++, and Java If it is true then print *
else print space.*/
if (m == 0 || m == sidesnum - 1 || n == 0
|| n == sidesnum - 1 || m == n
|| n == (sidesnum - 1 - m))
printf("%c ", characte);
else
printf(" ");
}
printf("\n");
}
}
Output:
10$ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $
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