In the previous article, we have discussed Java Program to Find the Product Between Sums of Two Diagonals of a Matrix
In this article we are going to see how we can write a program to count number of one’s in a binary matrix in JAVA language. A binary matrix is a matrix that has only 0 or 1 as its elements.
Java Program to Count the Numbers of 1’s in a Binary Matrix
A 3*3 Matrix is having 3 rows and 3 columns where this 3*3 represents the dimension of the matrix. Means there are 3*3 i.e. total 9 elements in a 3*3 Matrix.
Let’s understand it in more simpler way.
| A00 A01 A02 | Matrix A = | A10 A11 A12 | | A20 A21 A22 | 3*3
Matrix A
represents a 3*3 matrix.- ‘
A
‘ represents the matrix element - ‘
Aij
‘ represents the matrix element at it’s matrix position/index. - ‘
i
‘ represents the row index - ‘
j
‘ represents the column index - Means
A00=Aij
wherei=0
andj=0
,A01=aij
wherei=0
andj=1
and like this. - Here we have started
row
value from 0 andcolumn
value from 0.
A binary matrix is a matrix that has only 0 or 1 as its elements.
Let’s see different ways to count the Numbers of 1’s in a Binary Matrix.
Method-1: Java Program to Count the Numbers of 1’s in a Binary Matrix By Static Initialization of Array Elements
Approach:
- Initialize and an array of size 3×3, with elements.
- Use two for loops to iterate the rows and columns .
- Inside the for loops count all ones’ using a counter.
- Print the result.
Program:
public class matrix { public static void main(String args[]) { // Initializing the 3X3 matrix i.e. 2D array int arr[][] = {{1,0,0},{0,1,0},{1,1,1}}; int row, col, count = 0; System.out.print("The matrix elements are : "); printMatrix(arr); // Loops to total number of one's in a binary matrix for(row=0;row<3;row++) for(col=0;col<3;col++) { if(arr[row][col]==1) count++; } System.out.println("\nNumber of ones' in the binary matrix are : "+count); } // Method to print the matrix static void printMatrix(int arr[][]) { int row, col; // Loop to print the elements for(row=0;row<3;row++) { // Used for formatting System.out.print("\n"); for(col=0;col<3;col++) { System.out.print(arr[row][col]+" "); } } System.out.print("\n"); } }
Output: The matrix elements are : 1 0 0 0 1 0 1 1 1 Number of ones' in the binary matrix are : 5
Method-2: Java Program to Count the Numbers of 1’s in a Binary Matrix By Dynamic Initialization of Array Elements
Approach:
- Declare one array of size 3×3.
- Ask the user for input of array elements and store them in the array using two for loops.
- Use two for loops to iterate the rows and columns .
- Inside the for loops count all ones’ using a counter.
- Print the result.
Program:
import java.util.Scanner; public class matrix{ public static void main(String args[]) { //Scanner class to take input Scanner scan = new Scanner(System.in); // Initializing the 3X3 matrix i.e. 2D array int arr[][] = new int[3][3]; int row, col ,count = 0; // Taking matrix1 input System.out.println("Enter matrix elements : "); for(row=0;row<3;row++) for(col=0;col<3;col++) arr[row][col] = scan.nextInt(); System.out.print("The matrix elements are:"); printMatrix(arr); // Loops to total number of ones' in a binary matrix for(row=0;row<3;row++) for(col=0;col<3;col++) { if(arr[row][col]==1) count++; } System.out.println("\nNumber of ones' in the binary matrix are : "+count); } // Method to print the matrix static void printMatrix(int arr[][]) { int row, col; // Loop to print the elements for(row=0;row<3;row++) { // Used for formatting System.out.print("\n"); for(col=0;col<3;col++) { System.out.print(arr[row][col]+" "); } } System.out.print("\n"); } }
Output: Enter matrix elements : 1 1 1 1 1 1 1 0 0 The matrix elements are: 1 1 1 1 1 1 1 0 0 Number of ones' in the binary matrix are : 7
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