Java Program to Check Whether a Number is Even or Odd

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Check Whether a Number is Even or Odd

In this article we will see different ways to check whether a number is even or odd in Java. So, before going to the actual concept let’s first understand what is this even number and odd number then we will move to next part.

Even Number :

If a number is divisible by 2 and generates remainder of 0 then that number is called as even number.

For example:

14 is an even number because 14%2 returns remainder 0.
80 is an even number because 80%2 returns remainder 0.

Odd Number :

If a number is  not divisible by 2 and does not generate remainder of 0 then that number is called as odd number.

For example:

33 is an odd number because 33%2 returns remainder 1.
17 is an odd number because 17%2 returns remainder 1.

Different ways to check whether a number is even or odd:

Method-1 : Using modulo(%) operator

By using the modulo operator also we can check a number is even or odd.

Approach:

  • Divide the number by 2 modulo operator.
  • If the remainder is 0 then it is an even number and if the remainder is not equal to 0 then it is odd.

Let’s see the below program to understand how it actually works.

import java.util.*;

class Check
{
    public static void main(String args[])
    {
        // Scanner class object created for input
        Scanner sc=new Scanner(System.in); 
        
        System.out.print("Enter a number: ");
        //Take a number input from user
        int num=sc.nextInt();
        
        //get the remainder using modulo operator
        int rem=num%2;
        // If the remainder is equals to 0 then it is even number
        // else it is odd number
        if(rem==0)
        {
          System.out.println("Even number");
        }
        else
        {
         System.out.println("Odd number");
        }
    }
}
Output :
Enter a number: 90
Even number

//Another case
Enter a number: 9
Odd number

Method-2 : Using division(/) operator

By using the division operator also we can check a number is even or odd.

Approach :

  • Divide the number by division operator.
  • Then Again multiply 2 with quotient.
  • If quotient multiplied with 2 is equal to original number(dividend) then it is even.
  • If quotient multiplied with 2 is not equal to original number(dividend) then it is odd.

For example:

Example-1
Original number(dividend)=44
Then 44/2==22(quotient)
Then 22*2=44(original number)
So, it is even
Example-2
Original number(dividend)=33
Then 33/2==1(quotient)
Then 1*2=2(Not original number)
So, it is odd
import java.util.*;

class Check
{
    public static void main(String args[])
    {
        // Scanner class object created for input
        Scanner sc=new Scanner(System.in); 
        
        System.out.print("Enter a number: ");
        //Take a number input from user
        int num=sc.nextInt();
        
        //using division operartor
        if((num/2) * 2==num)
        {
          System.out.println("Even number");
        }
        else
        {
         System.out.println("Odd number");
        }
    }
}
Output:
Enter a number: 44
Even number

// Another case
Enter a number: 33
Odd number

Method-3 : Using ternary operator

By using the ternary operator also we can check a number is even or odd.

Synatx: variable = Expression1 ? Expression2: Expression3

Let’s see the below program to understand how it actually works.

import java.util.*;

class Check
{
    public static void main(String args[])
    {
        // Scanner class object created for input
        Scanner sc=new Scanner(System.in); 
        
        System.out.print("Enter a number: ");
        //Take a number input from user
        int num=sc.nextInt();
        
        // using ternary operator
        String res=(num%2==0) ? "Even number":"Odd number";
        System.out.println(res);
    }
}
Output:
Enter a number: 44
Even number

// Another case
Enter a number: 33
Odd number

Method-4 : Using Bit wise AND(&) operator

By using the bit wise AND(&) operator also we can check a number is even or odd.

Approach :

  • Perform the bit wise AND operation of the number with 1.
  • If the result is 1 then it is odd.
  • And if the result is 0 then it is even.

Let’s see the below program to understand how it actually works.

import java.util.*;

class Check
{
    public static void main(String args[])
    {
        // Scanner class object created for input
        Scanner sc=new Scanner(System.in); 
        
        System.out.print("Enter a number: ");
        //Take a number input from user
        int num=sc.nextInt();
        
        // performing bit wise AND operation
        if ((num & 1) == 1) 
        {
            System.out.println("Odd number");
        }
        else {
            System.out.println("Even number");
        }
    }
}
Output:
Enter a number: 44
Even number

// Another case
Enter a number: 33
Odd number

Method-5 : Using Bit wise OR(|) operator

By using the bit wise OR(&) operator also we can check a number is even or odd.

Approach :

  • Perform the bit wise OR operation of the number with 1.
  • If the value of the number incremented by 1 then it is even.
  • And if the value remains unchanged then it is odd.

Let’s see the below program to understand how it actually works.

import java.util.*;

class Check
{
    public static void main(String args[])
    {
        // Scanner class object created for input
        Scanner sc=new Scanner(System.in); 
        
        System.out.print("Enter a number: ");
        //Take a number input from user
        int num=sc.nextInt();
        
        // performing bit wise OR operation
        if ((num | 1) > num)  
        {
            System.out.println("Even number");
        }
        else {
            System.out.println("Odd number");
        }
    }
}
Output:
Enter a number: 44
Even number

// Another case
Enter a number: 33
Odd number

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