# Java Program to Find the Largest Among Three Numbers

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## Largest Among Three Numbers in Java

In this article we will see different ways to find the largest among three numbers.

### Method-1 : By using ternary operator

By suing ternary operator we can find the largest number among three numbers.

Synatx of ternary operator-: variable_name = (expression) ? value if true:value if false

Approach:

• Take three numbers input from user.
• Store it in 3 int variables first, second and third.
• Using ternary operator check the largest number among first and second.
• Store the largest among these two in an temporary integer variable temp.
• Now compare temp value with third value using ternary operator.
• Store the largest among these two in an integer variable big.
• big value represent the largest number.

Program:

import java.util.*;

public class Largest
{
public static void main(String[] args)
{
int first, second, third, big, temp;

//Scanner class object created to take input
Scanner sc = new Scanner(System.in);

//Taking input from the user
System.out.println("Enter the first number:");
first = sc.nextInt();
System.out.println("Enter the second number:");
second = sc.nextInt();
System.out.println("Enter the third number:");
third = sc.nextInt();

// compare first number with second number using ternary operator
// Store largest number among them in a temporary variable temp
temp=first>second?first:second;
//Then compare the temp variable with third variable using ternary operator
big=third>temp?third:temp;
//prints the largest number
System.out.println("The largest among three numbers: "+big);
}
}
Output :

Enter the first number:
4
Enter the second number:
2
Enter the third number:
8
The largest among three numbers: 8

### Method-2 : By using if-else statement

By suing if-else statement we can find the largest number among three numbers.

Approach:

• Take three numbers input from user.
• Store it in 3 int variables first, second and third.
• In the first if condition compare first number with other two numbers if it is larger than other two numbers then first number is largest.
• In the second else if condition compare second number with other two numbers if it is larger than other two numbers then second number is largest.
• If no one is bigger then, Otherwise third number is largest.

Program:

import java.util.*;

public class Largest
{
public static void main(String[] args)
{
int first, second, third, big, temp;

//Scanner class object created to take input
Scanner sc = new Scanner(System.in);

//Taking input from the user
System.out.println("Enter the first number:");
first = sc.nextInt();
System.out.println("Enter the second number:");
second = sc.nextInt();
System.out.println("Enter the third number:");
third = sc.nextInt();

//comparing first with second and third value
if(first>=second && first>=third)
System.out.println("The largest among largest numbers: "+first);
//comparing second with first and third value
else if (second>=first && second>=third)
System.out.println("The largest among largest numbers: "+second);
// else third value is largest
else
System.out.println("The largest among largest numbers: "+third);
}
}
Output :

Enter the first number:
7
Enter the second number:
9
Enter the third number:
2
The largest among largest numbers: 9

### Method-2 : By using nested if statement

By suing nested if statement we can find the largest number among three numbers.

Approach:

• Take three numbers input from user.
• Store it in 3 int variables first, second and third.
• In the first if condition comparing first number with second number
• If first number is greater so inner if condition now will be excuted
• Then comparing first number with third number
• If first is greater than third number then first is largest number
• otherwise third is largest number
• If the first if condition fails means second is largest
• So else part will be executed.
• Now if second number is greater than third number then second is largest.
• Other wise third number is largest.

Program:

import java.util.*;

public class Largest
{
public static void main(String[] args)
{
int first, second, third, big, temp;

//Scanner class object created to take input
Scanner sc = new Scanner(System.in);

//Taking input from the user
System.out.println("Enter the first number:");
first = sc.nextInt();
System.out.println("Enter the second number:");
second = sc.nextInt();
System.out.println("Enter the third number:");
third = sc.nextInt();

//comparing first number with second number
if(first >= second)
{
// first number is greater so this condition now will be excuted
// comparing first number with third number
// if first is greater than third number then first is largest number
// otherwise third is largest number
if(first >= third)
System.out.println("The largest among largest numbers: "+first);
else
System.out.println("The largest among largest numbers: "+third);
}
// means first if condition failed so this else will be executed
// means second is largest so first if condition failed
// now if second number is greater than third number then second is largest
// other wise third number is largest
else
{
if(second >= third)
System.out.println("The largest among largest numbers: "+second);
else
System.out.println("The largest among largest numbers: "+third);
}
}
}
Output :

Enter the first number:
9
Enter the second number:
2
Enter the third number:
8
The largest among largest numbers: 9

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