Java Program to Find the Largest Among Three Numbers

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Largest Among Three Numbers in Java

In this article we will see different ways to find the largest among three numbers.

By using ternary operator
By using if-else statement
By using nested if statement

Method-1 : By using ternary operator

By suing ternary operator we can find the largest number among three numbers.

Synatx of ternary operator-: variable_name = (expression) ? value if true:value if false

Approach:

Take three numbers input from user.
Store it in 3 int variables first, second and third.
Using ternary operator check the largest number among first and second.
Store the largest among these two in an temporary integer variable temp.
Now compare temp value with third value using ternary operator.
Store the largest among these two in an integer variable big.
big value represent the largest number.

Program:

import java.util.*;  

public class Largest 
{  
    public static void main(String[] args)   
    {  
        int first, second, third, big, temp; 
        
        //Scanner class object created to take input
        Scanner sc = new Scanner(System.in);
        
        //Taking input from the user  
        System.out.println("Enter the first number:");  
        first = sc.nextInt();  
        System.out.println("Enter the second number:");  
        second = sc.nextInt();  
        System.out.println("Enter the third number:");  
        third = sc.nextInt();  
        
        // compare first number with second number using ternary operator
        // Store largest number among them in a temporary variable temp
        temp=first>second?first:second;  
        //Then compare the temp variable with third variable using ternary operator
        big=third>temp?third:temp;  
        //prints the largest number  
        System.out.println("The largest among three numbers: "+big);  
    }  
}

Output :

Enter the first number:
4
Enter the second number:
2
Enter the third number:
8
The largest among three numbers: 8

Method-2 : By using if-else statement

By suing if-else statement we can find the largest number among three numbers.

Approach:

Take three numbers input from user.
Store it in 3 int variables first, second and third.
In the first if condition compare first number with other two numbers if it is larger than other two numbers then first number is largest.
In the second else if condition compare second number with other two numbers if it is larger than other two numbers then second number is largest.
If no one is bigger then, Otherwise third number is largest.

Program:

import java.util.*;  

public class Largest 
{  
    public static void main(String[] args)   
    {  
        int first, second, third, big, temp; 
        
        //Scanner class object created to take input
        Scanner sc = new Scanner(System.in);
        
        //Taking input from the user  
        System.out.println("Enter the first number:");  
        first = sc.nextInt();  
        System.out.println("Enter the second number:");  
        second = sc.nextInt();  
        System.out.println("Enter the third number:");  
        third = sc.nextInt();  
        
        //comparing first with second and third value
        if(first>=second && first>=third)  
            System.out.println("The largest among largest numbers: "+first);  
        //comparing second with first and third value
        else if (second>=first && second>=third)  
            System.out.println("The largest among largest numbers: "+second);  
        // else third value is largest
        else  
            System.out.println("The largest among largest numbers: "+third);  
    }  
}

Output :

Enter the first number:
7
Enter the second number:
9
Enter the third number:
2
The largest among largest numbers: 9

Method-2 : By using nested if statement

By suing nested if statement we can find the largest number among three numbers.

Approach:

Take three numbers input from user.
Store it in 3 int variables first, second and third.
In the first if condition comparing first number with second number
If first number is greater so inner if condition now will be excuted
Then comparing first number with third number
If first is greater than third number then first is largest number
otherwise third is largest number
If the first if condition fails means second is largest
So else part will be executed.
Now if second number is greater than third number then second is largest.
Other wise third number is largest.

Program:

import java.util.*;  

public class Largest 
{  
    public static void main(String[] args)   
    {  
        int first, second, third, big, temp; 
        
        //Scanner class object created to take input
        Scanner sc = new Scanner(System.in);
        
        //Taking input from the user  
        System.out.println("Enter the first number:");  
        first = sc.nextInt();  
        System.out.println("Enter the second number:");  
        second = sc.nextInt();  
        System.out.println("Enter the third number:");  
        third = sc.nextInt();  
        
        //comparing first number with second number 
        if(first >= second) 
        {
            // first number is greater so this condition now will be excuted
            // comparing first number with third number
            // if first is greater than third number then first is largest number
            // otherwise third is largest number
            if(first >= third)
                System.out.println("The largest among largest numbers: "+first);
            else
                System.out.println("The largest among largest numbers: "+third);
        } 
        // means first if condition failed so this else will be executed
        // means second is largest so first if condition failed
        // now if second number is greater than third number then second is largest
        // other wise third number is largest
        else 
        {
            if(second >= third)
                System.out.println("The largest among largest numbers: "+second);
            else
                System.out.println("The largest among largest numbers: "+third);
        }
    }  
}

Output :

Enter the first number:
9
Enter the second number:
2
Enter the third number:
8
The largest among largest numbers: 9

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