Java Program to Print the Series 1 22 333 4444 55555 … N

In the previous article we have discussed about Java Program to Print the Series 0 2 6 12 20 30 42 … N

In this article we are going to see how to print the series 1 22 333 4444 55555 … N by using Java programming language. How can you write a program to print the following pattern 1 22 333 in java? How do you print this pattern in java 1 22 333 4444 55555 666666 7777777 88888888 999999999? How to write the 1 22 333 pyramid pattern in java? How do you write 1 22 333 4444 pattern in java. Write nested for loops to produce the following output 1 22 333 4444 55555? How to write a program which will produce the following output 1 22 333 4444 55555? And 1 22 333 pattern in c? What is the output of the code Below Print(‘{:,}’.Format(1223334444))? Finally how to print the Print The Following Pattern For The Given N Number Of Rows, Pattern For N = 4 4444 333 22 1?

Java Program to Print the Series 1 22 333 4444 55555 … N

On observing the pattern carefully, we can see

1^st number starts from 1 and in each term it will increment by 1 and n times repeated.

1
22
333
4444
55555
.
nnnnnnn….n

Let’s see different ways to print the series 1 22 333 4444 55555 … N

By Using For Loop
By Using While Loop
By Using User Defined Method

Method-1: Java Program to Print the Series 1 22 333 4444 55555 … N By Using For Loop

Approach:

Create Scanner class object.
Declare an integer variable say ‘n’ which holds the Nth term of the series
Prompt the user to enter a number as value of n.
Use a for loop from i=1 to i<=n where the loop is incremented by 1
Inside the for loop we will again use a for loop from j =1 to j<=i where the loop is incremented by 1
Inside the j loop we will print the result of i which will be repeated j times.
Outside j loop we will Print the series separated by single space “ ”.

Program:

import java.util.*;
public class Main
{
    public static void main(String [] args)
    {
        //creating object of Scanner class 
        Scanner s = new Scanner(System.in);
        //Taking input of number of elements in the series
        System.out.println("Enter the Nth term “N” ");
        int n = s.nextInt();
        //for loop to print the series
        for (int i = 1; i <= n; i++) 
        {
            for(int j = 1; j<=i; j++)
            {
                System.out.print(i);
            }
            System.out.print(" ");
        } 
    }
}

Output:

Enter the Nth term “N” 
5
1 22 333 4444 55555

Method-2: Java Program to Print the Series 1 22 333 4444 55555 … N By Using While Loop

Approach:

Create Scanner class object.
Declare an integer variable say ‘n’ which holds the Nth term of the series
Prompt the user to enter a number as value of n.
Declare and initialize an integer variable i=1
Continue a while loop till i<=n, where i is incremented by 1.
Inside while loop Declare and initialize an integer variable j=1
Continue a while loop till j<=i, where j is incremented by 1.
Inside the j loop we will print the result of i which will be repeated j times.
Outside j loop we will Print the series separated by single space “ ”.

Program:

import java.util.*;
public class Main
{
    public static void main(String [] args)
    {
        //creating object of Scanner class 
        Scanner s = new Scanner(System.in);
        //Taking input of number of elements in the series
        System.out.println("Enter the Nth term “N” ");
        int n = s.nextInt();
        int i=1;
        while(i<=n)
        {
            int j = 1;
            while( j<=i)
            {
                System.out.print(i);
                j++;
            }
            System.out.print(" ");
            i++;
        }      
    }
}

Output:

Enter the Nth term “N” 
6
1 22 333 4444 55555 666666

Method-3: Java Program to Print the Series 1 22 333 4444 55555 … N By Using User Defined Method

Approach:

The same logic as method 1 but this time we are moving the for inside a user-defined method
Create a Scanner class object.
Prompt the user to enter the Nth term “N”
Call a user defined method printSeries() by passing n as parameter.
Inside the method use a for loop to find the series.
Use a for loop from i =1 to i<=n where the loop is incremented by 1
Inside the for loop we will again use another for loop from j = 1 to j<=i where the loop is incremented by 1
Inside the j loop we will print the result of i which will be repeated j times.
Outside j loop we will Print the series separated by single space “ ”.

Program:

import java.util.*;
public class Main
{
    public static void main(String[] args)
    {
        // creating object of scanner class 
        Scanner s = new Scanner(System.in);
        //Taking input of number of elements in the series
        System.out.println("Enter the value of Nth term 'N' ");
        int n = s.nextInt();
        // calling printSeries method to print the series
        printSeries(n);
    }
    
    //printSeries metthod to print the series
    public static void printSeries(int n)
    {
        //for loop to print the series
       for (int i = 1; i <= n; i++) 
        {
            for(int j = 1; j<=i; j++)
            {
                System.out.print(i);
            }
            System.out.print(" ");
        } 
    }
}

Output:

Enter the value of Nth term 'N' 
10
1 22 333 4444 55555 666666 7777777 88888888 999999999 10101010101010101010

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