# Java Program to Print the Series 1 22 333 4444 55555 … N

In the previous article we have discussed about Java Program to Print the Series 0 2 6 12 20 30 42 … N

In this article we are going to see how to print the series 1 22 333 4444 55555 … N by using Java programming language. How can you write a program to print the following pattern 1 22 333 in java? How do you print this pattern in java 1 22 333 4444 55555 666666 7777777 88888888 999999999? How to write the 1 22 333  pyramid pattern in java? How do you write 1 22 333 4444 pattern in java. Write nested for loops to produce the following output 1 22 333 4444 55555? How to write a program which will produce the following output 1 22 333 4444 55555? And 1 22 333 pattern in c? What is the output of the code Below Print(‘{:,}’.Format(1223334444))? Finally how to print the Print The Following Pattern For The Given N Number Of Rows, Pattern For N = 4 4444 333 22 1?

## Java Program to Print the Series 1 22 333 4444 55555 … N

On observing the pattern carefully, we can see

1st number starts from 1 and in each term it will increment by 1 and n times repeated.

1
22
333
4444
55555
.
nnnnnnn….n

Let’s see different ways to print the series 1 22 333 4444 55555 … N

Recommended Reading On: 2 … 3 … 6 … 11 … 18 … ? – Java Program to Print the Series 3 6 11 18 27 … N

### Method-1: Java Program to Print the Series 1 22 333 4444 55555 … N By Using For Loop

Approach:

• Create Scanner class object.
• Declare an integer variable say ‘n’ which holds the Nth term of the series
• Prompt the user to enter a number as value of n.
• Use a for loop from i=1 to i<=n where the loop is incremented by 1
• Inside the for loop we will again use a for loop from j =1 to j<=i where the loop is incremented by 1
• Inside the j loop we will print the result of i which will be repeated j times.
• Outside j loop we will Print the series separated by single space “ ”.

Program:

import java.util.*;
public class Main
{
public static void main(String [] args)
{
//creating object of Scanner class
Scanner s = new Scanner(System.in);
//Taking input of number of elements in the series
System.out.println("Enter the Nth term “N” ");
int n = s.nextInt();
//for loop to print the series
for (int i = 1; i <= n; i++)
{
for(int j = 1; j<=i; j++)
{
System.out.print(i);
}
System.out.print(" ");
}
}
}

Output:

Enter the Nth term “N”
5
1 22 333 4444 55555

### Method-2: Java Program to Print the Series 1 22 333 4444 55555 … N By Using While Loop

Approach:

• Create Scanner class object.
• Declare an integer variable say ‘n’ which holds the Nth term of the series
• Prompt the user to enter a number as value of n.
• Declare and initialize an integer variable i=1
• Continue a while loop till i<=n, where i is incremented by 1.
• Inside while loop Declare and initialize an integer variable j=1
• Continue a while loop till j<=i, where j is incremented by 1.
• Inside the j loop we will print the result of i which will be repeated j times.
• Outside j loop we will Print the series separated by single space “ ”.

Program:

import java.util.*;
public class Main
{
public static void main(String [] args)
{
//creating object of Scanner class
Scanner s = new Scanner(System.in);
//Taking input of number of elements in the series
System.out.println("Enter the Nth term “N” ");
int n = s.nextInt();
int i=1;
while(i<=n)
{
int j = 1;
while( j<=i)
{
System.out.print(i);
j++;
}
System.out.print(" ");
i++;
}
}
}

Output:

Enter the Nth term “N”
6
1 22 333 4444 55555 666666

### Method-3: Java Program to Print the Series 1 22 333 4444 55555 … N By Using User Defined Method

Approach:

• The same logic as method 1 but this time we are moving the for inside a user-defined method
• Create a Scanner class object.
• Prompt the user to enter the Nth term “N”
• Call a user defined method printSeries() by passing n as parameter.
• Inside the method use a for loop to find the series.
• Use a for loop from i =1 to i<=n where the loop is incremented by 1
• Inside the for loop we will again use another for loop from j = 1 to j<=i where the loop is incremented by 1
• Inside the j loop we will print the result of i which will be repeated j times.
• Outside j loop we will Print the series separated by single space “ ”.

Program:

import java.util.*;
public class Main
{
public static void main(String[] args)
{
// creating object of scanner class
Scanner s = new Scanner(System.in);
//Taking input of number of elements in the series
System.out.println("Enter the value of Nth term 'N' ");
int n = s.nextInt();
// calling printSeries method to print the series
printSeries(n);
}

//printSeries metthod to print the series
public static void printSeries(int n)
{
//for loop to print the series
for (int i = 1; i <= n; i++)
{
for(int j = 1; j<=i; j++)
{
System.out.print(i);
}
System.out.print(" ");
}
}
}
Output:

Enter the value of Nth term 'N'
10
1 22 333 4444 55555 666666 7777777 88888888 999999999 10101010101010101010

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