In the previous article, we have discussed about Java Program to Find Sum of Geometric Progression
In this article we will see how we can find product between sum of all even and sum of odd digits of a number using Java programming language.
Java Program to Find Product of Sum of Odd Digits and Even Digits of a Given Number
We have to find product of sum of even and odd digits of a number. Means we have to check each number it is even or odd. If it is odd then add it with odd digits and if it is even then add it with even digits and finally show the product between sum of odd and sum of even digits.
For example:
If a number is 67843
Then in this number even digits are 6, 8 and 4. So, sum of even digits are 6+8+4=18
Odd digits are 7 and 3. So, sum of odd digits are 7+3=10
So the product between sum of even digits and sum of odd digits = 18 * 10 = 180
Let’s see different ways to find sum of all even and odd digits of a number.
Method-1: Java Program to Find Product of Sum of Odd Digits and Even Digits of a Given Number By Using Static Input Value
Approach:
- Declare an integer variable ‘
number‘ and initialize the value. - Declare two integer variables
evenSumandoddSumand initialize both to 0. - Using a while loop check each digit the number.
- If digit is even then add it to
evenSum - else add it to
oddSum - Now find the product between
evenSumandoddSumand print the result.
Program:
public class Main
{
public static void main(String args[])
{
//an integr variable 'number' declared and initialized
int number = 6547;
//declaring two variables evenSum and oddSum
//and initializing both to 0
int evenSum=0;
int oddSum=0;
//continue loop till number becomes 0
while(number!=0)
{
//getting digit of number
int rem=number%10;
//if 'rem' is even digit then add it to evenSum
if(rem%2==0)
{
evenSum=evenSum+rem;
}
//else add it to oddSum
else
{
oddSum=oddSum+rem;
}
number=number/10;
}
System.out.println("Sum of even digits: "+ evenSum);
System.out.println("Sum of odd digits: "+ oddSum);
//find product between oddSum and evenSum and print result
System.out.println("Product between Sum of odd digits and Sum of even digits are: "+ (oddSum*evenSum));
}
}
Output: Sum of even digits: 10 Sum of odd digits: 12 Product between Sum of odd digits and Sum of even digits are: 120
Method-2: Java Program to Find Product of Sum of Odd Digits and Even Digits of a Given Number By Using User Input Value
Approach:
- Declare an integer variable ‘
number‘ and take the value as user input using Scanner class. - Declare two integer variables
evenSumandoddSumand initialize both to 0. - Using a while loop check each digit the number.
- If digit is even then add it to
evenSum - else add it to
oddSum - Now find the product between
evenSumandoddSumand print the result.
Program:
import java.util.*;
public class Main
{
public static void main(String args[])
{
Scanner sc=new Scanner(System.in);
//taking a number input from user
System.out.println("Enter a number: ");
int number = sc.nextInt();
//declaring two variables evenSum and oddSum
//and initializing both to 0
int evenSum=0;
int oddSum=0;
//continue loop till number becomes 0
while(number!=0)
{
//getting digit of number
int rem=number%10;
//if 'rem' is even digit then add it to evenSum
if(rem%2==0)
{
evenSum=evenSum+rem;
}
//else add it to oddSum
else
{
oddSum=oddSum+rem;
}
number=number/10;
}
System.out.println("Sum of even digits: "+ evenSum);
System.out.println("Sum of odd digits: "+ oddSum);
//find product between oddSum and evenSum and print result
System.out.println("Product between Sum of odd digits and Sum of even digits are: "+ (oddSum*evenSum));
}
}
Output: Enter a number: 5344 Sum of even digits: 8 Sum of odd digits: 8 Product between Sum of odd digits and Sum of even digits are: 64
Method-3: Java Program to Find Product of Sum of Odd Digits and Even Digits of a Given Number By Using User Defined Method
Approach:
- Declare an integer variable ‘
number‘ and initialize the value. - Call a user defined method
evenOdd()and pass that number as parameter. - Inside method declare two integer variables
evenSumandoddSumand initialize both to 0. - Using a while loop check each digit the number.
- If digit is even then add it to
evenSum - else add it to
oddSum - Now find the product between
evenSumandoddSumand print the result.
Program:
import java.util.*;
public class Main
{
public static void main(String args[])
{
Scanner sc=new Scanner(System.in);
//taking a number input from user
System.out.println("Enter a number: ");
int number = sc.nextInt();
//calling user defined method evenOdd()
evenOdd(number);
}
//evenOdd() method to find sum of even and odd digits
public static void evenOdd(int number)
{
//declaring two variables evenSum and oddSum
//and initializing both to 0
int evenSum=0;
int oddSum=0;
//continue loop till number becomes 0
while(number!=0)
{
//getting digit of number
int rem=number%10;
//if 'rem' is even digit then add it to evenSum
if(rem%2==0)
{
evenSum=evenSum+rem;
}
//else add it to oddSum
else
{
oddSum=oddSum+rem;
}
number=number/10;
}
System.out.println("Sum of even digits: "+ evenSum);
System.out.println("Sum of odd digits: "+ oddSum);
//find product between oddSum and evenSum and print result
System.out.println("Product between Sum of odd digits and Sum of even digits are: "+ (oddSum*evenSum));
}
}
Output: Enter a number: 73 Sum of even digits: 0 Sum of odd digits: 10 Product between Sum of odd digits and Sum of even digits are: 0
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