Java Program to Check Neon Number

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In the previous article, we have discussed Java Program to Check Harshad Number

In this article we are going to understand what Neon number is and how we can check whether a number is Neon or not in Java with examples.

Java Program to Check Neon Number

Neon numbers are numbers where the sum of digits of square of the number is equal to the number itself.

Example:

9-> (9)2= 81, 8+1=9 Neon number 
5 -> (5)2=25, 2+5=7 Not a Neon number 
8 -> (8)2=64, 6+4=10 Not a Neon number

Where (number)2 represents the square of the number inside parenthesis.

In the above examples the number 9 square is 81 which adds upto 9. The remaining two’s square digits sum doesn’t add up to the numbers. Hence 9 is the only Neon number here.

Let’s see different ways to check neon number.

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Approach:

  1. We ask the user to enter a number which we store in an integer variable num.
  2. Then we store the square of num in a variable square.
  3. We then use a while loop to iterate through all the digits in the number inside square variable and add it all.
  4. If the resultant sum is equal to the number, it is said to be a Neon number or else it is not.

Method-1: Java Program to Check Neon Number By Using Static Value

import java.util.Scanner;

public class NeonNumber
{
    public static void main(String args[])
    {
        //A number is declared
        int num = 9;

        //Square holds the square of the number
        int square = num*num , sum = 0, remainder;
        //Loop to iterate and add the digits of the square number
        while (square > 0)
        {
            remainder = square % 10;
            sum = sum + remainder;
            square = square / 10;
        }
        if (num == sum)
        {
            System.out.println(num+" is a Neon Number");
        }
        else
        {
            System.out.println(num+" is not a Neon Number");
        }
    }
}

 Output:

Enter a number : 9
9 is a Neon Number

Method-2: Java Program to Check Neon Number By Using User Input Value

import java.util.Scanner;

public class NeonNumber
{
    public static void main(String args[])
    {
        //Taking the number as input from the user using scanner class
        Scanner scan = new Scanner(System.in);
        System.out.print("Enter a number : ");
        int num = scan.nextInt();

        //Square holds the square of the number
        int square = num*num , sum = 0, remainder;
        //Loop to iterate and add the digits of the square number
        while (square > 0)
        {
            remainder = square % 10;
            sum = sum + remainder;
            square = square / 10;
        }
        if (num == sum)
        {
            System.out.println(num+" is a Neon Number");
        }
        else
        {
            System.out.println(num+" is not a Neon Number");
        }
    }
}

 Output:

Enter a number : 9
9 is a Neon Number

Method-3: Java Program to Check Neon Number By Using User Defined Method

import java.util.Scanner;

public class NeonNumber
{
    public static void main(String args[])
    {
        //Taking the number as input from the user using scanner class
        Scanner scan = new Scanner(System.in);
        System.out.print("Enter a number : ");
        int num = scan.nextInt();
        //calling the user defined method
        //to check Neon number or not.
        checkNumber(num);
    }

    //checkNumber() method tocheck Neon number
    public static void checkNumber(int num)
    {

        //Square holds the square of the number
        int square = num*num , sum = 0, remainder;
        //Loop to iterate and add the digits of the square number
        while (square > 0)
        {
            remainder = square % 10;
            sum = sum + remainder;
            square = square / 10;
        }
        if (num == sum)
        {
            System.out.println(num+" is a Neon Number");
        }
        else
        {
            System.out.println(num+" is not a Neon Number");
        }
    }
}

 

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