Java Program to Print Zig-Zag Matrix Number Pattern

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Printing Zig-Zag Matrix Number Pattern

In the previous article, we have discussed Java Program to Print Rectangular with User Input Centre Number Pattern.

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In this article we will see how to print Zig Zag Matrix number pattern.

Example-1 

When number of row value is taken 3

1 2 4 
3 5 7
6 8 9
Example-2 

When number of row value is taken 5

1    2    4    7     11
3    5    8    12   16
6    9    13  17   20
10 14   18   21  23
15 19   22   24  25

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Approach :

  • Enter the dimension of the matrix .
  • Create N*N matrix according to the dimension.
  • Divide the matrix to 2 right angle tringle .
  • Take first for loop calculate the all value of the upper part of the right angle tringle
  • Take second for loop to calculate all the vale of the lower tringle .
  • After calculating all the matrix value print it .

Java Code to Print Zig-Zag Matrix Number Pattern:

import java.io.*;
import java.util.*;

class Main
{
    public static void main(String[] args)
    {
        // taking the dimention of the square of the matrix as size
        Scanner sc=new Scanner(System.in);
        System.out.println("Enter dimension: ")
        int size=sc.nextInt();
        int numberOfRows , numberOfColumns  ;
        
        //  N * N matrix to store the values
        int [][]arr = new int[size][size];
        arr[0][0] = 1;
        // first loop for Filling the values of upper triangle
        for ( numberOfRows = 0; numberOfRows < size; numberOfRows++) 
        {
            if (numberOfRows > 0) 
                arr[numberOfRows][0] = arr[numberOfRows - 1][0] + numberOfRows + 1;
            for ( numberOfColumns = 1;numberOfColumns < size - numberOfRows; numberOfColumns++)
                arr[numberOfRows][numberOfColumns] = arr[numberOfRows][numberOfColumns - 1] + numberOfRows + numberOfColumns;
        }
        //second loop for Filling the values of lower triangle
        arr[1][size - 1] = arr[size - 1][0] + 1;
        int div = 0;
        for ( numberOfRows = 2; numberOfRows < size; numberOfRows++) 
        {
            div = size - 2;
            for ( numberOfColumns = size - numberOfRows; numberOfColumns < size; numberOfColumns++)
            {
                if (numberOfColumns == size - numberOfRows)
                    arr[numberOfRows][numberOfColumns] = arr[numberOfRows - 1][numberOfColumns + 1] + 1;
                else 
                 {
                    arr[numberOfRows][numberOfColumns] = arr[numberOfRows][numberOfColumns - 1] + div;
                    div--;
                 }
            }
        }
         // loop for Printing the array
        for ( numberOfRows = 0; numberOfRows < size; numberOfRows++)
            {
                for ( numberOfColumns = 0; numberOfColumns < size; numberOfColumns++) 
                    System.out.print(arr[numberOfRows][numberOfColumns] + " ");
                System.out.print("\n");
            }
    }
}


Output:

Enter dimension: 3

1 2 4 
3 5 7
6 8 9

C Code to Print Zig-Zag Matrix Number Pattern:

(Static size 5 taken.)

#include <stdio.h>
#include <stdlib.h>
int main()
{
        int  size = 5, numberOfRows , numberOfColumns;
        int arr[size][size];
        arr[0][0] = 1;
        for ( numberOfRows = 0; numberOfRows < size; numberOfRows++) 
          {
            if (numberOfRows > 0) 
                arr[numberOfRows][0] = arr[numberOfRows - 1][0] + numberOfRows + 1;
            for ( numberOfColumns = 1;numberOfColumns < size - numberOfRows; numberOfColumns++)
                arr[numberOfRows][numberOfColumns] = arr[numberOfRows][numberOfColumns - 1] + numberOfRows + numberOfColumns;
          }
        arr[1][size - 1] = arr[size - 1][0] + 1;
        int div = 0;
        for ( numberOfRows = 2; numberOfRows < size; numberOfRows++) 
        {
            div = size - 2;
            for ( numberOfColumns = size - numberOfRows; numberOfColumns < size; numberOfColumns++)
            {
                if (numberOfColumns == size - numberOfRows)
                    arr[numberOfRows][numberOfColumns] = arr[numberOfRows - 1][numberOfColumns + 1] + 1;
                else 
                 {
                    arr[numberOfRows][numberOfColumns] = arr[numberOfRows][numberOfColumns - 1] + div;
                    div--;
                 }
            }
        }
        for ( numberOfRows = 0; numberOfRows < size; numberOfRows++)
            {
                for ( numberOfColumns = 0; numberOfColumns < size; numberOfColumns++) 
                    printf("%d ",arr[numberOfRows][numberOfColumns]);
                    printf("\n");
            }
    return 0;
}

Output:

1   2   4   7   11
3   5   8   12 16
6   9   13 17 20
10 14 18 21 23
15 19 22 24 25

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Try yourself:

  1. Write a program to print the matrix in a zigzag form in c?
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  4. Given an nxn matrix print the values in reverse diagonal order?
  5. Print matrix in zigzag form leetcode?
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