# Java Program to Print Series 3 6 9 12 15 18 …N

In the previous article, we have discussed about Java Program to Print Series 2 4 6 8 10 12 …N

In this article we are going to see how to print the series 3 6 9 12 15 18 …N by using Java programming language.

## Java Program to Print Series 3 6 9 12 15 18 …N

In this series it can be seen that

• Numbers at each position ‘i‘, the term is calculated as 3×i OR
• First element of series is 3 and next elements are calculated as previous element + 3

For example, if the series has 3 terms, the output will be

3×1   3×2   3×3

3        6        9

For example, if the series has 5 terms, the output will be

3×1  3×2  3×3  3×4  3×5

3       6      9       12      15

Let’s see different ways to find the series.

### Method-1: Java Program to Print Series 3 6 9 12 15 18 …N By Using Multiplication

Approach:

• Create Scanner class object.
• Declare an integer variable ‘n‘ which holds the value of number of terms in the series.
• Prompt the user to enter the value of variable ‘n
• Run a for loop from i=0 to i<=n.
• Inside the loop, print 3*i

Program:

import java.util.Scanner;
public class Main
{
public static void main(String[] args)
{
//create a Scanner object
Scanner sc = new Scanner(System.in);
//prompt the user to enter the number of terms
System.out.print("Enter the number of terms: ");
int n = sc.nextInt();
//print the series
System.out.print("The series is: ");
for (int i = 1; i <= n; i++)
{
System.out.print(3*i + " ");
}
}
}
Output:

Enter the number of terms: 10
The series is: 3 6 9 12 15 18 21 24 27 30

### Method-2: Java Program to Print Series 3 6 9 12 15 18 …N By Using Addition

Approach:

• Create Scanner class object.
• Declare an integer variable ‘n‘ which holds the value of number of terms in the series.
• Declare an integer variable say ‘value‘ and initialize it with value 3.
• Prompt the user to enter the value of variable ‘n
• Print ‘value‘ which is having value 3.
• Run a for loop from i=0 to i<n-1.
• Inside the loop, print value+3 , as by using addition logic when we will add previous element with 3 then we will get next element of the series.

Program:

import java.util.Scanner;
public class Main
{
public static void main(String[] args)
{
// create a Scanner object
Scanner sc = new Scanner(System.in);
// prompt the user to enter the number of terms
System.out.print("Enter the number of terms: ");
int n = sc.nextInt();
int value=3;
// print the series
System.out.print("The series is: ");
System.out.print(value+" ");
for (int i = 0; i < n-1; i++)
{
value=value+3;
System.out.print(value+" ");
}
}
}
Output:

Enter the number of terms: 5
The series is: 3 6 9 12 15

### Method-3: Java Program to Print Series 3 6 9 12 15 18 …N By Using User Defined Method

Approach:

• Create Scanner class object.
• Declare an integer variable ‘n‘ which holds the value of number of terms in the series.
• Prompt the user to enter the value of variable ‘n
• Then call a user defined method by passing n as parameter.
• Inside method run a for loop from i=0 to i<=n.
• Inside the loop, print 3*i

Program:

import java.util.Scanner;
public class Main
{
public static void main(String[] args)
{
//create a Scanner object
Scanner sc = new Scanner(System.in);
//prompt the user to enter the number of terms
System.out.print("Enter the number of terms: ");
int n = sc.nextInt();
//call the method to print the series
printSeries(n);
}

//user defined method printSeries() to print series
private static void printSeries(int n)
{
System.out.println("The series is: ");
for (int i = 1; i <= n; i++)
{
System.out.print(3*i + " ");
}
}
}
Output:

Enter the number of terms: 8
The series is:
3 6 9 12 15 18 21 24

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