Java Program to Print Forward Slash Character Pattern

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Program to Print Forward Slash Character Pattern

In the previous article, we have discussed Java Program to print Arrow Character Pattern

In this article we are going to see how to print the forward slash character pattern.

Example-1:

When no. of rows :    5

        E 
      D 
    C 
  B 
A
Example-2

When no. of rows :    8
          
               H 
            G 
          F 
        E 
      D 
    C 
  B 
A

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Approach:

  • Enter total row and store it an integer variable say row.
  • Take first for loop to print all the rows.
  • Take inner loop to print the column values.
  • Print the character symbol if c==(row+1-r).

Java Code to Print Forward Slash Character Pattern

import java.util.Scanner;
class Main 
{
    public static void main(String[] args) 
    {
        int r,c,row;
        // starting ASCII value taken 65
        int ascii=65;
        System.out.print("Enter no of rows : ");
        // create object of Scanner class
        Scanner sc= new Scanner(System.in);
        // Store the input from user to row
        row=sc.nextInt();
    
        // loop for no of rows
        for(r=1;r<=row;r++)
        {
          // loop for printing character symbol
          for(c=1;c<=row;c++)
          {
                // printing characters and spaces based on condition
                if(c <= (row+1-r))
                {
                   if( c == (row+1-r) )
                      System.out.print((char)(c+ascii)+" ");
                   else
                      System.out.print("  ");
                }
          }
          System.out.println("");
       }
    }
}

Output:

Enter no of rows :     8
       
              H 
            G 
          F 
        E 
      D 
    C 
  B 
A

C Code to Print Forward Slash Character Pattern

#include<stdio.h>
int main()
{
   int r,c,row;
   int ascii=64;
   printf("Enter no of rows : ");
   scanf("%d",&row);
   for(r=1;r<=row;r++)
   {
      for(c=1;c<=row;c++)
      {
            if(c <= (row+1-r))
            {
               if( c == (row+1-r) )
                  printf("%c",(c+ascii));
               else
                  printf("  ");
            }
      }
      printf("\n");
   }
   return 0;
}
Output:

Enter no of rows :    8  

              H 
            G 
          F 
        E 
      D 
    C 
  B 
A

C++ Code to Print Forward Slash Character Pattern

#include <iostream>
using namespace std;
int main() {
   int r,c,row;
   // starting ASCII value taken 64
   int ascii=64;
 
   cout<<("Enter no of rows : ");
   cin>>row;
   for(r=1;r<=row;r++)
   {
      for(c=1;c<=row;c++)
      {
            if(c <= (row+1-r))
            {
               if( c == (row+1-r) )
                  cout<< (char)(c+ascii) << " ";
               else
                  cout<<("  ");
            }
      }
      cout<<("\n");
   }
   return 0;
}
Output:

Enter no of rows :     8
 
              H 
            G 
          F 
        E 
      D 
    C 
  B 
A

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