Java Program to Compute a3+b3+c3 -3abc where Value of a, b, and c are Given

In the previous article we have discussed Java Program to Compute 2(a2+b2) where Value of a and b are Given

In this program we are going to see how to compute a³+b³+c³-3abc where value of a, b, and c are given

Java Program to Compute a3+b3+c3 -3abc where Value of a, b, and c are Given

The formula of a³ + b³ + c³– 3abc is given below.

a³ + b³ + c³– 3abc = (a + b + c)(a² + b² + c² – ab – bc – ca)

Now we will convert this into a valid Java expression.

Let x= a³+b³+c³-3abc

= (a + b + c)(a² + b² + c² – ab – bc – ca)

=(a+b+c)*((a*a)+(b*b)+(c*c)-(a*b)-(b*c)-(c*a))

Now let’s see different ways to compute a³+b³+c³-3abc

By Using Static Input Value
By Using pow() Function
By Using User Defined Method

Method-1: Java Program to Compute a3+b3+c3 -3abc where Value of a, b, and c are Given By Using Static Input Value

Approach:

Declare and initialize three integer variables say a, b and c.
By using the formula compute a³+b³+c³-3abc
Print the result.

Program:

class Main
{
    public static void main(String[] args)
    {
        //declare the first integer variable with an integer value
        int a= 4;
        System.out.println("a= " +a);
        //declare the second integer variable with an integer value
        int b= 4;
        System.out.println("b= "+b);
        //declare the third integer variable with an integer value
        int c= 2;
        System.out.println("c= "+c);
        //declare another integer variable and assigned the formulated value to it.
        int d=(a+b+c)*((a*a)+(b*b)+(c*c)-(a*b)-(b*c)-(c*a));
        System.out.println("(a3+b3+c3)-3abc= "+d);
    }
}

Output:

a= 4
b= 4
c= 2
(a3+b3+c3)-3abc= 40

Method-2: Java Program to Compute a3+b3+c3 -3abc where Value of a, b, and c are Given By Using User Input Value and Pow() Function

Approach:

Declare three integer variables say a, b and c.
Take the value of a and b as user input by using Scanner class.
Then By using the formula compute a³+b³+c³-3abc
Here we will use inbuilt pow() function to compute the value.
Print the result.

Program:

import java.lang.Math;
import java.util.Scanner;
class Main
{
    public static void main(String[] args)
    {
        //create object of scanner class.
        Scanner sc=new Scanner(System.in);
        System.out.print("a= ");
        //Take the first input from the user.
        int a= sc.nextInt();
        System.out.print("b= ");
        //Take the second input from the user.
        int b= sc.nextInt();
        System.out.print("c= ");
        //Take the third input from the user.
        int c= sc.nextInt();
        //declare another integer variable and assigned the formulated value to it.
        double  d=(a+b+c)*( Math.pow(a,2)+ Math.pow(b,2)+ Math.pow(c,2)- (a*b)-(b*c)-(c*a));
        System.out.println("(a3+b3+c3) -3abc = "+(int)d); 
    }
}

Output:

a= 4
b= 5
c= 6
(a3+b3+c3) -3abc = 45

Method-3: Java Program to Compute a3+b3+c3 -3abc where Value of a, b, and c are Given By Using User Defined Method

Approach:

Declare three integer variables say a, b and c.
Take the value of a and b as user input by using Scanner class.
Then call a user defined method say computeValue() and pass a, b and c as parameter.
Then inside method by using the formula compute a³+b³+c³-3abc
Print the result.

Program:

import java.util.Scanner;
class Main
{
    public static void main(String[] args)
    {
        //create object of scanner class.
        Scanner sc=new Scanner(System.in);
        System.out.print("a= ");
        //Take the first input from the user.
        int a= sc.nextInt();
        System.out.print("b= ");
        //Take the second input from the user.
        int b= sc.nextInt();
        System.out.print("c= ");
        //Take the third input from the user.
        int c= sc.nextInt();
        //call the funtion
        computeValue(a,b,c);
    }
    //define the method
    public static void computeValue(int a, int b,int c)
    {
        //declare another integer variable and assigned the formulated value to it.
        int d=(a+b+c)*((a*a)+(b*b)+(c*c)-(a*b)-(b*c)-(c*a));
        System.out.println("(a3+b3+c3)-3abc= "+d);
    }
}

Output:

a= 8
b= 10
c= 12
(a3+b3+c3)-3abc= 360

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