# Java Program to Compute (a-b)4 where Value of a and b are Given

In the previous article we have discussed Java Program to Compute (a+b)4 where Value of a and b are Given

In this program we are going to see how to compute (a-b)4 where value of a and b are given by using Java programming language.

## Java Program to Compute (a-b)4 where Value of a and b are Given

The formula of (a – b)4 is given below.

(a – b)4 = a4 + b4 – 4a3b + 6a2b2 – 4ab3

Now we will convert this into a valid Java expression.7.

Let x= (a-b)4

=  a4 + b4 – 4a3b + 6a2b2 – 4ab3

= (a * a * a * a) + (b * b * b * b) – (4 * a * a * a * b) + (6 * a * a * b  * b) – (4 * a * b * b * b)

Example:

Suppose a=2 and b=2, then

(a-b)4
= (a * a * a * a) + (b * b * b * b) - (4 * a * a * a * b) + (6 * a * a * b  * b) - (4 * a * b * b * b)
= (2*2*2*2)+(2*2*2*2)-(4*2*2*2*2)+(6*2*2*2*2)-(4*2*2*2*2)
= 0

Now let’s see different ways to compute (a-b)4

### Method-1: Java Program to Compute (a-b)4 where Value of a and b are Given By Using Static Input Value

Approach:

• Declare and initialize two integer variables say a and b.
• By using the formula compute (a-b)4
• Print the result.

Program:

class Main
{
public static void main(String[] args)
{
//declare the first integer variable with an integer value
int a= 15;
System.out.println("a= " +a);
//declare the second integer variable with an integer value
int b= 7;
System.out.println("b= "+b);
//declare another integer variable and assigned the formulated value to it.
int c=(a*a*a*a) + (b*b*b*b) - (4*a*a*a*b) + (6*a*a*b*b) - (4*a*b*b*b);
System.out.println("(a-b)4= "+c);
}
}

Output:

a= 15
b= 7
(a-b)4= 4096

### Method-2: Java Program to Compute (a-b)4 where Value of a and b are Given By Using User Input Value

Approach:

• Declare two integer variables say a and b.
• Take the value of a and b as user input by using Scanner class.
• Then By using the formula compute (a-b)4
• Print the result.

Program:

import java.util.Scanner;
class Main
{
public static void main(String[] args)
{
//create object of scanner class.
Scanner sc=new Scanner(System.in);
System.out.print("a= ");
//Take the first input from the user.
int a= sc.nextInt();
System.out.print("b= ");
//Take the second input from the user.
int b= sc.nextInt();
//declare another integer variable and assigned the formulated value to it.
int c=(a*a*a*a) + (b*b*b*b) - (4*a*a*a*b) + (6*a*a*b*b) - (4*a*b*b*b);
System.out.println("(a-b)4= "+c);
}
}

Output:

a= 20
b= 11
(a-b)4= 6561

### Method-3: Java Program to Compute (a-b)4 where Value of a and b are Given By Using User Defined Method

Approach:

• Declare two integer variables say a and b.
• Take the value of a and b as user input by using Scanner class.
• Then call a user defined method say computeValue() and pass a and b as parameter.
• Then inside method by using the formula compute (a-b)4
• Print the result.

Program:

import java.util.Scanner;
class Main
{
public static void main(String[] args)
{
//create object of scanner class.
Scanner sc=new Scanner(System.in);
System.out.print("a= ");
//Take the first input from the user.
int a= sc.nextInt();
System.out.print("b= ");
//Take the second input from the user.
int b= sc.nextInt();
//call the function
computeValue(a,b);
}
//define the method
public static void computeValue(int a, int b)
{
//declare another integer variable and assigned the formulated value to it.
int c=(a*a*a*a) + (b*b*b*b) - (4*a*a*a*b) + (6*a*a*b*b) - (4*a*b*b*b);
System.out.println("(a-b)4= "+c);
}
}

Output:

a= 8
b= 10
(a-b)4= 16

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