Write a Java Program to Check Buzz Number

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In the previous article, we have discussed Java Program to Check Automorphic Number

In this article we are going to understand what Buzz number is and how we can check whether a number is Buzz or not in Java with examples.

Java Program to Check Buzz Number

Buzz numbers are numbers which are divisible by 7 or contain 7 if it ends with 7.

Example:

49 -> Buzz number
67 -> Buzz number
99 -> not a Buzz number

In the above examples the number 49 is divisible by 7 and number 67 has 7 at its end. Both of them are either divisible by 7 or have 7 at its end hence they are Buzz number. However, 99 is not divisible by 7 and neither does it contain 7 at its end. Hence 9 is not a Buzz number.

Let’s see different ways to check Buzz number.

Approach:

  1. We ask the user to enter a number which we store in an integer variable num.
  2. Then the number is divided by 10 to see if it leaves 7 as a remainder, if not its divisibility by 7 is checked.
  3. If the number passed either of the condition it is a Buzz number else not.

Method-1:Java Program to Check Buzz Number By Using Static Value

import java.util.Scanner;
public class BuzzNumber
{
    public static void main(String args[])
    {
        //A number is declared
        int num = 49;

        //Checks whether the number is divisble by 7 or has 7 at its end
        if (num % 10 == 7 || num % 7 == 0)
        {
            System.out.println(num+" is a Buzz number");
        }
        else
        {
            System.out.println(num+" is not a Buzz number");
        }
    }
}

Output:

49 is a Buzz number

Method-2: Java Program to Check Buzz Number By Using User Input Value

import java.util.Scanner;
public class BuzzNumber
{
    public static void main(String args[])
    {
        //Taking the number as input from the user using scanner class
        Scanner scan = new Scanner(System.in);
        System.out.print("Enter a number : ");
        int num = scan.nextInt();

        //Checks whether the number is divisble by 7 or has 7 at its end
        if (num % 10 == 7 || num % 7 == 0)
        {
            System.out.println(num+" is a Buzz number");
        }
        else
        {
            System.out.println(num+" is not a Buzz number");
        }
    }
}

Output:

Enter a number : 97
97 is a Buzz number

By Using C Language:

#include<stdio.h>

 int main()
 {
     //an integer variable declared
     //to store the number
     int number;
     
     printf("Enter a number : ");
     //taking a number input
     scanf("%d",&number);
     
     //checking buzz number or not
     if(number%10==7||number%7==0)
         printf("%d is a Buzz number",number);
     else
         printf("%d is not a Buzz number",number);
     return 0;
 }

Output:

Enter a number : 7
7 is a Buzz number

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