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Given the number of rows of the pyramid, the task is to print a Reverse Pyramid of Numbers in C, C++, and Python.
Examples:
Example1:
Input:
Given number of rows = 10
Output:
1 2 1 3 2 1 4 3 2 1 5 4 3 2 1 6 5 4 3 2 1 7 6 5 4 3 2 1 8 7 6 5 4 3 2 1 9 8 7 6 5 4 3 2 1
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Example2:
Input:
Given number of rows = 6
Output:
1 2 1 3 2 1 4 3 2 1 5 4 3 2 1
Program to Print Reverse Pyramid of Numbers in C,C++, and Python
Method #1: Using For Loop (Static Input)
Approach:
- Give the number of rows as static input and store it in a variable.
- Loop from 1 to the number of rows using For loop.
- Loop from the parent loop iterator value to 0 in decreasing order using another For loop(Nested For Loop).
- Print the iterator value of the inner for loop.
- Print the Newline character after the end of the inner loop.
- The Exit of the Program.
1) Python Implementation
Below is the implementation:
# Give the number of rows as static input and store it in a variable.
numbrrows = 10
# Loop from 1 to the number of rows using For loop.
for m in range(1, numbrrows):
# Loop from the parent loop iterator value to 0 in decreasing order
# using another For loop(Nested For Loop).
for n in range(m, 0, -1):
# Print the iterator value of the inner for loop.
print(n, end=' ')
# Print the Newline character after the end of the inner loop.
print()
Output:
1 2 1 3 2 1 4 3 2 1 5 4 3 2 1 6 5 4 3 2 1 7 6 5 4 3 2 1 8 7 6 5 4 3 2 1 9 8 7 6 5 4 3 2 1
2) C++ Implementation
Below is the implementation:
#include <iostream>
using namespace std;
int main()
{
// Give the number of rows as static input and store it
// in a variable.
int numbrrows = 10;
// Loop from 1 to the number of rows using For loop.
for (int m = 1; m < numbrrows; m++) {
// Loop from the parent loop iterator value to 0 in
// decreasing order using another For loop(Nested
// For Loop).
for (int n = m; n > 0; n--) {
// Print the iterator value of the inner for
// loop.
cout << n << " ";
}
// Print the Newline character after the end of the
// inner loop.
cout << endl;
}
return 0;
}
Output:
1 2 1 3 2 1 4 3 2 1 5 4 3 2 1 6 5 4 3 2 1 7 6 5 4 3 2 1 8 7 6 5 4 3 2 1 9 8 7 6 5 4 3 2 1
3) C Implementation
Below is the implementation:
#include <stdio.h>
int main()
{
// Give the number of rows as static input and store it
// in a variable.
int numbrrows = 10;
// Loop from 1 to the number of rows using For loop.
for (int m = 1; m < numbrrows; m++) {
// Loop from the parent loop iterator value to 0 in
// decreasing order using another For loop(Nested
// For Loop).
for (int n = m; n > 0; n--) {
// Print the iterator value of the inner for
// loop.
printf("%d ", n);
}
// Print the Newline character after the end of the
// inner loop.
printf("\n");
}
return 0;
}
Output:
1 2 1 3 2 1 4 3 2 1 5 4 3 2 1 6 5 4 3 2 1 7 6 5 4 3 2 1 8 7 6 5 4 3 2 1 9 8 7 6 5 4 3 2 1
Method #2: Using For Loop (User Input)
Approach:
- Give the number of rows as user input and store it in a variable.
- Loop from 1 to the number of rows using For loop.
- Loop from the parent loop iterator value to 0 in decreasing order using another For loop(Nested For Loop).
- Print the iterator value of the inner for loop.
- Print the Newline character after the end of the inner loop.
- The Exit of the Program.
1) Python Implementation
Give the number of rows as user input using int(input()) and store it in a variable.
Below is the implementation:
# Give the number of rows as user input using int(input()) and store it in a variable.
numbrrows = int(input('Enter some random number of rows = '))
# Loop from 1 to the number of rows using For loop.
for m in range(1, numbrrows):
# Loop from the parent loop iterator value to 0 in decreasing order
# using another For loop(Nested For Loop).
for n in range(m, 0, -1):
# Print the iterator value of the inner for loop.
print(n, end=' ')
# Print the Newline character after the end of the inner loop.
print()
Output:
Enter some random number of rows = 6 1 2 1 3 2 1 4 3 2 1 5 4 3 2 1
2) C++ Implementation
Give the number of rows as user input using cin and store it in a variable.
Below is the implementation:
#include <iostream>
using namespace std;
int main()
{
// Give the number of rows as user input using
// cin and store it in a variable.
int numbrrows;
cin >> numbrrows;
// Loop from 1 to the number of rows using For loop.
for (int m = 1; m < numbrrows; m++) {
// Loop from the parent loop iterator value to 0 in
// decreasing order using another For loop(Nested
// For Loop).
for (int n = m; n > 0; n--) {
// Print the iterator value of the inner for
// loop.
cout << n << " ";
}
// Print the Newline character after the end of the
// inner loop.
cout << endl;
}
return 0;
}
Output:
6 1 2 1 3 2 1 4 3 2 1 5 4 3 2 1
3) C Implementation
Give the number of rows as user input using scanf and store it in a variable.
Below is the implementation:
#include <stdio.h>
int main()
{
// Give the number of rows as user input using scanf and
// store it in a variable.
int numbrrows;
scanf("%d", &numbrrows);
// Loop from 1 to the number of rows using For loop.
for (int m = 1; m < numbrrows; m++) {
// Loop from the parent loop iterator value to 0 in
// decreasing order using another For loop(Nested
// For Loop).
for (int n = m; n > 0; n--) {
// Print the iterator value of the inner for
// loop.
printf("%d ", n);
}
// Print the Newline character after the end of the
// inner loop.
printf("\n");
}
return 0;
}
Output:
6 1 2 1 3 2 1 4 3 2 1 5 4 3 2 1
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