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Given the number of rows and number of columns of the box, the task is to print the Hollow Box Number pattern in C, C++, and python.
Examples:
Example1:
Input:
given number of rows of the box =11 given number of columns of the box =19
Output:
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
Example2:
Input:
given number of rows of the box =11 given number of columns of the box =19 given character to print ='&'
Output:
& & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & &
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Program to Print Hollow Box Number Pattern in C, C++, and Python
Below are the ways to Print Hollow Box Number Pattern in C, C++, and python.
Method #1: Using For Loop (Static Character)
Approach:
- Give the number of rows and number of columns of the box as static or user input and store them in two separate variables.
- Loop from 1 to the number of rows of the box +1 using a For loop.
- Loop from 1 to the number of columns of the box +1 using another Nested For loop.
- Check if the parent iterator value is equal to 1 or the number of rows of the box using the If statement.
- Check if the inner loop iterator value is equal to 1 or the number of columns of the box using the If statement.
- Merge these two conditions in a single If statement using or operator.
- If the condition is true then print 1 with a space character.
- Else print space character.
- Print the newline character after the end of the inner For loop.
- The Exit of the Program.
1) Python Implementation
Below is the implementation:
# Give the number of rows and number of columns of the box as static or user input
# and store them in two separate variables.
boxrows = 11
boxcolumns = 19
# Loop from 1 to the number of rows of the box +1 using a For loop.
for m in range(1, boxrows+1):
# Loop from 1 to the number of columns of the box +1 using another Nested For loop.
for n in range(1, boxcolumns+1):
'''Check if the parent iterator value is equal to 1 or the number of rows of the box using the If statement.
Check if the inner loop iterator value is equal to 1 or the number of columns of the box using the If statement.
Merge these two conditions in a single If statement using or operator.
'''
if(m == 1 or m == boxrows or n == 1 or n == boxcolumns):
# If the condition is true then print 1 with a space character.
print("1", end=" ")
else:
# Else print space character.
print(" ", end=" ")
# Print the newline character after the end of the inner For loop.
print()
Output:
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
2) C++ Implementation
Below is the implementation:
#include <iostream>
using namespace std;
int main()
{
// Give the number of rows and number of columns of the
// box as static or user input and store them in two
// separate variables.
int boxrows = 11;
int boxcolumns = 19;
// Loop from 1 to the number of rows of the box +1 using
// a For loop.
for (int m = 1; m <= boxrows; m++) {
// Loop from 1 to the number of columns of the box
// +1 using another Nested For loop.
for (int n = 1; n <= boxcolumns; n++) {
/*Check if the parent iterator value is equal to
1 or the number of rows of the box using the
If statement. Check if the inner loop
iterator value is equal to 1 or the number of
columns of the box using the If statement.
Merge these two conditions in a single If
statement using or operator. */
if (m == 1 || m == boxrows || n == 1
|| n == boxcolumns) {
// If the condition is true then print 1
// with a space character.
cout << "1 ";
}
else {
// Else print space character.
cout << " ";
}
}
// Print the newline character after the end of the
// inner For loop.
cout << endl;
}
return 0;
}
Output:
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
3) C Implementation
Below is the implementation:
#include <stdio.h>
int main()
{
// Give the number of rows and number of columns of the
// box as static or user input and store them in two
// separate variables.
int boxrows = 11;
int boxcolumns = 19;
// Loop from 1 to the number of rows of the box +1 using
// a For loop.
for (int m = 1; m <= boxrows; m++) {
// Loop from 1 to the number of columns of the box
// +1 using another Nested For loop.
for (int n = 1; n <= boxcolumns; n++) {
/*Check if the parent iterator value is equal to
1 or the number of rows of the box using the
If statement. Check if the inner loop
iterator value is equal to 1 or the number of
columns of the box using the If statement.
Merge these two conditions in a single If
statement using or operator. */
if (m == 1 || m == boxrows || n == 1
|| n == boxcolumns) {
// If the condition is true then print 1
// with a space character.
printf("1 ");
}
else {
// Else print space character.
printf(" ");
}
}
// Print the newline character after the end of the
// inner For loop.
printf("\n");
}
return 0;
}
Output:
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
Method #2: Using For Loop (User Character)
Approach:
- Give the number of rows and number of columns of the box as user input and store them in two separate variables.
- Give the character to print as a box pattern as user input and store it in a variable.
- Loop from 1 to the number of rows of the box +1 using a For loop.
- Loop from 1 to the number of columns of the box +1 using another Nested For loop.
- Check if the parent iterator value is equal to 1 or the number of rows of the box using the If statement.
- Check if the inner loop iterator value is equal to 1 or the number of columns of the box using the If statement.
- Merge these two conditions in a single If statement using or operator.
- If the condition is true then print the given character with a space character.
- Else print space character.
- Print the newline character after the end of the inner For loop.
- The Exit of the Program.
1) Python Implementation
- Give the number of rows of the box as user input using int(input()) and store it in a variable.
- Give the number of columns of the box as user input using int(input()) and store it in another variable.
- Give the Character as user input using input() and store it in another variable.
Below is the implementation:
# Give the number of rows and number of columns of the box as user input and store them in two separate variables.
boxrows = int(input("Enter some random number of rows of the box = "))
boxcolumns = int(input("Enter some random number of columns of the box = "))
# Give the character to print as a box pattern as user input and store it in a variable.
userchar = input('Enter some random character to print = ')
# Loop from 1 to the number of rows of the box +1 using a For loop.
for m in range(1, boxrows+1):
# Loop from 1 to the number of columns of the box +1 using another Nested For loop.
for n in range(1, boxcolumns+1):
'''Check if the parent iterator value is equal to 1 or the number of rows of the box using the If statement.
Check if the inner loop iterator value is equal to 1 or the number of columns of the box using the If statement.
Merge these two conditions in a single If statement using or operator.
'''
if(m == 1 or m == boxrows or n == 1 or n == boxcolumns):
# If the condition is true then print the given character with a space character.
print(userchar, end=" ")
else:
# Else print space character.
print(" ", end=" ")
# Print the newline character after the end of the inner For loop.
print()
Output:
Enter some random number of rows of the box = 9 Enter some random number of columns of the box = 13 Enter some random character to print = & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & &
2) C++ Implementation
- Give the number of rows of the box as user input using cin and store it in a variable.
- Give the number of columns of the box as user input using cin and store it in another variable.
- Give the Character as user input using cin and store it in another variable.
Below is the implementation:
#include <iostream>
using namespace std;
int main()
{
// Give the number of rows of the box as user input
// using cin and store it in a variable.
// Give the number of columns of the box as user input
// using cin and store it in another variable.
int boxrows;
int boxcolumns;
cin >> boxrows;
cin >> boxcolumns;
// Give the Character as user input using cin and store
// it in another variable.
char userchar;
cin >> userchar;
cout << endl;
// Loop from 1 to the number of rows of the box +1 using
// a For loop.
for (int m = 1; m <= boxrows; m++) {
// Loop from 1 to the number of columns of the box
// +1 using another Nested For loop.
for (int n = 1; n <= boxcolumns; n++) {
/*Check if the parent iterator value is equal to
1 or the number of rows of the box using the
If statement. Check if the inner loop
iterator value is equal to 1 or the number of
columns of the box using the If statement.
Merge these two conditions in a single If
statement using or operator. */
if (m == 1 || m == boxrows || n == 1
|| n == boxcolumns) {
// If the condition is true then print user
// character with a space character.
cout << userchar << " ";
}
else {
// Else print space character.
cout << " ";
}
}
// Print the newline character after the end of the
// inner For loop.
cout << endl;
}
return 0;
}
Output:
Enter some random number of rows of the box = 9 Enter some random number of columns of the box = 13 Enter some random character to print = & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & &
3) C Implementation
- Give the number of rows of the box as user input using scanf and store it in a variable.
- Give the number of columns of the box as user input using scanf and store it in another variable.
- Give the Character as user input using scanf and store it in another variable.
Below is the implementation:
#include <stdio.h>
int main()
{
// Give the number of rows of the box as user input
// using scanf and store it in a variable.
// Give the number of columns of the box as user input
// using scanf and store it in another variable.
int boxrows;
int boxcolumns;
// Give the Character as user input using cin and store
// it in another variable.
char userchar;
scanf("%d%d%c",&boxrows,&boxcolumns,&userchar);
printf("\n");
// Loop from 1 to the number of rows of the box +1 using
// a For loop.
for (int m = 1; m <= boxrows; m++) {
// Loop from 1 to the number of columns of the box
// +1 using another Nested For loop.
for (int n = 1; n <= boxcolumns; n++) {
/*Check if the parent iterator value is equal to
1 or the number of rows of the box using the
If statement. Check if the inner loop
iterator value is equal to 1 or the number of
columns of the box using the If statement.
Merge these two conditions in a single If
statement using or operator. */
if (m == 1 || m == boxrows || n == 1
|| n == boxcolumns) {
// If the condition is true then print user
// character with a space character.
printf("%c ", userchar);
}
else {
// Else print space character.
printf(" ");
}
}
// Print the newline character after the end of the
// inner For loop.
printf("\n");
}
return 0;
}
Output:
Enter some random number of rows of the box = 9 Enter some random number of columns of the box = 13 Enter some random character to print = & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & &
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