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Given the number of rows, the task is to print Exponentially Increasing Star Pattern in C, C++, and Python
Examples:
Example1:
Input:
given number of rows =5
Output:
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
Example2:
Input:
given number of rows =4 given character to print =@
Output:
@ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @
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Program to Print Exponentially Increasing Star Pattern in C, C++, and Python
Below are the ways to print Exponentially Increasing Star Pattern in C, C++, and python.
Method #1: Using For loop (Star Character)
Approach:
- Give the number of rows of the pattern as static input and store it in a variable.
- Loop till a given number of rows using For loop.
- Calculate the exponential value of the first loop iterator value using 2**(iterator value of the first loop).
- Loop till the exponential value using another For loop(Nested For loop).
- Print the star character in the inner for loop.
- Print the newline character after the end of the inner for loop.
- The Exit of the Program.
1) Python Implementation
Below is the implementation:
# Give the number of rows of the pattern as static input and store it in a variable.
rowsnumb = 5
# Loop till a given number of rows using For loop.
for m in range(rowsnumb+1):
# Calculate the exponential value of the first loop iterator
# value using 2**(iterator value of the first loop).
expvalue = 2**m
# Loop till the exponential value using another For loop(Nested For loop).
for n in range(expvalue):
# Print the star character in the inner for loop.
print("*", end=" ")
# Print the newline character after the end of the inner for loop.
print()
Output:
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
2) C++ Implementation
Below is the implementation:
#include <iostream>
#include <math.h>
using namespace std;
int main()
{
// Give the number of rows of the pattern as static
// input and store it in a variable.
int rowsnumb = 5;
// Loop till a given number of rows using For loop.
for (int m = 0; m <= rowsnumb; m++) {
// Calculate the exponential value of the first loop
// iterator value using 2**(iterator value of the
// first loop).
int expvalue = pow(2, m);
// Loop till the exponential value using another For
// loop(Nested For loop).
for (int n = 1; n <= expvalue; n++) {
// Print the star character in the inner for
// loop.
cout << "* ";
}
// Print the newline character after the end of the
// inner for loop.
cout << endl;
}
return 0;
}
Output:
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
3) C Implementation
Below is the implementation:
#include <math.h>
#include <stdio.h>
int main()
{
// Give the number of rows of the pattern as static
// input and store it in a variable.
int rowsnumb = 5;
// Loop till a given number of rows using For loop.
for (int m = 0; m <= rowsnumb; m++) {
// Calculate the exponential value of the first loop
// iterator value using 2**(iterator value of the
// first loop).
int expvalue = pow(2, m);
// Loop till the exponential value using another For
// loop(Nested For loop).
for (int n = 1; n <= expvalue; n++) {
// Print the star character in the inner for
// loop.
printf("* ");
}
// Print the newline character after the end of the
// inner for loop.
printf("\n");
}
return 0;
}
Output:
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
Method #2: Using For loop (User Character)
Approach:
- Give the number of rows of the pattern as user input and store it in a variable.
- Give the character to print as user input and store it in a variable.
- Loop till a given number of rows using For loop.
- Calculate the exponential value of the first loop iterator value using 2**(iterator value of the first loop).
- Loop till the exponential value using another For loop(Nested For loop).
- Print the user character in the inner for loop.
- Print the newline character after the end of the inner for loop.
- The Exit of the Program.
1) Python Implementation
- Give the number of rows using int(input()) and store it in a variable.
- Give the Character as user input using input() and store it in another variable.
Below is the implementation:
# Give the number of rows using int(input()) and store it in a variable.
rowsnumb = int(input('Enter some random number of rows = '))
# Give the Character as user input using input() and store it in another variable.
usercharact = input('Enter some random character to print = ')
for m in range(rowsnumb+1):
# Calculate the exponential value of the first loop iterator
# value using 2**(iterator value of the first loop).
expvalue = 2**m
# Loop till the exponential value using another For loop(Nested For loop).
for n in range(expvalue):
# Print the user character in the inner for loop.
print(usercharact, end=" ")
# Print the newline character after the end of the inner for loop.
print()
Output:
Enter some random number of rows = 4 Enter some random character to print = @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @
2) C++ Implementation
- Give the number of rows using cin and store it in a variable.
- Give the Character as user input using cin and store it in another variable.
Below is the implementation:
#include <iostream>
#include <math.h>
using namespace std;
int main()
{
// Give the number of rows of the pattern as user input
// and store it in a variable.
int rowsnumb;
cin >> rowsnumb;
// Give the character to print as user input and store
// it in a variable.
char usercharact;
cin >> usercharact;
cout<<endl;
// Loop till a given number of rows using For loop.
for (int m = 0; m <= rowsnumb; m++) {
// Calculate the exponential value of the first loop
// iterator value using 2**(iterator value of the
// first loop).
int expvalue = pow(2, m);
// Loop till the exponential value using another For
// loop(Nested For loop).
for (int n = 1; n <= expvalue; n++) {
// Print the user character in the inner for
// loop.
cout << usercharact << " ";
}
// Print the newline character after the end of the
// inner for loop.
cout << endl;
}
return 0;
}
Output:
Enter some random number of rows = 4 Enter some random character to print = @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @
3) C Implementation
- Give the number of rows using scanf and store it in a variable.
- Give the Character as user input using scanf and store it in another variable.
Below is the implementation:
#include <math.h>
#include <stdio.h>
int main()
{ // Give the number of rows of the pattern as user input
// and store it in a variable.
int rowsnumb;
scanf("%d", &rowsnumb);
// Give the character to print as user input and store
// it in a variable.
char usercharact;
scanf("%c", &usercharact);
// Loop till a given number of rows using For loop.
for (int m = 0; m <= rowsnumb; m++) {
// Calculate the exponential value of the first loop
// iterator value using 2**(iterator value of the
// first loop).
int expvalue = pow(2, m);
// Loop till the exponential value using another For
// loop(Nested For loop).
for (int n = 1; n <= expvalue; n++) {
// Print the user character in the inner for
// loop.
printf("%c ", usercharact);
}
// Print the newline character after the end of the
// inner for loop.
printf("\n");
}
return 0;
}
Output:
@ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @
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