Python Program to Print Exponentially Increasing Star Pattern

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Given the number of rows, the task is to print Exponentially Increasing Star Pattern in C, C++, and Python

Examples:

Example1:

Input:

given number of rows =5

Output:

* 
* * 
* * * * 
* * * * * * * * 
* * * * * * * * * * * * * * * * 
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *

Example2:

Input:

given number of rows =4
given character to print =@

Output:

@ 
@ @ 
@ @ @ @ 
@ @ @ @ @ @ @ @ 
@ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @

Program to Print Exponentially Increasing Star Pattern in C, C++, and Python

Below are the ways to print Exponentially Increasing Star Pattern in C, C++, and python.

Method #1: Using For loop (Star Character)

Approach:

  • Give the number of rows of the pattern as static input and store it in a variable.
  • Loop till a given number of rows using For loop.
  • Calculate the exponential value of the first loop iterator value using 2**(iterator value of the first loop).
  • Loop till the exponential value using another For loop(Nested For loop).
  • Print the star character in the inner for loop.
  • Print the newline character after the end of the inner for loop.
  • The Exit of the Program.

1) Python Implementation

Below is the implementation:

# Give the number of rows of the pattern as static input and store it in a variable.
rowsnumb = 5
# Loop till a given number of rows using For loop.
for m in range(rowsnumb+1):
  # Calculate the exponential value of the first loop iterator
  # value using 2**(iterator value of the first loop).
    expvalue = 2**m
    # Loop till the exponential value using another For loop(Nested For loop).
    for n in range(expvalue):
      # Print the star character in the inner for loop.
        print("*", end=" ")
    # Print the newline character after the end of the inner for loop.
    print()

Output:

* 
* * 
* * * * 
* * * * * * * * 
* * * * * * * * * * * * * * * * 
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *

2) C++ Implementation

Below is the implementation:

#include <iostream>
#include <math.h>
using namespace std;

int main()
{
    // Give the number of rows of the pattern as static
    // input and store it in a variable.
    int rowsnumb = 5;
    // Loop till a given number of rows using For loop.
    for (int m = 0; m <= rowsnumb; m++) {
        // Calculate the exponential value of the first loop
        // iterator value using 2**(iterator value of the
        // first loop).
        int expvalue = pow(2, m);
        // Loop till the exponential value using another For
        // loop(Nested For loop).
        for (int n = 1; n <= expvalue; n++) {
            // Print the star character in the inner for
            // loop.
            cout << "* ";
        }
        // Print the newline character after the end of the
        // inner for loop.
        cout << endl;
    }

    return 0;
}

Output:

* 
* * 
* * * * 
* * * * * * * * 
* * * * * * * * * * * * * * * * 
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *

3) C Implementation

Below is the implementation:

#include <math.h>
#include <stdio.h>
int main()
{
    // Give the number of rows of the pattern as static
    // input and store it in a variable.
    int rowsnumb = 5;
    // Loop till a given number of rows using For loop.
    for (int m = 0; m <= rowsnumb; m++) {
        // Calculate the exponential value of the first loop
        // iterator value using 2**(iterator value of the
        // first loop).
        int expvalue = pow(2, m);
        // Loop till the exponential value using another For
        // loop(Nested For loop).
        for (int n = 1; n <= expvalue; n++) {
            // Print the star character in the inner for
            // loop.
            printf("* ");
        }
        // Print the newline character after the end of the
        // inner for loop.
        printf("\n");
    }

    return 0;
}

Output:

* 
* * 
* * * * 
* * * * * * * * 
* * * * * * * * * * * * * * * * 
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *

Method #2: Using For loop (User Character)

Approach:

  • Give the number of rows of the pattern as user input and store it in a variable.
  • Give the character to print as user input and store it in a variable.
  • Loop till a given number of rows using For loop.
  • Calculate the exponential value of the first loop iterator value using 2**(iterator value of the first loop).
  • Loop till the exponential value using another For loop(Nested For loop).
  • Print the user character in the inner for loop.
  • Print the newline character after the end of the inner for loop.
  • The Exit of the Program.

1) Python Implementation

  • Give the number of rows using int(input()) and store it in a variable.
  • Give the Character as user input using input() and store it in another variable.

Below is the implementation:

# Give the number of rows using int(input()) and store it in a variable.
rowsnumb = int(input('Enter some random number of rows = '))
# Give the Character as user input using input() and store it in another variable.
usercharact = input('Enter some random character to print = ')
for m in range(rowsnumb+1):
  # Calculate the exponential value of the first loop iterator
  # value using 2**(iterator value of the first loop).
    expvalue = 2**m
    # Loop till the exponential value using another For loop(Nested For loop).
    for n in range(expvalue):
      # Print the user character in the inner for loop.
        print(usercharact, end=" ")
    # Print the newline character after the end of the inner for loop.
    print()

Output:

Enter some random number of rows = 4
Enter some random character to print = @
@ 
@ @ 
@ @ @ @ 
@ @ @ @ @ @ @ @ 
@ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @

2) C++ Implementation

  • Give the number of rows using cin and store it in a variable.
  • Give the Character as user input using cin and store it in another variable.

Below is the implementation:

#include <iostream>
#include <math.h>
using namespace std;

int main()
{
    // Give the number of rows of the pattern as user input
    // and store it in a variable.
    int rowsnumb;
    cin >> rowsnumb;
    // Give the character to print as user input and store
    // it in a variable.
    char usercharact;
    cin >> usercharact;
    cout<<endl;
    // Loop till a given number of rows using For loop.
    for (int m = 0; m <= rowsnumb; m++) {
        // Calculate the exponential value of the first loop
        // iterator value using 2**(iterator value of the
        // first loop).
        int expvalue = pow(2, m);
        // Loop till the exponential value using another For
        // loop(Nested For loop).
        for (int n = 1; n <= expvalue; n++) {
            // Print the user character in the inner for
            // loop.
            cout << usercharact << " ";
        }
        // Print the newline character after the end of the
        // inner for loop.
        cout << endl;
    }

    return 0;
}

Output:

Enter some random number of rows = 4
Enter some random character to print = @
@ 
@ @ 
@ @ @ @ 
@ @ @ @ @ @ @ @ 
@ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @

3) C Implementation

  • Give the number of rows using scanf and store it in a variable.
  • Give the Character as user input using scanf and store it in another variable.

Below is the implementation:

#include <math.h>
#include <stdio.h>
int main()
{ // Give the number of rows of the pattern as user input
    // and store it in a variable.
    int rowsnumb;
    scanf("%d", &rowsnumb);
    // Give the character to print as user input and store
    // it in a variable.
    char usercharact;
    scanf("%c", &usercharact);
    // Loop till a given number of rows using For loop.
    for (int m = 0; m <= rowsnumb; m++) {
        // Calculate the exponential value of the first loop
        // iterator value using 2**(iterator value of the
        // first loop).
        int expvalue = pow(2, m);
        // Loop till the exponential value using another For
        // loop(Nested For loop).
        for (int n = 1; n <= expvalue; n++) {
            // Print the user character in the inner for
            // loop.
            printf("%c ", usercharact);
        }
        // Print the newline character after the end of the
        // inner for loop.
        printf("\n");
    }

    return 0;
}

Output:

@ 
@ @ 
@ @ @ @ 
@ @ @ @ @ @ @ @ 
@ @ @ @ @ @ @ @ @ @ @ @ @ @ @ @

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