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Given the number of rows, the task is to Print a Unique Pyramid Pattern of Digits in C, C++, and Python
Examples:
Example1:
Input:
Given number of rows = 8
Output:
1 1 2 1 1 2 3 2 1 1 2 3 4 3 2 1 1 2 3 4 5 4 3 2 1 1 2 3 4 5 6 5 4 3 2 1 1 2 3 4 5 6 7 6 5 4 3 2 1
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Example2:
Input:
Given number of rows = 7
Output:
1 1 2 1 1 2 3 2 1 1 2 3 4 3 2 1 1 2 3 4 5 4 3 2 1 1 2 3 4 5 6 5 4 3 2 1
Program to Print a Unique Pyramid Pattern of Digits in C, C++, and Python
Below are the ways to Print a Unique Pyramid Pattern of Digits in C, C++, and Python
Method #1: Using For Loop (Static Input)
Approach:
- Give the number of rows as static input and store it in a variable.
- Loop from 1 to the number of rows using For loop.
- Loop from 1 to m-1 using another For loop(Nested For loop) where m is the iterator value of the parent For loop.
- Print the inner loop iterator value with space.
- Loop from m-1 to 0 in decreasing order using another For loop(Nested For loop) where m is the iterator value of the parent For loop.
- Print the inner loop iterator value with space.
- Print the Newline character after the end of the inner loop.
- The Exit of the Program.
1) Python Implementation
Below is the implementation:
# Give the number of rows as static input and store it in a variable.
numberOfRows = 8
# Loop from 1 to the number of rows using For loop.
for m in range(1, numberOfRows + 1):
# Loop from 1 to m-1 using another For loop(Nested For loop)
# where m is the iterator value of the parent For loop.
for n in range(1, m - 1):
# Print the inner loop iterator value with space.
print(n, end=" ")
# Loop from m-1 to 0 in decreasing order using another For loop(Nested For loop)
# where m is the iterator value of the parent For loop.
for n in range(m - 1, 0, -1):
# Print the inner loop iterator value with space.
print(n, end=" ")
# Print the Newline character after the end of the inner loop.
print()
Output:
1 1 2 1 1 2 3 2 1 1 2 3 4 3 2 1 1 2 3 4 5 4 3 2 1 1 2 3 4 5 6 5 4 3 2 1 1 2 3 4 5 6 7 6 5 4 3 2 1
2) C++ Implementation
Below is the implementation:
#include <iostream>
#include <math.h>
using namespace std;
int main()
{
// Give the number of rows as static input and store it
// in a variable.
int numberOfRows = 8;
// Loop from 1 to the number of rows using For loop.
for (int m = 1; m <= numberOfRows; m++) {
// Loop from 1 to m-1 using another For loop(Nested
// For loop)
// where m is the iterator value of the parent For
// loop.
for (int n = 1; n < m - 1; n++) {
// Print the inner loop iterator value with
// space.
cout << n << " ";
}
// Loop from m-1 to 0 in decreasing order using
// another For loop(Nested For loop) where m is the
// iterator value of the parent For loop.
for (int n = m - 1; n > 0; n--) {
// Print the inner loop iterator value with
// space.
cout << n << " ";
}
// Print the Newline character after the end of the
// inner loop.
cout << endl;
}
return 0;
}
Output:
1 1 2 1 1 2 3 2 1 1 2 3 4 3 2 1 1 2 3 4 5 4 3 2 1 1 2 3 4 5 6 5 4 3 2 1 1 2 3 4 5 6 7 6 5 4 3 2 1
3) C Implementation
Below is the implementation:
#include <stdio.h>
int main()
{
// Give the number of rows as static input and store it
// in a variable.
int numberOfRows = 7;
// Loop from 1 to the number of rows using For loop.
for (int m = 1; m <= numberOfRows; m++) {
// Loop from 1 to m-1 using another For loop(Nested
// For loop) where m is the iterator value of the
// parent For loop.
for (int n = 1; n < m - 1; n++) {
// Print the inner loop iterator value with
// space.
printf("%d ", n);
}
// Loop from m-1 to 0 in decreasing order using
// another For loop(Nested For loop) where m is the
// iterator value of the parent For loop.
for (int n = m - 1; n > 0; n--) {
// Print the inner loop iterator value with
// space.
printf("%d ", n);
}
// Print the Newline character after the end of the
// inner loop.
printf("\n");
}
return 0;
}
Output:
1 1 2 1 1 2 3 2 1 1 2 3 4 3 2 1 1 2 3 4 5 4 3 2 1 1 2 3 4 5 6 5 4 3 2 1
Method #2: Using For Loop (User Input)
Approach:
- Give the number of rows as user input and store it in a variable.
- Loop from 1 to the number of rows using For loop.
- Loop from 1 to m-1 using another For loop(Nested For loop) where m is the iterator value of the parent For loop.
- Print the inner loop iterator value with space.
- Loop from m-1 to 0 in decreasing order using another For loop(Nested For loop) where m is the iterator value of the parent For loop.
- Print the inner loop iterator value with space.
- Print the Newline character after the end of the inner loop.
- The Exit of the Program.
1) Python Implementation
Give the number of rows as user input using int(input()) and store it in a variable.
Below is the implementation:
# Give the number of rows as user input using int(input()) and store it in a variable.
numberOfRows = int(input('Enter some random number of rows = '))
# Loop from 1 to the number of rows using For loop.
for m in range(1, numberOfRows + 1):
# Loop from 1 to m-1 using another For loop(Nested For loop)
# where m is the iterator value of the parent For loop.
for n in range(1, m - 1):
# Print the inner loop iterator value with space.
print(n, end=" ")
# Loop from m-1 to 0 in decreasing order using another For loop(Nested For loop)
# where m is the iterator value of the parent For loop.
for n in range(m - 1, 0, -1):
# Print the inner loop iterator value with space.
print(n, end=" ")
# Print the Newline character after the end of the inner loop.
print()
Output:
Enter some random number of rows = 17 1 1 2 1 1 2 3 2 1 1 2 3 4 3 2 1 1 2 3 4 5 4 3 2 1 1 2 3 4 5 6 5 4 3 2 1 1 2 3 4 5 6 7 6 5 4 3 2 1 1 2 3 4 5 6 7 8 7 6 5 4 3 2 1 1 2 3 4 5 6 7 8 9 8 7 6 5 4 3 2 1 1 2 3 4 5 6 7 8 9 10 9 8 7 6 5 4 3 2 1 1 2 3 4 5 6 7 8 9 10 11 10 9 8 7 6 5 4 3 2 1 1 2 3 4 5 6 7 8 9 10 11 12 11 10 9 8 7 6 5 4 3 2 1 1 2 3 4 5 6 7 8 9 10 11 12 13 12 11 10 9 8 7 6 5 4 3 2 1 1 2 3 4 5 6 7 8 9 10 11 12 13 14 13 12 11 10 9 8 7 6 5 4 3 2 1 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1
2) C++ Implementation
Give the number of rows as user input using cin and store it in a variable.
Below is the implementation:
#include <iostream>
#include <math.h>
using namespace std;
int main()
{
// Give the number of rows as user input using
// int(input()) and store it in a variable.
int numberOfRows;
cin >> numberOfRows;
// Loop from 1 to the number of rows using For loop.
for (int m = 1; m <= numberOfRows; m++) {
// Loop from 1 to m-1 using another For loop(Nested
// For loop)
// where m is the iterator value of the parent For
// loop.
for (int n = 1; n < m - 1; n++) {
// Print the inner loop iterator value with
// space.
cout << n << " ";
}
// Loop from m-1 to 0 in decreasing order using
// another For loop(Nested For loop) where m is the
// iterator value of the parent For loop.
for (int n = m - 1; n > 0; n--) {
// Print the inner loop iterator value with
// space.
cout << n << " ";
}
// Print the Newline character after the end of the
// inner loop.
cout << endl;
}
return 0;
}
Output:
5 1 1 2 1 1 2 3 2 1 1 2 3 4 3 2 1
3) C Implementation
Give the number of rows as user input using scanf and store it in a variable.
Below is the implementation:
#include <stdio.h>
int main()
{
// Give the number of rows as user input using scanf and
// store it in a variable.
int numberOfRows;
scanf("%d", &numberOfRows);
// Loop from 1 to the number of rows using For loop.
for (int m = 1; m <= numberOfRows; m++) {
// Loop from 1 to m-1 using another For loop(Nested
// For loop) where m is the iterator value of the
// parent For loop.
for (int n = 1; n < m - 1; n++) {
// Print the inner loop iterator value with
// space.
printf("%d ", n);
}
// Loop from m-1 to 0 in decreasing order using
// another For loop(Nested For loop) where m is the
// iterator value of the parent For loop.
for (int n = m - 1; n > 0; n--) {
// Print the inner loop iterator value with
// space.
printf("%d ", n);
}
// Print the Newline character after the end of the
// inner loop.
printf("\n");
}
return 0;
}
Output:
6 1 1 2 1 1 2 3 2 1 1 2 3 4 3 2 1 1 2 3 4 5 4 3 2 1
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