Python Program to Find the Type of Triangle with Given Sides

Python Program to Find the Type of Triangle with Given Sides

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Given the sides of the triangle, the task is to find the type of triangle with the given sides i.e print the type of triangle acute-angled, obtuse-angled, or right-angled Triangle.

Examples:

Example1:

Input:

Given first side =11
Given second side =6
Given third side =7

Output:

The Triangle with given sides 11 6 7 is Obtuse-angled triangle

Example2:

Input:

Given first side =8
Given second side =6
Given third side =10

Output:

The Triangle with given sides 8 6 10 is Right-angled triangle

Python Program to Find the Type of Triangle with Given Sides

Below are the ways to Find the Type of Triangle with Given Sides in Python.

If c² = a² + b², then the triangle is right-angled.

If c² < a² + b², the triangle is an acute-angle triangle.

If c² > a² + b², the triangle has an obtuse angle.

Method #1:Using If  Else Statement (Static Input)

Approach:

  • Give the three sides of the triangle as static input and store them in three separate variables.
  • Calculate the square of each side of the triangle using the ** operator and store them in three separate variables (squareside1,squareside2,squareside3).
  • Check if squareside1== squareside3+ squareside2, squareside2== squareside1+squareside3,or squareside3== squareside1+squareside2.
  • If it is true then print it as a Right-angled triangle.
  • Print Obtuse-angled triangle if squareside1 > squareside3+ squareside2, squareside2 > squareside1+squareside3, or squareside3 > squareside1+squareside2.
  • Else Print Acute-angled triangle.
  • The Exit of the Program.

Below is the Implementation:

# Give the three sides of the triangle as static input and store them in three separate variables.
side1 = 11
side2 = 6
side3 = 7
# Calculate the square of each side of the triangle using the ** operator and
# store them in three separate variables (squareside1,squareside2,squareside3).
squareside1 = side1**2
squareside2 = side2**2
squareside3 = side3**2
# Check if squareside1== squareside3+ squareside2,
# squareside2== squareside1+squareside3,or squareside3== squareside1+squareside2.
if(squareside1 == (squareside3 + squareside2) or squareside2 == (squareside1+squareside3) or squareside3 == (squareside1+squareside2)):
    # If it is true then print it as a Right-angled triangle.
    print('The Triangle with given sides', side1,
          side2, side3, 'is Right-angled triangle ')
# Print Obtuse-angled triangle if squareside1 > squareside3+ squareside2, squareside2 > squareside1+squareside3, or squareside3 > squareside1+squareside2.
elif(squareside1 > (squareside3 + squareside2) or squareside2 > (squareside1+squareside3) or squareside3 > (squareside1+squareside2)):
    print('The Triangle with given sides', side1,
          side2, side3, 'is Obtuse-angled triangle ')
else:
    # Else Print Acute-angled triangle.
    print('The Triangle with given sides', side1,
          side2, side3, 'is Acute-angled triangle ')

Output:

The Triangle with given sides 11 6 7 is Obtuse-angled triangle

Method #2:Using If  Else Statement (User Input)

Approach:

  • Give the three sides of the triangle as user input using map(),int() and split() functions.
  • Store them in three separate variables.
  • Calculate the square of each side of the triangle using the ** operator and store them in three separate variables (squareside1,squareside2,squareside3).
  • Check if squareside1== squareside3+ squareside2, squareside2== squareside1+squareside3,or squareside3== squareside1+squareside2.
  • If it is true then print it as a Right-angled triangle.
  • Print Obtuse-angled triangle if squareside1 > squareside3+ squareside2, squareside2 > squareside1+squareside3, or squareside3 > squareside1+squareside2.
  • Else Print Acute-angled triangle.
  • The Exit of the Program.

Below is the Implementation:

# Give the three sides of the triangle as user input using map(),int() and split() functions.
side1, side2, side3 = map(int, input(
    'Enter some random three sides of the triangle ').split())
# Calculate the square of each side of the triangle using the ** operator and
# store them in three separate variables (squareside1,squareside2,squareside3).
squareside1 = side1**2
squareside2 = side2**2
squareside3 = side3**2
# Check if squareside1== squareside3+ squareside2,
# squareside2== squareside1+squareside3,or squareside3== squareside1+squareside2.
if(squareside1 == (squareside3 + squareside2) or squareside2 == (squareside1+squareside3) or squareside3 == (squareside1+squareside2)):
    # If it is true then print it as a Right-angled triangle.
    print('The Triangle with given sides', side1,
          side2, side3, 'is Right-angled triangle ')
# Print Obtuse-angled triangle if squareside1 > squareside3+ squareside2, squareside2 > squareside1+squareside3, or squareside3 > squareside1+squareside2.
elif(squareside1 > (squareside3 + squareside2) or squareside2 > (squareside1+squareside3) or squareside3 > (squareside1+squareside2)):
    print('The Triangle with given sides', side1,
          side2, side3, 'is Obtuse-angled triangle ')
else:
    # Else Print Acute-angled triangle.
    print('The Triangle with given sides', side1,
          side2, side3, 'is Acute-angled triangle ')

Output:

Enter some random three sides of the triangle 8 6 10
The Triangle with given sides 8 6 10 is Right-angled triangle

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