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Given the sides of the triangle, the task is to find the type of triangle with the given sides i.e print the type of triangle acute-angled, obtuse-angled, or right-angled Triangle.

**Examples:**

**Example1:**

**Input:**

Given first side =11 Given second side =6 Given third side =7

**Output:**

The Triangle with given sides 11 6 7 is Obtuse-angled triangle

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**Example2:**

**Input:**

Given first side =8 Given second side =6 Given third side =10

**Output:**

The Triangle with given sides 8 6 10 is Right-angled triangle

## Python Program to Find the Type of Triangle with Given Sides

Below are the ways to Find the Type of Triangle with Given Sides in Python.

If c² = a² + b², then the triangle is right-angled.

If c² < a² + b², the triangle is an acute-angle triangle.

If c² > a² + b², the triangle has an obtuse angle.

### Method #1:Using If Else Statement (Static Input)

**Approach:**

- Give the three sides of the triangle as static input and store them in three separate variables.
- Calculate the square of each side of the triangle using the ** operator and store them in three separate variables (squareside1,squareside2,squareside3).
- Check if squareside1== squareside3+ squareside2, squareside2== squareside1+squareside3,or squareside3== squareside1+squareside2.
- If it is true then print it as a Right-angled triangle.
- Print Obtuse-angled triangle if squareside1 > squareside3+ squareside2, squareside2 > squareside1+squareside3, or squareside3 > squareside1+squareside2.
- Else Print Acute-angled triangle.
- The Exit of the Program.

**Below is the Implementation:**

# Give the three sides of the triangle as static input and store them in three separate variables. side1 = 11 side2 = 6 side3 = 7 # Calculate the square of each side of the triangle using the ** operator and # store them in three separate variables (squareside1,squareside2,squareside3). squareside1 = side1**2 squareside2 = side2**2 squareside3 = side3**2 # Check if squareside1== squareside3+ squareside2, # squareside2== squareside1+squareside3,or squareside3== squareside1+squareside2. if(squareside1 == (squareside3 + squareside2) or squareside2 == (squareside1+squareside3) or squareside3 == (squareside1+squareside2)): # If it is true then print it as a Right-angled triangle. print('The Triangle with given sides', side1, side2, side3, 'is Right-angled triangle ') # Print Obtuse-angled triangle if squareside1 > squareside3+ squareside2, squareside2 > squareside1+squareside3, or squareside3 > squareside1+squareside2. elif(squareside1 > (squareside3 + squareside2) or squareside2 > (squareside1+squareside3) or squareside3 > (squareside1+squareside2)): print('The Triangle with given sides', side1, side2, side3, 'is Obtuse-angled triangle ') else: # Else Print Acute-angled triangle. print('The Triangle with given sides', side1, side2, side3, 'is Acute-angled triangle ')

**Output:**

The Triangle with given sides 11 6 7 is Obtuse-angled triangle

### Method #2:Using If Else Statement (User Input)

**Approach:**

- Give the three sides of the triangle as user input using map(),int() and split() functions.
- Store them in three separate variables.
- Calculate the square of each side of the triangle using the ** operator and store them in three separate variables (squareside1,squareside2,squareside3).
- Check if squareside1== squareside3+ squareside2, squareside2== squareside1+squareside3,or squareside3== squareside1+squareside2.
- If it is true then print it as a Right-angled triangle.
- Print Obtuse-angled triangle if squareside1 > squareside3+ squareside2, squareside2 > squareside1+squareside3, or squareside3 > squareside1+squareside2.
- Else Print Acute-angled triangle.
- The Exit of the Program.

**Below is the Implementation:**

# Give the three sides of the triangle as user input using map(),int() and split() functions. side1, side2, side3 = map(int, input( 'Enter some random three sides of the triangle ').split()) # Calculate the square of each side of the triangle using the ** operator and # store them in three separate variables (squareside1,squareside2,squareside3). squareside1 = side1**2 squareside2 = side2**2 squareside3 = side3**2 # Check if squareside1== squareside3+ squareside2, # squareside2== squareside1+squareside3,or squareside3== squareside1+squareside2. if(squareside1 == (squareside3 + squareside2) or squareside2 == (squareside1+squareside3) or squareside3 == (squareside1+squareside2)): # If it is true then print it as a Right-angled triangle. print('The Triangle with given sides', side1, side2, side3, 'is Right-angled triangle ') # Print Obtuse-angled triangle if squareside1 > squareside3+ squareside2, squareside2 > squareside1+squareside3, or squareside3 > squareside1+squareside2. elif(squareside1 > (squareside3 + squareside2) or squareside2 > (squareside1+squareside3) or squareside3 > (squareside1+squareside2)): print('The Triangle with given sides', side1, side2, side3, 'is Obtuse-angled triangle ') else: # Else Print Acute-angled triangle. print('The Triangle with given sides', side1, side2, side3, 'is Acute-angled triangle ')

**Output:**

Enter some random three sides of the triangle 8 6 10 The Triangle with given sides 8 6 10 is Right-angled triangle

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