Python Program to Count Number of Digits in a Text File

Files in Python:

One of the most important subjects for programmers and automation testers is Python file handling (also known as File I/O). It is necessary to work with files in order to write to or read data from them.

Also, if you didn’t know, I/O operations are the most expensive processes where a programme can go wrong. As a result, you must use extreme caution while implementing file processing for reporting or any other reason. Optimizing a single file action can help in the creation of a high-performing application or a reliable automated software testing solution.

Consider the following scenario: you’re planning to construct a large Python project with a large number of workflows. Then it’s unavoidable that you don’t make a log file. You’ll also be handling the log file’s read and write activities. Debugging huge applications with log files is a terrific way to go. It’s usually better to consider a scalable design from the start, as you won’t be sorry later if you didn’t.

Given a file, the task is to count the number of digits in a given file in Python.

Program to Count Number of Digits in a Text File in Python

Below is the full approach for counting the number of digits in a given file in Python.

Approach:

Make a single variable to store the path of the file. This is a constant value. This value must be replaced with the file path from your own system in the example below.
Pass the given filename, r (represents read-only) as arguments to the open() function to open the given file.
Read the above file using the read() function(get the content) and store it in a variable.
Take a variable(which gives the count of digits in a file) and initialize its value with zero.
Check if each character of the file text is digit or not using the isdigit() function and if conditional statement.
If it is true, then increment the value of the above-initialized variable(digit_cnt) by 1.
Print the count of the number of digits in a given file.
Close the above file.
The Exit of Program.

Below is the implementation:

# Make a single variable to store the path of the file. This is a constant value. 
# This value must be replaced with the file path from your own system in the example below.
givenFilename = "samplefile.txt"
# Pass the given filename, r (represents read only) as arguments to the open() function
# to open the given file
file = open(givenFilename,"r")
# Read the above file using the read() function(get the content) and store it in a variable
filetext = file.read()
# Take a variable(which gives the count of digits in a file) and initialize its value with zero.
digit_cnt = 0
# Iterate in the above text of the file using the for loop
for chr in filetext:
    # Check if each character of the file text is digit or not using the isdigit() function
    # and if conditional statement
    if chr.isdigit():
        # If it is true, then increment the value of the above initialized 
        # variable(digit_cnt) by 1
        digit_cnt += 1
# Print the count of number of digits in a given file
print("The count of number of digits in a given file = ",digit_cnt)
# Close the above file
file.close()

Output:

The count of number of digits in a given file = 6

File Content:

hello 123 this is 567 btechgeeks

Google Colab Images:

Files and Code:

samplefile.txt:

Program to Count Number of Digits in a Text File in Python

Related