# Python Program to Check Whether Sum of digits at Odd places of a Number is Divisible by K

In the previous article, we have discussed Python Program to Find Even Digits Sum and Odd Digits Sum Divisible by 4 and 3 Respectively
The task is to check if the sum of digits at odd places of a given number is divisible by the another given input number say K.

Examples:

Example1:

Input:

Given  Number = 24689131
Given  another Number (k) = 2

Output:

The sum of digits at odd places of the given number{ 24689131 } is divisible by the another given number k{ 2 }

Example2:

Input:

Given Number = 12573
Given another Number (k) = 5

Output:

The sum of digits at odd places of the given number{ 12573 } is not divisible by the another given number k{ 5 }

## Program to Check Whether Sum of digits at Odd places of a Number is Divisible by K in Python

Below are the ways to check if the sum of digits at odd places of a given number is divisible by the another given input number say K.

### Method #1: Using For Loop (Static Input)

Approach:

• Give the number as static input and store it in a variable.
• Give the other number k as static input and store it in another variable.
• Convert the given number to a string using the str() function and store it in another variable.
• Create a list of digits say “digtslst” using map(),list(),int functions.
• Store it in another variable.
• Take another variable say “od_sum” and initialize it with 0.
• Loop in the above list of digits until the length of the “digtslst” using the for loop.
• Check if the iterator value is odd or not using the if conditional statement.
• If the statement is true, then add the element of digits list at the iterator value to the “od_sum” and store it in the same variable od_sum.
• Check if the od_sum modulus given number k is equal to 0 or not using the if conditional statement.
• If the statement is true, then print “The sum of digits at odd places of the given number is divisible by the another given number k.
• If the statement is false, then print “The sum of digits at odd places of the given number is Not divisible by the another given number k.
• The Exit of the Program.

Below is the implementation:

# Give the number as static input and store it in a variable.
gvn_numb = 12573
# Give the other number k as static input and store it in another variable.
gvn_k = 5
# Convert the given number to a string using the str() function and store it in
# another variable.
stringnum = str(gvn_numb)
# Create a list of digits say "digtslst" using map(),list(),int functions.
digtslst = list(map(int, stringnum))
# Take a variable say "od_sum" and initialize it with 0.
od_sum = 0
# Loop in the above list of digits until the length of the "digtslst" using the for loop.
for itr in range(len(digtslst)):
# Check if the iterator value is odd or not using
# the if conditional statement.
if(itr % 2 != 0):
# If the statement is true, then add the element of digits list at iterator value to
# the "od_sum"  and store it in the same variable od_sum.
od_sum += digtslst[itr]
# Check if the od_sum modulus given number k is equal to 0 or not using the if conditional
# statement.
if(od_sum % gvn_k == 0):
# If the statement is true, then print "The sum of digits at odd places of the given
# number is divisible by the another given number k.
print("The sum of digits at odd places of the given number{", gvn_numb,
"} is divisible by the another given number k{", gvn_k, "}")
else:
# If the statement is false, then print "The sum of digits at odd places of the given
# number is Not divisible by the another given number k.
print("The sum of digits at odd places of the given number{", gvn_numb,
"} is not divisible by the another given number k{", gvn_k, "}")


Output:

The sum of digits at odd places of the given number{ 12573 } is not divisible by the another given number k{ 5 }

### Method #2: Using For loop (User Input)

Approach:

• Give the number as user input using the int(input()) function and store it in a variable.
• Give the other number k as user input using the int(input()) function and store it in another variable.
• Convert the given number to a string using the str() function and store it in another variable.
• Create a list of digits say “digtslst” using map(),list(),int functions.
• Store it in another variable.
• Take another variable say “od_sum” and initialize it with 0.
• Loop in the above list of digits until the length of the “digtslst” using the for loop.
• Check if the iterator value is odd or not using the if conditional statement.
• If the statement is true, then add the element of digits list at the iterator value to the “od_sum” and store it in the same variable od_sum.
• Check if the od_sum modulus given number k is equal to 0 or not using the if conditional statement.
• If the statement is true, then print “The sum of digits at odd places of the given number is divisible by the another given number k.
• If the statement is false, then print “The sum of digits at odd places of the given number is Not divisible by the another given number k.
• The Exit of the Program.

Below is the implementation:

# Give the number as user input using the int(input()) function and store it in a variable.
gvn_numb = int(input("Enter some random number = "))
#Give the other number k as user input using the int(input()) function and store it in another variable.
gvn_k = int(input("Enter some random number = "))
# Convert the given number to a string using the str() function and store it in
# another variable.
stringnum = str(gvn_numb)
# Create a list of digits say "digtslst" using map(),list(),int functions.
digtslst = list(map(int, stringnum))
# Take a variable say "od_sum" and initialize it with 0.
od_sum = 0
# Loop in the above list of digits until the length of the "digtslst" using the for loop.
for itr in range(len(digtslst)):
# Check if the iterator value is odd or not using
# the if conditional statement.
if(itr % 2 != 0):
# If the statement is true, then add the element of digits list at iterator value to
# the "od_sum"  and store it in the same variable od_sum.
od_sum += digtslst[itr]
# Check if the od_sum modulus given number k is equal to 0 or not using the if conditional
# statement.
if(od_sum % gvn_k == 0):
# If the statement is true, then print "The sum of digits at odd places of the given
# number is divisible by the another given number k.
print("The sum of digits at odd places of the given number{", gvn_numb,
"} is divisible by the another given number k{", gvn_k, "}")
else:
# If the statement is false, then print "The sum of digits at odd places of the given
# number is Not divisible by the another given number k.
print("The sum of digits at odd places of the given number{", gvn_numb,
"} is not divisible by the another given number k{", gvn_k, "}")


Output:

Enter some random number = 624351
Enter some random number = 3
The sum of digits at odd places of the given number{ 624351 } is divisible by the another given number k{ 3 }

Explore more instances related to python concepts from Python Programming Examples Guide and get promoted from beginner to professional programmer level in Python Programming Language.