In the previous article, we have discussed Python Program to Find XOR of Two Numbers Without Using XOR operator

Given a number, the task is to check if the given Number has the bits in an alternate pattern

For example, the number 42 has an alternate pattern, which is 101010 (after 1 we are getting 0 and next 1 so on).

If it has an alternate bit pattern, print “Yes,” else “No.”

**Examples:**

**Example1:**

**Input:**

Given Number= 42

**Output:**

Yes, the given number{ 42 } has an alternate bit pattern

**Example2:**

**Input:**

Given Number= 14

**Output:**

No, the given number{ 14 } doesn't have an alternate bit pattern

- Python Program to Print Alternate Numbers Pattern using While Loop
- Python Program to Find Position of Rightmost Set Bit
- Python Program to Print Series 0 2 6 12 20 30 42…N

## Program to Check if a Number has Bits in Alternate Pattern in Python

Below are the ways to check if a given number has bits in an alternate pattern in python:

### Method #1: Using While Loop (Static Input)

**Approach:**

- Give the number as static input and store it in a variable.
- Create a function to say
**chek_alterntebit**which takes the given number as an argument and returns true if it has an alternate bit pattern else returns False. - Apply given number modulus 2 to get the last bit and store it in a variable.
- Divide the given number by 2 and store it in the same variable gvn_numbr.
- Loop until the given number is greater than 0 using a while loop.
- Inside the loop, calculate the current bit by applying the given number modulus 2 and store it in another variable.
- Check if the current bit is equal to the last bit using the if conditional statement.
- If the statement is true, then return false.
- Assign the current bit to the last bit.
- Divide the given number by 2 and store it in the same variable gvn_numbr.
- Return True. (out of while loop)
- Pass the gvn_numbr as an argument to theĀ
**chek_alterntebit**() function and check whether it returns true or false using the if conditional statement. - If the statement is true, print “Yes, the given number has an alternate bit pattern”.
- Else print “No, the given number doesn’t have an alternate bit pattern”.
- The Exit of the Program.

**Below is the implementation:**

# Create a function to say chek_alterntebit which takes the given number as an # argument and returns true if it has an alternate bit pattern else returns False. def chek_alterntebit(gvn_numbr): # Apply given number modulus 2 to get the last bit and store it in a variable. lst_bit = gvn_numbr % 2 # Divide the given number by 2 and store it in the same variable gvn_numbr. gvn_numbr = gvn_numbr // 2 # Loop until the given number is greater than 0 using a while loop. while (gvn_numbr > 0): # Inside the loop, calculate the current bit by applying the given number modulus 2 # and store it in another variable. prsent_bit = gvn_numbr % 2 # Check if the current bit is equal to the last bit using the if conditional # statement. if (prsent_bit == lst_bit): # If the statement is true, then return false. return False # Assign the current bit to the last bit. lst_bit = prsent_bit # Divide the given number by 2 and store it in the same variable gvn_numbr. gvn_numbr = gvn_numbr // 2 # Return True. (out of while loop) return True # Give the number as static input and store it in a variable. gvn_numbr = 42 # Pass the given number as an argument to the chek_alterntebit function. # Check if the chek_alterntebit(gvn_numbr) using the if conditional statement. if(chek_alterntebit(gvn_numbr)): # If the statement is true, print "Yes, the given number has an alternate bit pattern". print("Yes, the given number{", gvn_numbr, "} has an alternate bit pattern") else: # Else print "No, the given number doesn't have an alternate bit pattern". print("No, the given number{", gvn_numbr, "} doesn't have an alternate bit pattern")

**Output:**

Yes, the given number{ 42 } has an alternate bit pattern

### Method #2: Using While loop (User Input)

**Approach:**

- Give the number as user input using the int(input()) function and store it in a variable.
- Create a function to say
**chek_alterntebit**which takes the given number as an argument and returns true if it has an alternate bit pattern else returns False. - Apply given number modulus 2 to get the last bit and store it in a variable.
- Divide the given number by 2 and store it in the same variable gvn_numbr.
- Loop until the given number is greater than 0 using a while loop.
- Inside the loop, calculate the current bit by applying the given number modulus 2 and store it in another variable.
- Check if the current bit is equal to the last bit using the if conditional statement.
- If the statement is true, then return false.
- Assign the current bit to the last bit.
- Divide the given number by 2 and store it in the same variable gvn_numbr.
- Return True. (out of while loop)
- Pass the gvn_numbr as an argument to theĀ
**chek_alterntebit**() function and check whether it returns true or false using the if conditional statement. - If the statement is true, print “Yes, the given number has an alternate bit pattern”.
- Else print “No, the given number doesn’t have an alternate bit pattern”.
- The Exit of the Program.

**Below is the implementation:**

# Create a function to say chek_alterntebit which takes the given number as an # argument and returns true if it has an alternate bit pattern else returns False. def chek_alterntebit(gvn_numbr): # Apply given number modulus 2 to get the last bit and store it in a variable. lst_bit = gvn_numbr % 2 # Divide the given number by 2 and store it in the same variable gvn_numbr. gvn_numbr = gvn_numbr // 2 # Loop until the given number is greater than 0 using a while loop. while (gvn_numbr > 0): # Inside the loop, calculate the current bit by applying the given number modulus 2 # and store it in another variable. prsent_bit = gvn_numbr % 2 # Check if the current bit is equal to the last bit using the if conditional # statement. if (prsent_bit == lst_bit): # If the statement is true, then return false. return False # Assign the current bit to the last bit. lst_bit = prsent_bit # Divide the given number by 2 and store it in the same variable gvn_numbr. gvn_numbr = gvn_numbr // 2 # Return True. (out of while loop) return True # Give the number as user input using the int(input()) function and store it in a variable. gvn_numbr = int(input('Enter some random number = ')) # Pass the given number as an argument to the chek_alterntebit function. # Check if the chek_alterntebit(gvn_numbr) using the if conditional statement. if(chek_alterntebit(gvn_numbr)): # If the statement is true, print "Yes, the given number has an alternate bit pattern". print("Yes, the given number{", gvn_numbr, "} has an alternate bit pattern") else: # Else print "No, the given number doesn't have an alternate bit pattern". print("No, the given number{", gvn_numbr, "} doesn't have an alternate bit pattern")

**Output:**

Enter some random number = 14 No, the given number{ 14 } doesn't have an alternate bit pattern

Dive into numerous Python Programming Language Examples for practice and get the best out of the tutorial and learn python one step at a time.