Program to Print V Character Pattern
In the previous article, we have discussed Java Program to Print Inverted V Symbol Character Pattern
In this article, we are going to see how to print the character pattern of the letter V.
- Java Code to Print V Character Pattern
- C Code to Print V Character Pattern
- C++ Code to Print V Character Pattern
Example-1
When the number of rows =5
A I
B H
C G
D F
E
Example-2
When the number of rows =8
A O
B N
C M
D L
E K
F J
G I
H
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Approach
- Enter total row and store it in an integer variable say
row. - Take a inner for loop to print the column values.
- Keep iterating and print the values.
Java Code to Print V Character Pattern
import java.util.Scanner;
public class Main
{
public static void main(String[] args)
{
int row;
// starting ASCII value taken 64
int ascii=64;
// create scanner class to take user input
Scanner sc= new Scanner(System.in);
System.out.print("Enter no of row = ");
row=sc.nextInt();
int c, r;
int x = 1;
// store row*2-1 value in y
int y = row * 2 - 1;
// loop to iterate through rows
for (r = 1; r <= row; r++)
{
// iterate inner loop from 1 till row*2
for (c = 1; c <= row * 2; c++)
{
// if c= x or y print the symbol, else space
if (c == x || c == y)
{
System.out.print((char)(c+ascii));
}
else
{
System.out.print(" ");
}
}
// increment x
x++;
// decrement y
y--;
System.out.println("");
}
}
}
Output:
Enter no of row = 8
A O
B N
C M
D L
E K
F J
G I
H
C Code to Print V Character Pattern
#include <stdio.h>
int main()
{
printf("Enter no of row = ");
int row;
int ascii=64;
scanf("%d", &row);
int c, r;
int x = 1;
int y = row * 2 - 1;
for (r = 1; r <= row; r++)
{
for (c = 1; c <= row * 2; c++)
{
if (c == x || c == y)
{
printf("%c",(c+ascii));
}
else
{
printf(" ");
}
}
x++;
y--;
printf("\n");
}
}
Output:
Enter no of row = 8
A O
B N
C M
D L
E K
F J
G I
H
C++ Code to Print V Character Pattern
#include <iostream>
using namespace std;
int main()
{
cout<<"Enter no of row = ";
int row;
cin>>row;
int c, r;
int ascii=64;
int x = 1;
int y = row * 2 - 1;
for (r = 1; r <= row; r++)
{
for (c = 1; c <= row * 2; c++)
{
if (c == x || c == y)
{
cout<<(char)(c+ascii);
}
else
{
cout<<" ";
}
}
x++;
y--;
cout<<"\n";
}
}
Output:
Enter no of row = 8
A O
B N
C M
D L
E K
F J
G I
H
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