In the previous article we have discussed about Java Program to print Series 8 6 9 23 87 … N
In this article we are going to see how to print the series 11 22 33 44 55 … N by using Java programming language.
Java Program to Print the Series 11 22 33 44 55 … N
On observing the pattern carefully, we can see
1st number starts from 11, Then the next number is the nth times of the previous number
Example:
11 | 22 | 33 | 44 | 55 | 66 | … | N |
11*1 11*2 11*3 11*4 11*5 11*6 11*n
Let’s see different ways to print the series 11 22 33 44 55 … N
Method-1: Java Program to Print the Series 11 22 33 44 55 … N By Using For Loop
Approach:
- Create Scanner class object.
- Declare an integer variable say ‘
n
’ which holds the Nth term of the series - Prompt the user to enter a number as value of
n
. - Let declare a integer variable say ‘
number
’ and initialize it to 11 - Use a for loop
from i=1 to i<=n
where the loop is incremented by 1 - Let declare an integer variable say ‘
result
’ - Inside the for loop we will find the value of
result = number*i
. - Print the result in the series.
Program:
import java.util.*; public class Main { public static void main(String [] args) { //creating object of Scanner class Scanner s = new Scanner(System.in); //Taking input of number of elements in the series System.out.println("Enter the Nth term “N” "); int n = s.nextInt(); int number = 11; //for loop to print the series for (int i = 1; i <= n; i++) { int result = number*i; System.out.print(result+" "); } } }
Output: Enter the Nth term “N” 5 11 22 33 44 55
Method-2: Java Program to Print the Series 11 22 33 44 55 … N By Using While Loop
Approach:
- Create Scanner class object.
- Declare an integer variable say ‘
n
’ which holds the Nth term of the series - Prompt the user to enter a number as value of
n
. - Let declare a integer variable say ‘
number
’ and initialize it to 11 - Declare and initialize an integer variable
i=1
- Continue a while loop
till i<=n
, where i is incremented by 1. - Declare an integer variable ‘
result
’ - Inside while loop find the value of
result = number*i
- Print the result in the series.
Program:
import java.util.*; public class Main { public static void main(String [] args) { //creating object of Scanner class Scanner s = new Scanner(System.in); //Taking input of number of elements in the series System.out.println("Enter the Nth term “N” "); int n = s.nextInt(); int number=11; int i=1; while(i<=n) { int result =number*i; System.out.print(result+" "); i++; } } }
Output: Enter the Nth term “N” 7 11 22 33 44 55 66 77
Method-3: Java Program to Print the Series 11 22 33 44 55 … N By Using For Loop
Approach:
- Create Scanner class object.
- Declare an integer variable say ‘
n
’ which holds the Nth term of the series - Prompt the user to enter a number as value of
n
. - Call a user defined method
printSeries()
by passingn
as parameter. - Inside method declare a integer variable say ‘
number
’ and initialize it to 11 - Use a for loop
from i=1 to i<=n
where the loop is incremented by 1 - Let declare an integer variable say ‘
result
’ - Inside the for loop we will find the value of
result = number*i
. - Print the result in the series.
Program:
import java.util.*; public class Main { public static void main(String[] args) { // creating object of scanner class Scanner s = new Scanner(System.in); //Taking input of number of elements in the series System.out.println("Enter the value of Nth term 'N' "); int n = s.nextInt(); // calling printSeries method to print the series printSeries(n); } //printSeries metthod to print the series public static void printSeries(int n) { int number = 11; //for loop to print the series for (int i = 1; i <=n; i++) { int result =number*i; System.out.print(result+" "); } } }
Output: Enter the value of Nth term 'N' 6 11 22 33 44 55 66
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