In the previous article we have discussed about Java Program to Print the Sum of Series 3 + 7+ 13 + 21 + … + N
In this article we are going to see how to print the series 1 9 17 33 49 73 97 … N by using Java programming language.
Java Program to Print the Series 1 9 17 33 49 73 97 … N
On observing the pattern carefully, we can see the series follows a logic
If i is odd then 2*(i*i)-1
If i is even then 2*(i*i)+1
Example:
2*(i*i)-1 = 2*(1*1)-1 = 1
2*(i*i)-1 = 2*(2*2)+1 = 9
2*(i*i)-1 = 2*(3*3)-1 = 17
2*(i*i)-1 = 2*(4*4)+1 = 33 … and so on.
1 | 9 | 17 | 33 | 49 | 73 | …… | N |
Let’s see different ways to
Method-1: Java Program to Print the Series 1 9 17 33 49 73 97 … N By Using For Loop
Approach:
- Create Scanner class object.
- Declare an integer variable say ‘
n
’ which holds the number of terms in the series. - Prompt the user to enter a number as value of
n
. - Let declare an integer variable say ‘
result
’ - Use a for loop
from i=1 to i<=n
where the loop is incremented by 1 - Inside the for loop we will find the value of result according to the position of
i
. Ifi
is odd thenresult=2*(i*i)-1
, Ifi
is even thenresult=2*(i*i)+1
- Print the result in the series.
Program:
import java.util.*; public class Main { public static void main(String [] args) { //creating object of Scanner class Scanner s = new Scanner(System.in); //Taking input of number of elements in the series System.out.println("Enter the number of terms "); int n = s.nextInt(); int result; //for loop to print the series for (int i = 1; i <= n; i++) { if(i%2==0) { result=(int) (2*Math.pow(i,2)+1); System.out.print(result+" "); } else { result=(int) (2*Math.pow(i,2)-1); System.out.printf(result+" "); } } } }
Output: Enter the number of terms 5 1 9 17 33 49
Method-2: Java Program to Print the Series 1 9 17 33 49 73 97 … N By Using While Loop
Approach:
- Create Scanner class object.
- Declare an integer variable say ‘
n
’ which holds the number of terms in the series. - Prompt the user to enter a number as value of
n
. - Let declare integer variable say ‘
result
’ - Declare and initialize an integer variable
i=1
- Continue a while loop till
i<=n
, wherei
is incremented by 1. - Inside while loop we will find the value of result according to the position of
i
. Ifi
is odd thenresult=2*(i*i)-1
, Ifi
is even thenresult=2*(i*i)+1
- Print the result in the series.
Program:
import java.util.*; public class Main { public static void main(String [] args) { //creating object of Scanner class Scanner s = new Scanner(System.in); //Taking input of number of elements in the series System.out.println("Enter the Nth term “N” "); int n = s.nextInt(); int result; int i=1; while(i<=n) { if(i%2==0) { result=(int) (2*Math.pow(i,2)+1); System.out.print(result+" "); } else { result=(int) (2*Math.pow(i,2)-1); System.out.printf(result+" "); } i++; } } }
Output: Enter the number of terms 7 1 9 17 33 49 73 97
Method-3: Java Program to Print the Series 1 9 17 33 49 73 97 … N By Using User Defined Method
Approach:
- Create a Scanner class object.
- Prompt the user to enter a value of
n
which holds the number of terms in the series. - Call a user defined method
printSeries()
by passing n as parameter. - Inside the method declare integer variable say ‘
result
’. - Inside the for loop we will find the value of result according to the position of
i
. Ifi
is odd thenresult=2*(i*i)-1
, Ifi
is even thenresult=2*(i*i)+1
- Print the result in the series.
Program:
import java.util.*; public class Main { public static void main(String[] args) { // creating object of scanner class Scanner s = new Scanner(System.in); //Taking input of number of elements in the series System.out.println("Enter the value of Nth term 'N' "); int n = s.nextInt(); // calling printSeries method to print the series printSeries(n); } //printSeries() metthod to print the series public static void printSeries(int n) { int result ; for(int i = 1; i<=n; i++) { if(i%2==0) { result=(int) (2*Math.pow(i,2)+1); System.out.print(result+" "); } else { result=(int) (2*Math.pow(i,2)-1); System.out.printf(result+" "); } } } }
Output: Enter the number of terms 9 1 9 17 33 49 73 97 129 161
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