In the previous article we have discussed about Java Program to Print the Series 2 1 4 3 6 5 N
In this article we are going to see how to print the series 1 2 11 12 21 … N by using Java programming language.
Java Program to Print the Series 1 2 11 12 21 … N
On observing the pattern carefully, we can see
1st & 2nd number is 1, 2 respectively. Then the next number follows a logic
1 2 1+10=11 2+10=12 11+10=21 12+10=22… and so on
Example:
1 | 2 | 11 | 12 | 21 | 22 | …… | N |
1+10 2+10 11+10 12+10
Let’s see different ways to print the series 1 2 11 12 21 … N
Method-1: Java Program to Print the Series 1 2 11 12 21 … N By Using For Loop
Approach:
- Create Scanner class object.
- Declare an integer variable say ‘
n
’ which holds the number of terms in the series. - Prompt the user to enter a number as value of
n
. - Declare two integer variables say ‘
a
’, ‘b
’ and initialize it to 1,2 respectively. - Use a for loop
from i=1 to i<=n-2
where the loop is incremented by 1 - Inside the for loop we will find the value of
a
,b
according to the position ofi
. Ifi%2 != 0
thena = a+10
elseb=b+10
- Print the result in the series.
Program:
import java.util.*; public class Main { public static void main(String [] args) { //creating object of Scanner class Scanner s = new Scanner(System.in); //Taking input of number of elements in the series System.out.println("Enter number of terms "); int n = s.nextInt(); int a = 1; int b = 2; System.out.print(a+" "+b); //for loop to print the series for (int i = 1; i <= n-2; i++) { if(i%2 != 0) { a+=10; System.out.print(" "+a); } else { b+=10; System.out.print(" "+b); } } } }
Output: Enter number of terms 5 1 2 11 12 21
Method-2: Java Program to Print the Series 1 2 11 12 21 … N By Using While Loop
Approach:
- Create Scanner class object.
- Declare an integer variable say ‘
n
’ which holds the number of terms in the series. - Prompt the user to enter a number as value of
n
. - Declare two integer variables say ‘
a
’, ‘b
’ and initialize it to 1,2 respectively. - Declare and initialize an integer variable i=1
- Continue a while loop
till i<=n-2
, wherei
is incremented by 1. - Inside the while loop we will find the value of
a
,b
according to the position ofi
. Ifi%2 != 0
thena = a+10
elseb=b+10
- Print the result in the series.
Program:
import java.util.*; public class Main { public static void main(String [] args) { //creating object of Scanner class Scanner s = new Scanner(System.in); //Taking input of number of elements in the series System.out.println("Enter number of terms "); int n = s.nextInt(); int a = 1, b=2; System.out.print(a + " " +b); int i=1; while(i<=n-2) { if(i%2 != 0) { a+=10; System.out.print(" "+a); } else { b+=10; System.out.print(" "+b); } i++; } } }
Output: Enter number of terms 7 31 1 2 11 12 21 22
Method-3: Java Program to Print the Series 1 2 11 12 21 … N By Using User Defined Method
Approach:
- Create Scanner class object.
- Declare an integer variable say ‘
n
’ which holds the number of terms in the series. - Prompt the user to enter a number as value of
n
. - Call a user defined method say
printSeries()
by passingn
as parameter. - Inside method declare two integer variables say ‘
a
’, ‘b
’ and initialize it to 1,2 respectively. - Use a for loop
from i=1 to i<=n-2
where the loop is incremented by 1 - Inside the for loop we will find the value of
a
,b
according to the position ofi
. Ifi%2 != 0
thena = a+10
elseb=b+10
- Print the result in the series.
Program:
import java.util.*; public class Main { public static void main(String[] args) { // creating object of scanner class Scanner s = new Scanner(System.in); //Taking input of number of elements in the series System.out.println("Enter number of terms "); int n = s.nextInt(); // calling printSeries method to print the series printSeries(n); } //printSeries metthod to print the series public static void printSeries(int n) { int a=1, b = 2; System.out.print(a+" "+b); //for loop to print the series for (int i = 1; i <=n-2; i++) { if(i%2 != 0) { a+=10; System.out.print(" "+a); } else { b+=10; System.out.print(" "+b); } } } }
Output: Enter number of terms 9 1 2 11 12 21 22 31 32 41
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