In the previous article we have discussed about Java Program to Print the Series 2 1 1/2 1/4 1/8 … N
In this article we are going to see how to print the series 0 4 18 48 100 180 …N by using Java programming language.
Java Program to Print the Series 0 4 18 48 100 180 …N
On observing the pattern carefully, we can see
The series follows a logic using i.e (i^3)-(i^2)
where i
starts from 1 and incremented by 1 in each term.
(1^3)-(1^2) = 0
(2^3)-(2^2) = 4
(3^3)-(3^2) = 18
(4^3)-(4^2) = 48 and so on.
Example:
0 | 4 | 18 | 48 | 100 | 180 | …… | N |
Let’s see different ways to print the series 0 4 18 48 100 180 …N
Method-1: Java Program to Print the Series 0 4 18 48 100 180 …N By Using For Loop
Approach:
- Create Scanner class object.
- Declare an integer variable say ‘
n
’ which holds the number of terms in the series. - Prompt the user to enter a number as value of
n
. - Let declare an double variable say ‘
result
’ - Use a for loop from
i=1 to i<=n
where the loop is incremented by 1 - Inside the for loop we will find the value of
result=(i^3)-(i^2)
. - Print the result in the series.
Program:
import java.util.*; public class Main { public static void main(String [] args) { //creating object of Scanner class Scanner s = new Scanner(System.in); //Taking input of number of elements in the series System.out.println("Enter the Nth term “N” "); int n = s.nextInt(); double result; //for loop to print the series for (int i = 1; i <= n; i++) { result = Math.pow(i,3)-Math.pow(i,2); System.out.print((int)result+" "); } } }
Output: Enter the Nth term “N” 5 0 4 18 48 100
Method-2: Java Program to Print the Series 0 4 18 48 100 180 …N By Using While Loop
Approach:
- Create Scanner class object.
- Declare an integer variable say ‘
n
’ which holds the number of terms in the series. - Prompt the user to enter a number as value of
n
. - Let declare double variable say ‘
result
’ - Declare and initialize an integer variable
i=1
- Continue a while loop
till i<=n
, wherei
is incremented by 1. - Inside while loop find the value of
result = (i^3)-(i^2)
. - Print the result in the series.
Program:
import java.util.*; public class Main { public static void main(String [] args) { //creating object of Scanner class Scanner s = new Scanner(System.in); //Taking input of number of elements in the series System.out.println("Enter the Nth term “N” "); int n = s.nextInt(); double result; int i=1; while(i<=n) { result = Math.pow(i,3)-Math.pow(i,2); System.out.print((int)result+" "); i++; } } }
Output: Enter the Nth term “N” 7 0 4 18 48 100 180 294
Method-3: Java Program to Print the Series 0 4 18 48 100 180 …N By Using User Defined Method
Approach:
- Create Scanner class object.
- Declare an integer variable say ‘
n
’ which holds the number of terms in the series. - Prompt the user to enter a number as value of
n
. - Call a user defined method say
printSeries()
by passingn
as parameter. - Inside method declare an double variable say ‘
result
’ - Use a for loop from
i=1 to i<=n
where the loop is incremented by 1 - Inside the for loop we will find the value of
result=(i^3)-(i^2)
. - Print the result in the series.
Program:
import java.util.*; public class Main { public static void main(String[] args) { // creating object of scanner class Scanner s = new Scanner(System.in); //Taking input of number of elements in the series System.out.println("Enter the value of Nth term 'N' "); int n = s.nextInt(); // calling printSeries method to print the series printSeries(n); } //printSeries metthod to print the series public static void printSeries(int n) { double result; //for loop to print the series for (int i = 1; i <=n; i++) { result = Math.pow(i,3)-Math.pow(i,2); System.out.print((int)result+" "); } } }
Output: Enter the value of Nth term 'N' 9 0 4 18 48 100 180 294 448 648
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