# Spiral matrix in java – Java Program to Print the elements of the Matrix in Spiral Form

Spiral matrix in java: In the previous article, we have seen Java Program to Print Matrix in Z form

In this article we are going to see how we can write a program to how to print Matrix in spiral from.

## Java Program to Print the elements of the Matrix in Spiral Form

A 3*3 Matrix is having 3 rows and 3 columns where this 3*3 represents the dimension of the matrix. Means there are 3*3 i.e. total 9 elements in a 3*3 Matrix.

Let’s understand it in more simpler way.

                   | A00   A01   A02 |
Matrix A =  | A10   A11   A12 |
| A20   A21   A22 | 3*3
• Matrix A represents a 3*3 matrix.
• A‘ represents the matrix element.
• Aij‘ represents the matrix element at it’s matrix position/index.
• i‘ represents the row index
• j‘ represents the column index
• Means A00=Aij  where i=0 and j=0,  A01=aij where i=0 and j=1 and like this.
• Here we have started row value from 0 and column value from 0.

Let’s see different ways to print Matrix in spiral from.

### Method: Java Program to Print the elements of the Matrix in Spiral Form By Static Initialization of Array Elements

Approach:

• Initialize and declare a matrix.
• Traverse the matrix through [0,0] point and traverse by row wise.
• Take 1st for loop to move from left to right.
• Take 2nd for loop to move top to bottom.
• Take 3rd for loop to move right to left.

Program:

import java.util.*;
public class Main
{
public static void main(String args[])
{
int mat[][]={{10,20,30},{40,50,60},{70,80,90}};
int a = 0;
int b = mat.length-1;
int c = 0;
int d = mat.length-1;
while(a <= b && c <= d)
{
for (int x = a; x <= d; x++)
{
System.out.print(mat[a][x] + " ");
}
for (int x = a+1; x <= b; x++)
{
System.out.print(mat[x][d] + " ");
}
if(a+1 <= b)
{
for (int x = d-1; x >= c; x--)
{
System.out.print(mat[b][x] + " ");
}
}
if(c+1 <= d)
{
for (int x = b-1; x > a; x--)
{
System.out.print(mat[x][c] + " ");
}
}
a++;
b--;
c++;
d--;
}
}
}

Output:

10 20 30 60 90 80 70 40 50

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