Spiral matrix in java: In the previous article, we have seen Java Program to Print Matrix in Z form
In this article we are going to see how we can write a program to how to print Matrix in spiral from.
Java Program to Print the elements of the Matrix in Spiral Form
A 3*3 Matrix is having 3 rows and 3 columns where this 3*3 represents the dimension of the matrix. Means there are 3*3 i.e. total 9 elements in a 3*3 Matrix.
Let’s understand it in more simpler way.
| A00 A01 A02 | Matrix A = | A10 A11 A12 | | A20 A21 A22 | 3*3
Matrix A
represents a 3*3 matrix.- ‘
A
‘ represents the matrix element. - ‘
Aij
‘ represents the matrix element at it’s matrix position/index. - ‘
i
‘ represents the row index - ‘
j
‘ represents the column index - Means
A00=Aij
wherei=0
andj=0
,A01=aij
wherei=0
andj=1
and like this. - Here we have started
row
value from 0 andcolumn
value from 0.
Let’s see different ways to print Matrix in spiral from.
Method: Java Program to Print the elements of the Matrix in Spiral Form By Static Initialization of Array Elements
Approach:
- Initialize and declare a matrix.
- Traverse the matrix through [0,0] point and traverse by row wise.
- Take 1st for loop to move from left to right.
- Take 2nd for loop to move top to bottom.
- Take 3rd for loop to move right to left.
Program:
import java.util.*; public class Main { public static void main(String args[]) { int mat[][]={{10,20,30},{40,50,60},{70,80,90}}; int a = 0; int b = mat.length-1; int c = 0; int d = mat[0].length-1; while(a <= b && c <= d) { for (int x = a; x <= d; x++) { System.out.print(mat[a][x] + " "); } for (int x = a+1; x <= b; x++) { System.out.print(mat[x][d] + " "); } if(a+1 <= b) { for (int x = d-1; x >= c; x--) { System.out.print(mat[b][x] + " "); } } if(c+1 <= d) { for (int x = b-1; x > a; x--) { System.out.print(mat[x][c] + " "); } } a++; b--; c++; d--; } } }
Output: 10 20 30 60 90 80 70 40 50
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