Java Program to Print Square with Increasing Number Pattern

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Print Square with Increasing Number Pattern

In the previous article, we have discussed Java Program to Print K shape Decreasing Number Pattern

In this program we are going to see how to print the square with increasing number pattern.

Example-1

When size value=5

 1    2   3    4   5
 6    7   8   9  10
 11 12 13 14 15
 16 17 18 19 20
 21 22 23 24 25
Example-2:

When size value=3

 1 2 3
 4 5 6
 7 8 9

Now, let’s see the actual program to print it.

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Approach:

  • Enter total size and store it in an integer variable size.
  • Take one outer for loop to iterate the rows,
  • Take one inner for loop to iterate the columns and print the column values.
  • After each iteration print a newline.

Java Code to Print Square with Increasing Number Pattern

import java.util.Scanner;
class Main
{
    public static void main(String[] args)
    {
        //Taking size as input from user
        System.out.print("Size of square : ");
        Scanner scan = new Scanner(System.in);
        int size = scan.nextInt();

        //Row and column are the iterators
        //Holder holds our value after each iteration
        int row, col, holder = 0;

        //Outer loop to iterate the rows
        //Iterates from 1 to the size entered by the user
        for(row=1;row<=size;row++)
        {
                //Inner loop to iterate the columns
                //Iterates from 1 to the size entered by the user
                for(col = 1; col<=size; col++)
                {
                        //Increments the value in the holder then prints the value
                        System.out.print(++holder+" ");
                }
                //Prints a newline
                System.out.println();
        }
    }
}


Output:

Size of square : 5

 1 2 3 4 5
 6 7 8 9 10
 11 12 13 14 15
 16 17 18 19 20
 21 22 23 24 25

C Code to Print Square with Increasing Number Pattern

#include <stdio.h>

int main()
{
    //Taking size as input from user
    printf("Size of square : ");
    int size;
    scanf("%d", &size);

    //Row and column are the iterators
    //Holder holds our value after each iteration
    int row, col, holder = 0;

    //Outer loop to iterate the rows
    //Iterates from 1 to the size entered by the user
    for (row = 1; row <= size; row++)
    {
        //Inner loop to iterate the columns
        // Iterates from 1 to the size entered by the user
        for (col = 1; col <= size; col++)
        {
            //Increments the value in the holder then prints the value
            printf("%d ", ++holder);
        }
        //Prints a newline
        printf("\n");
    }
    return 0;
}

Output:

Size of square : 5

 1 2 3 4 5
 6 7 8 9 10
 11 12 13 14 15
 16 17 18 19 20
 21 22 23 24 25

C++ Code to Print Square with Increasing Number Pattern

#include <iostream>
using namespace std;
int main(int argc, char const *argv[])
{
    //Taking size as input from user
    cout << "Size of square : ";
    int size;
    cin >> size;

    //Row and column are the iterators
    //Holder holds our value after each iteration
    int row, col, holder = 0;

    //Outer loop to iterate the rows
    //Iterates from 1 to the size entered by the user
    for (row = 1; row <= size; row++)
    {
        //Inner loop to iterate the columns
        // Iterates from 1 to the size entered by the user
        for (col = 1; col <= size; col++)
        {
            //Increments the value in the holder then prints the value
            cout << " " << ++holder;
        }
        //Prints a newline
        cout << endl;
    }
    return 0;
}



Output:

Size of square : 5

 1 2 3 4 5
 6 7 8 9 10
 11 12 13 14 15
 16 17 18 19 20
 21 22 23 24 25

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