Program to Print Rhombus Star Pattern
In this article we are going to see how to print the rhombus star pattern.
Example-1 When row value=4 **** **** **** ****
Example-2 When row value=5 ***** ***** ***** ***** *****
Now, let’s see the actual program to print it.
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Approach:
- Enter total row and store it in an integer variable
rows. - Take one outer for loop to iterate the rows.
- Take two inner for loops, one to print the space and the other one to print the star.
- After each iteration print a new line.
JAVA Code:
Method-1 : Static Star Character
import java.util.Scanner;
class pattern
{
public static void main(String[] args)
{
Scanner scan = new Scanner(System.in);
System.out.print("Rows : ");
//Taking input from user
int rows=scan.nextInt();
//Outer loop
for (int r=1; r<=rows; r++)
{//Inner loop 1
for (int c=rows-1; c>=r; c--)
{
System.out.print(" ");
}
// Prints star in decreasing order
for (int k=1; k<=rows; k++)
{//Inner loop 2
System.out.print("*");
}
//Prints a newline
System.out.println();
}
}
}
Output: Rows : 5 ***** ***** ***** ***** *****
Method-2 : User Input Character
import java.util.Scanner;
class pattern
{
public static void main(String[] args)
{
Scanner scan = new Scanner(System.in);
System.out.print("Rows : ");
//Taking input from user
int rows=scan.nextInt();
System.out.print("Symbol : ");
//Taking random character input from user
char s=scan.next().charAt(0);
//Outer loop
for (int r=1; r<=rows; r++)
{//Inner loop 1
for (int c=rows-1; c>=r; c--)
{
System.out.print(" ");
}
// Prints star in decreasing order
for (int k=1; k<=rows; k++)
{//Inner loop 2
System.out.print(s);
}
//Prints a newline
System.out.println();
}
}
}
Output: Rows : 5 Symbol : ^ ^^^^^ ^^^^^ ^^^^^ ^^^^^ ^^^^^
Explanation :
Let’s understand the program by going through the detailed explanation.
We have taken rows value as 5.
Iteration-1
r=1, goes into the first inner loop and prints 4 space as it will iterate upto c>=r
The second for loop prints five star(‘*’) for k<=rows (i.e. 5).
*****
Iteration-2
r=2, goes into the first inner loop and prints 3 space as it will iterate upto c>=r.
The second for loop prints five star(‘*’) for k<=rows (i.e. 5).
*****
Iteration-3
r=3, goes into the first inner loop and prints 2 space as it will iterate upto c>=r
The second for loop prints five star(‘*’) for k<=rows (i.e. 5).
*****
Iteration-4
r=4, goes into the first inner loop and prints 1 space as it will iterate upto c>=r
The second for loop prints five star(‘*’) for k<=rows (i.e. 5).
*****
Iteration-5
r=5, does not go into first inner loop as conditions fails c>r(while current c value is row-1 i.e 4 but condition is c>r means 4>5 ios false). So no space will be printed.
The second for loop prints five star(‘*’) for k<=rows (i.e. 5).
*****
After this r >rows i.e. 6 so program will come out of the loop.
Now, after end of all iteration we will see the complete pattern is printed on the output screen like this.
***** ***** ***** ***** *****
C Code:
#include <stdio.h>
int main(int argc, char const *argv[])
{
printf("Enter rows : ");
int rows;
//Taking row as input from user
scanf("%d", &rows);
//Outer loop
for (int r = 1; r <= rows; r++)
{ //Inner loop
for (int c = rows - 1; c >= r; c--)
{
printf(" ");
}
// Print stars in decreasing order
for (int k = 1; k <= rows; k++)
{ //Inner loop 2
printf("*");
} //To print a newline
printf("\n");
}
return 0;
}
Output: Enter rows : 5 ***** ***** ***** ***** *****
C++ Code:
#include <iostream>
using namespace std;
int main(int argc, char const *argv[])
{
cout << "Enter rows : ";
int rows;
//Taking row as input from user
cin >> rows;
//Outer loop
for (int r = 1; r <= rows; r++)
{ //Inner loop 1
for (int c = rows - 1; c >= r; c--)
{
cout << " ";
}
// Print stars in decreasing order
for (int k = 1; k <= rows; k++)
{ //Inner loop 2
cout << "*";
} //To print a newline
cout << endl;
}
return 0;
}
Output: Enter rows : 5 ***** ***** ***** ***** *****
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