Java Program to Print Pencil Shape Star Pattern

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Program to Print Pencil Shape Star Pattern

In this article we are going to see how to print the Pencil star pattern

Example-1

If the user input is 2
* * *
* * *
* * *
 * *
  *
Example-2

If the user input is 4
* * * * *
* * * * *
* * * * *
* * * * *
* * * * *
 * * * *
  * * *
   * *
    *

The best and excellent way to learn a java programming language is by practicing Simple Java Program Examples as it includes basic to advanced levels of concepts.

Approach:

  • Enter total row and store it an integer variable say row.
  • Take first for loop to print all the rows.
  • Take inner loop to print the column values.

JAVA Code:

Methdo-1 : Static Star Character

import java.util.Scanner;
public class Main{
    public static void main(String[] args){
    int r,c,h,row;
    Scanner sc= new Scanner(System.in);
    System.out.print("Enter the Value for row : ");
    row=sc.nextInt();
    
    // this loop will execute from -row to +row
    for(r=-row; r<=row; r++) 
    {
        h=r;
 
        for(c=0; c<=row; c++)
        {
            if(h<=c)
                System.out.print("* ");
            else
                System.out.print(" ");
        }
         System.out.println("");
    }
    }
}


Output:

Enter the Value for row: 2
*  *  *
*  *  *
*  *  *
 *  *
   *

Method-2 : User Input Character

import java.util.Scanner;
public class Main{
    public static void main(String[] args){
    int r,c,h,row;
    Scanner sc= new Scanner(System.in);
    System.out.println("Enter the Value for row : ");
    row=sc.nextInt();
    
    System.out.print("Enter any character : ");
    char s=sc.next().charAt(0);
    
    // this loop will execute from -row to +row
    for(r=-row; r<=row; r++) 
    {
        h=r;
 
        for(c=0; c<=row; c++)
        {
            if(h<=c)
                System.out.print(s+" ");
            else
                System.out.print(" ");
        }
         System.out.println("");
    }
    }
}



Output:

Enter the value for row :
2
Enter any character : @
@ @ @
@ @ @
@ @ @
  @ @
    @

Explanation:

Let’s understand the program with detailed explanation.

Let we have taken row as 2.

Iteration-I

r=-2 (passed through first for loop condition) which will execute till r<=2.

The r value will be store in a variable say h.

Then inner for loop will iterate from c=0 till c<=row.

If h<=c print the symbol 3 times, otherwise print space.

***

Iteration-II

r=-1 (passed through first for loop condition) which will execute till r<=2.

The r value will be store in a variable say h.

Then inner for loop will iterate from c=0 till c<=row.

If h<=c print the symbol 3 times, otherwise print space.

***

Iteration-III

r=0 (passed through first for loop condition) which will execute till r<=2.

The r value will be store in a variable say h.

Then inner for loop it from c=0 till c<=row.

If h<=c print the symbol 3 times, otherwise print space.

***

Iteration-IV

r=1 (passed through first for loop condition) which will execute till r<=2.

The r value will be store in a variable say h. Then inner for loop it from c=0 till c<=row.

If h<=c print the symbol 2 times, otherwise print space.

 * *

Iteration-V

r=2 (passed through first for loop condition) which will execute till r<=2.

The r value will be store in a variable say h.

Then inner for loop it from c=0 till c<=row. If h<=c print the symbol 1 time, otherwise print space.

  *

Now r=3, so first for loop condition fails. And no more for loop will be executed. At last we see a pattern like this.

* * *
* * *
* * *
 * *
  *

C Code:

#include <stdio.h>

int main() {
    int r,c,h,row;
    printf("Enter the Value for h: ");
    scanf("%d",&row);
    for(r=-row; r<=row; r++) 
    {
        h=r;
 
        for(c=0; c<=row; c++)
        {
            if(h<=c)
                printf("* ");
            else
                printf(" ");
        }
         printf("\n");
    }
}


Output:

Enter the Value for h: 2
* * *
* * *
* * *
 * *
  *

C++ Code:

#include <iostream>
using namespace std;

int main() {
    int r,c,h,row;
    cout<<("Enter the Value for h: ");
    cin>>row;
    for(r=-row; r<=row; r++) 
    {
        h=r;
 
        for(c=0; c<=row; c++)
        {
            if(h<=c)
                cout<<("* ");
            else
                cout<<(" ");
        }
         cout<<("\n");
    }
}


Output:

Enter the Value for h: 2
* * *
* * *
* * *
 * *
  *

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