Program to Print Inverted Pascal’s Triangle Star Pattern
Pascal triangle java: In this article we are going to see how to print the triangle star program.
Example-1 When row value=4 * * * * * * * * * *
Example-2: When row value=5 * * * * * * * * * * * * * * *
Now, let’s see how program printing it.
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Approach:
- Enter total row and store it in an integer variable
row. - Take first for loop to print all rows.
- Take first inner for loop to print column values i.e., first inner for loop will print all the spaces in the column.
- Take second inner for loop to print column values i.e., second inner for loop will print all the stars in the column.
- Then go on printing the star symbol according to loop.
JAVA Code:
Method-1 : Static Star Character
import java.util.*;
public class Main
{
public static void main(String args[])
{ // taking variable for loop iteration and row .
int row,r,c,d;
//creating object
Scanner s = new Scanner(System.in);
// entering the number of row
System.out.print("Enter rows : ");
row = s.nextInt();
//counting space
for (r=row;r>=1;r--)
{
//printing the spaces
for(c=row-r;c>=1;c--)
System.out.print(" ");
//printing the stars
for(c=1;c<=r;c++)
System.out.print(" * ");
// taking to new line
System.out.println();
}
}
}
Output: Enter rows : 5 * * * * * * * * * * * * * * *
Method-2 User Input Character
import java.util.*;
public class Main
{
public static void main(String args[])
{ // taking variable for loop iteration and row .
int row,r,c,d;
//creating object
Scanner s = new Scanner(System.in);
// entering the number of row
System.out.print("Enter rows : ");
row = s.nextInt();
// entering the symbol
System.out.print("Enter symbol : ");
char symbol = s.next().charAt(0);
//counting space
for (r=row;r>=1;r--)
{
//printing the spaces
for(c=row-r;c>=1;c--)
System.out.print(" ");
//printing the stars
for(c=1;c<=r;c++)
System.out.print(" "+symbol+" ");
// taking to new line
System.out.println();
}
}
}
Output: Enter rows : 5 Enter symbol : # # # # # # # # # # # # # # # #
Explanation :
Iteration-1
r=5 (passes the first for loop condition) as it will iterate up to r>=1 times.
First inner for loop will iterate (row-r) to 1 that means , it will print the space 0 time .
then 2nd inner for loop will iterate up to c<=r times so, it prints the * 5 time .
So, star will be printed 5 time.
* * * * *
Iteration-2
r=4 (passes the first for loop condition) as it will iterate up to r>=1 times.
First inner for loop will iterate (row-r) to 1 that means , it will print the space 1 time .
then 2nd inner for loop will iterate up to c<=r times so, it prints the * 4 time .
So, star will be printed 4 time.
* * * *
Iteration-3
r=3 (passes the first for loop condition) as it will iterate up to r>=1 times.
First inner for loop will iterate (row-r) to 1 that means , it will print the space 2 time .
then 2nd inner for loop will iterate up to c<=r times so, it prints the * 3 time .
So, star will be printed 3 time.
* * *
Iteration-4
r=2 (passes the first for loop condition) as it will iterate up to r>=1 times.
First inner for loop will iterate (row-r) to 1 that means , it will print the space 3 time .
then 2nd inner for loop will iterate up to c<=r times so, it prints the * 2 time .
So, star will be printed 2 time.
* *
Iteration-5
r=1 (passes the first for loop condition) as it will iterate up to r>=1 times.
First inner for loop will iterate (row-r) to 1 that means , it will print the space 4 time .
then 2nd inner for loop will iterate up to c<=r times so, it prints the * 1 time .
So, star will be printed 1 time.
*
Now when r=0, first for loop condition will fail so no other loops will be executed.
At last, we will see a pattern like this as output.
* * * * * * * * * * * * * * *
C Code:
#include <stdio.h>
int main() {
int r, row, c ,d;
printf("Enter rows: ");
scanf("%d", &row);
for (r=row;r>=1;r--)
{
for(c=row-r;c>=1;c--)
printf(" ");
for(c=1;c<=r;c++)
printf(" * ");
printf("\n");
}
return 0;
}
Output: Enter rows : 5 * * * * * * * * * * * * * * *
C++ Code:
#include <iostream>
using namespace std;
int main()
{
int row, r , c ,d ;
cout << "Enter rows: ";
cin >> row;
for (r=row;r>=1;r--)
{
for(c=row-r;c>=1;c--)
cout << " ";
for(c=1;c<=r;c++)
cout << "* ";
cout << "\n";
}
return 0;
Output: Enter rows : 5 * * * * * * * * * * * * * * *
Related Java Star Pattern Programs: