Java Program to Print Exponentially Increasing Pattern

Program to Print Exponentially Increasing Pattern

In this article we are going to see how to print the exponentially increasing star pattern.

Example-1

If no of row = 4
*
**
****
********

Example-2

If no of row = 5
*
**
****
********
****************

Approach:

Enter total row and store it in an integer variable say row.
Take an outer for loop to print the rows.
Take an inner loop to print the column values.
Then go on printing the star symbols according to the pattern.

JAVA Code:

Static Star Character
User Input Character

Method-1 : Static Star Character

import java.util.Scanner;
public class Main
{
    public static void main(String[] args) 
    {
    int r,c,row;
    Scanner sc= new Scanner(System.in);
    System.out.print("Enter no of rows = ");
    row=sc.nextInt();
     
    // iteration for no of row
    for(r = 0; r < row; r++)
    {
      // print the column values
      // each column will print the values with power of r
      // Math.pow() function gives power of a number       
      for(c = 0; c < Math.pow(2,r); c++)
       {
           System.out.print("*");
       }
       // move to next line/row
       System.out.println("");
    }
    }
}

Output:

Enter no of rows = 5
*
**
****
********
****************

Method-2 : User Input Character

import java.util.Scanner;
public class Main
{
    public static void main(String[] args) 
    {
    int r,c,row;
    Scanner sc= new Scanner(System.in);
    System.out.print("Enter no of rows = ");
    row=sc.nextInt();
    
    System.out.print("Enter any character = ");
    char s=sc.next().charAt(0);
     
    // iteration for no of row
    for(r = 0; r < row; r++)
    {
      // print the column values
      // each column will print the values with power of r
      // Math.pow() function gives power of a number       
      for(c = 0; c < Math.pow(2,r); c++)
       {
           System.out.print(s);
       }
       // move to next line/row
       System.out.println("");
    }
    }
}

Output:

Enter no of rows = 5
Enter any character = @
@
@@
@@@@
@@@@@@@@
@@@@@@@@@@@@@@@@

Explanation:

Let’s understand the program with detailed explanation.

Let we have taken row as 5.

Iteration-I

r=0 (passed through first for loop condition) which will execute till r<row.

It will enter inner loop and execute it from c=0 till power of r^2 i.e. 1 time and print the values. It will print 1 star symbol.

Iteration-II

r=1 (passed through first for loop condition) which will execute till r<row.

It will enter inner loop and execute it from c=0 till power of r^2 i.e. 2 times and print the values. It will print 2 star symbols.

**

Iteration-III

r=2 (passed through first for loop condition) which will execute till r<row.

It will enter inner loop and execute it from c=0 till power of r^2 i.e. 4 times and print the values. It will print 4 star symbols.

****

Iteration-IV

r=3 (passed through first for loop condition) which will execute till r<row.

It will enter inner loop and execute it from c=0 till power of r^2 i.e. 8 times and print the values. It will print 8 star symbols.

********

Iteration-V

r=4 (passed through first for loop condition) which will execute till r<row.

It will enter inner loop and execute it from c=0 till power of r^2 i.e. 16 times and print the values. It will print 16 star symbols.

****************

Now i=5, so first for loop condition fails i.e. r<row. At no more for loop will be executed. At last we will see a pattern like this on output screen.

*
**
****
********
****************

C Code:

#include<stdio.h> 
#include<math.h>
 
int main(){
    int r,c,row;
    printf("Enter no of rows = ");
    scanf("%d", &row);
    for(r = 0; r < row; r++){
       for(c = 0; c < pow(2,r); c++){
           printf("*");
       }
       printf("\n");
    }
    return 0;
}

Output:

Enter no of rows = 5
*
**
****
********
****************

C++ Code:

#include <iostream>
#include <cmath>

using namespace std;

int main(){
    int r,c,row;
    cout<<"Enter no of rows = ";
    cin>>row;
    for(r = 0; r < row; r++)
    {
       for(c = 0; c < pow(2,r); c++)
       {
           cout<<"*";
       }
       cout<<"\n";
    }
    return 0;
}

Output:

Enter no of rows = 5
*
**
****
********
****************

Related Java Star Pattern Programs: