Program to Print Double Sided Stair Case Number Pattern
Print staircase java: In the previous article, we have discussed Java Program to Print Stair Case Number Pattern
In this article we are going to see how to print double sided staircase number program.
- Java Code to Print Double Sided Stair Case Number Pattern
- C Code to Print Double Sided Stair Case Number Pattern
- C++ Code to Print Double Sided Stair Case Number Pattern
Example-1 When row value=8 0 1 0 1 0 1 2 3 0 1 2 3 0 1 2 3 4 5 0 1 2 3 4 5 0 1 2 3 4 5 6 7 0 1 2 3 4 5 6 7
Example-2: When row value= 6 0 1 0 1 0 1 2 3 0 1 2 3 0 1 2 3 4 5 0 1 2 3 4 5
Now, let’s see the actual program to print it.
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Approach:
- Enter total row and store it in an integer variable
row
. - Take first outer for loop to keep track of number of rows.
- Take first inner for loop to print spaces .
- Take second inner for loop for printing numbers.
- Then go on printing the number according to loop.
Java Code to Print Double Sided Stair Case Number Pattern
import java.util.*; public class Main { public static void main(String args[]) { // taking variable for loop iteration and row . int row ,c,r,k; //creating object Scanner s = new Scanner(System.in); // entering the number of row System.out.print("Enter rows : "); row = s.nextInt(); for (r = 1; r <= row; r++) { if(r % 2 != 0) k = r + 1 ; else k = r; // loop for printing spaces for (c = row; c > k; c--) System.out.print(" "); // loop for printing numbers for (c = 0; c < k; c++) System.out.print(c+" "); System.out.println(); } } }
Output: Enter rows : 6 0 1 0 1 0 1 2 3 0 1 2 3 0 1 2 3 4 5 0 1 2 3 4 5
C Code to Print Double Sided Stair Case Number Pattern
#include <stdio.h> int main() { int row,r,c,k ; printf("Enter rows: "); scanf("%d", &row); for (r = 1; r <= row; r++) { if(r % 2 != 0) k = r + 1 ; else k = r; for (c = row; c > k; c--) printf(" "); for (c = 0; c < k; c++) printf("%d ",c); printf("\n"); } return 0; }
Output: Enter rows : 6 0 1 0 1 0 1 2 3 0 1 2 3 0 1 2 3 4 5 0 1 2 3 4 5
C++ Code to Print Double Sided Stair Case Number Pattern
#include <iostream> using namespace std; int main() { int row,r,c,k ; cout << "Enter rows: "; cin>> row; for (r = 1; r <= row; r++) { if(r % 2 != 0) k = r + 1 ; else k = r; for (c = row; c > k; c--) cout <<" "; for (c = 0; c < k; c++) cout << c << " "; cout <<"\n"; } return 0; }
Output: Enter rows : 6 0 1 0 1 0 1 2 3 0 1 2 3 0 1 2 3 4 5 0 1 2 3 4 5
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