Java Program to Print Cross Number Pattern

Printing Cross Number Pattern

In the previous article, we have discussed Java Program to Print Pascal’s Triangle Number Pattern

In this article we are going to see how to print the cross number pattern in java. What is number pattern program in java, cross pattern in java, Java Program To Print Cross Pattern, number patterns in java, Number Pattern Printing In Java, java code pattern, Xylem And Phloem Number In Java, Xylem And Phloem Program In Java, get the points in detail manner.

Example-1

When number value = 5

1        1
 2      2
  3    3
   4  4
     5
   4  4
  3    3
 2      2
1        1
Example-2:

When number value=7

1            1
 2          2
  3        3
   4      4
    5    5
     6  6
       7
     6  6
    5    5
   4      4
  3        3
 2          2
1            1

Now, let’s see the actual program to print it. 

The best and excellent way to learn a java programming language is by practicing Simple Java Program Examples as it includes basic to advanced levels of concepts.

Approach:

  • Enter the number to print up to and store it in an integer variable number.
  • Take one outer for loop to iterate the rows.
  • Take one inner for loop to iterate the columns.
  • After each iteration print a new line.

Recommended Reading On: Java Program to Print Pant Number Pattern (Second Approach)

Java Code to Print Cross Number Pattern

import java.util.Scanner;
class Main
{
public static void main(String[] args)
{
    //Create a new Scanner object
    Scanner scan = new Scanner(System.in);

    //Taking total number to print as input from user
    System.out.print("Number to print upto : ");
    int number = scan.nextInt();

   //Row and column are the iterators, space is the number of space
    //tempHolder is the pattern lines holder and numHolder iterates the value
    int numberOfRows, numberOfColumns, tempHolder = number * 2 - 1, numHolder = 1;

    //Outer loop to iterate the rows
    //Iterates from 1 to tempHolder(i.e. pattern lines)
    for (numberOfRows = 1; numberOfRows <= tempHolder; numberOfRows++)
    {
        //Inner loop to iterate the columns and print the number
        //Iterates from 1 to tempHolder(i.e. pattern lines)
        for (numberOfColumns = 1; numberOfColumns <= tempHolder; numberOfColumns++)
        {
            if (numberOfColumns == numberOfRows || numberOfColumns == tempHolder - numberOfRows + 1)
                System.out.print(numHolder);
            System.out.print(" ");
        }
        //Prints a newline
        System.out.println();
        //Logic to change the numholder value after each iteration
        numHolder = (numberOfRows <= tempHolder / 2) ? ++numHolder : --numHolder;
    }
}
}
Output:

Number to print upto : 6

1          1
 2        2
  3      3
   4    4
    5  5
     6
    5  5
   4    4
  3      3
 2        2
1          1

C Code to Print Cross Number Pattern

#include <stdio.h>

int main()
{
   //Taking total number to print as input from user
   printf("Number to print upto : ");
   int number;
   scanf("%d", &number);

   //Row and column are the iterators, space is the number of space
   //tempHolder is the pattern lines holder and numHolder iterates the value
   int numberOfRows, numberOfColumns, tempHolder = number * 2 - 1, numHolder = 1;

   //Outer loop to iterate the rows
   //Iterates from 1 to tempHolder(i.e. pattern lines)
   for (numberOfRows = 1; numberOfRows <= tempHolder; numberOfRows++)
   {
      //Inner loop to iterate the columns and print the number
      //Iterates from 1 to tempHolder(i.e. pattern lines)
      for (numberOfColumns = 1; numberOfColumns <= tempHolder; numberOfColumns++)
      {
         if (numberOfColumns == numberOfRows || numberOfColumns == tempHolder - numberOfRows + 1)
            printf("%d", numHolder);
         printf(" ");
      }
      //Prints a newline
      printf("\n");
      //Logic to change the numholder value after each iteration
      numHolder = (numberOfRows <= tempHolder / 2) ? ++numHolder : --numHolder;
   }
   return 0;
}
Output

Number to print upto : 6

1          1
 2        2
  3      3
   4    4
    5  5
     6
    5  5
   4    4
  3      3
 2        2
1          1

C++ Code to Print Cross Number Pattern

#include <iostream>
using namespace std;
int main(int argc, char const *argv[])
{
    //Taking total number to print as input from user
    cout << "Number to print upto : ";
    int number;
    cin >> number;

    //Row and column are the iterators, space is the number of space
    //tempHolder is the pattern lines holder and numHolder iterates the value
    int numberOfRows, numberOfColumns, tempHolder = number * 2 - 1, numHolder = 1;

    //Outer loop to iterate the rows
    //Iterates from 1 to tempHolder(i.e. pattern lines)
    for (numberOfRows = 1; numberOfRows <= tempHolder; numberOfRows++)
    {
        //Inner loop to iterate the columns and print the number
        //Iterates from 1 to tempHolder(i.e. pattern lines)
        for (numberOfColumns = 1; numberOfColumns <= tempHolder; numberOfColumns++)
        {
            if (numberOfColumns == numberOfRows || numberOfColumns == tempHolder - numberOfRows + 1)
                cout << numHolder;
            cout << " ";
        }
        //Prints a newline
        cout << endl;
        //Logic to change the numholder value after each iteration
        numHolder = (numberOfRows <= tempHolder / 2) ? ++numHolder : --numHolder;
    }
    return 0;
}
Output:

Number to print upto : 6

1          1
 2        2
  3      3
   4    4
    5  5
     6
    5  5
   4    4
  3      3
 2        2
1          1

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