Java Program to Print Alphabet Z Number Pattern

Print Alphabet Z Number Pattern

In the previous article, we have discussed Java Program to Print Alphabet H Number Pattern

In this article we are going to see how to print alphabet ‘H’  number pattern.

Example-1

When rows value = 5

1 2 3 4 5
         4
      3
   2
1 2 3 4 5
Example-2:

When rows value=7

1 2 3 4 5 6 7
               6
            5
         4
      3
   2
1 2 3 4 5 6 7

Now, let’s see the actual program to print it.

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Approach:

  • Enter total number of rows and store it in an integer variable rows.
  • Take for loops to iterate the rows and columns.
  • After each iteration print a new line.

Java Code to Print Alphabet Z Number Pattern

import java.util.Scanner;
class Main
{

public static void main(String[] args)
{
    //Create a new Scanner object
    Scanner scan = new Scanner(System.in);

    //Taking total number of rows as input from user
    System.out.print("Rows : ");
    int rows= scan.nextInt();

    //Row and column are the iterators and counter to print
    int numberOfRows, numberOfColumns;

       //THe dimensions for the pattern
    int top = 1, bot = 1, dia = rows - 1;

    //Prints the top part
    //Iterates from 0 to (2 * rows) -1
    for (numberOfRows = 0; numberOfRows < rows; numberOfRows++)
        System.out.print(top++ + " ");
    //Prints a newline
    System.out.println();

    //Prints the diagonal part
    for (numberOfRows = 1; numberOfRows < rows - 1; numberOfRows++)
    {
        //Inner for loop to print the space
        for (numberOfColumns = 0; numberOfColumns < 2 * (rows - numberOfRows - 1); numberOfColumns++)
            System.out.print(" ");
        System.out.print(dia--);
        //Prints a newline
        System.out.println();
    }
    //Prints the bottom part
    for (numberOfRows = 0; numberOfRows < rows; numberOfRows++)
        System.out.print(bot++ + " ");
}
}

Output

Rows : 7

1 2 3 4 5 6 7
               6
            5
         4 
      3
   2
1 2 3 4 5 6 7

C Code to Print Alphabet Z Number Pattern

#include <stdio.h>

int main()
{
   //Taking total number of rows as input from user
   printf("Rows : ");
   int rows;
   scanf("%d", &rows);

   //Row and column are the iterators and counter to print
   int numberOfRows, numberOfColumns;

   //THe dimensions for the pattern
   int top = 1, bot = 1, dia = rows - 1;

   //Prints the top part
   //Iterates from 0 to (2 * rows) -1
   for (numberOfRows = 0; numberOfRows < rows; numberOfRows++)
      printf("%d ", top++);
   //Prints a newline
   printf("\n");

   //Prints the diagonal part
   for (numberOfRows = 1; numberOfRows < rows - 1; numberOfRows++)
   {
      //Inner for loop to print the space
      for (numberOfColumns = 0; numberOfColumns < 2 * (rows - numberOfRows - 1); numberOfColumns++)
         printf(" ");
      printf("%d ", dia--);
      printf("\n");
   }
   //Prints the bottom part
   for (numberOfRows = 0; numberOfRows < rows; numberOfRows++)
      printf("%d ", bot++);
   return 0;
}
Output:

Rows : 7

1 2 3 4 5 6 7
               6
            5
         4
      3
   2
1 2 3 4 5 6 7

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