Java Program to get ceiling value of a number

Ceiling function java – Java Program to Get Ceiling Value of a Number

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Ceiling function java: In the previous article, we have seen Java Program to Find Cube Root of a Number

In this article we are going to see how to find ceiling value of a given number using Java programming language.

Java Program to Get Ceiling Value of a Number

Before Jumping into the program directly let’s see how to find ceiling value  of any given number.

Explanation:

Ceiling is often used as a rounding function. This is a single-value function.

In java we have Math.ceil() which takes an argument as input and returns a double ceiling value as output.

It returns the closest integer value greater than or equal to a given number and also equal to nearest mathematical integer.

Important-

  • When input argument is an integer then output is also integer.
  • When input argument NaN or an infinity or Positive zero or Negative zero then output is also same as the input argument.
  • When input argument is greater than -1 but less than 0 then output is Negative zero.

Example:

When 
n= 5.3 then ceiling value = 6.0
n= 0.0 then ceiling value = 0.0
n= -463.33 then ceiling value = -463.00
n= -0.11 then ceiling value = -0.0

Let’s see different ways to find ceiling value of a given number.

Method-1: Java Program to Get Ceiling Value of a Number By Using Math.ceil() Method (Static Input)

Approach:

  • Declare double variables to hold input arguments and assign the value to it.
  • Now by using Math.ceil() find the ceiling values of input arguments.
  • Print the result.

Program:

import java.io.*;
class Main
{
    public static void main(String [] args)
    {
        //input arguments declared
        double a = -0.11;
        double b = 5.3;
        double c = 0.0;
        double d = -463.33;
        
        //finding ceiling value by using Math.ceil()
        double ceila = Math.ceil(a);
        double ceilb = Math.ceil(b);
        double ceilc = Math.ceil(c);
        double ceild = Math.ceil(d);
        
        //printing the results
        System.out.println("The ceiling value of  " + a + " is " + ceila);
        System.out.println("The ceiling value of  " + b + " is " + ceilb);
        System.out.println("The ceiling value of  " + c + " is " + ceilc);
        System.out.println("The ceiling value of  " + d + " is " + ceild);
    }
}


Output:

The ceiling value of -0.11 is -0.0
The ceiling value of 5.3 is 6.0
The ceiling value of 0.0 is 0.0
The ceiling value of -463.33 is -463.0

Method-2: Java Program to Get Ceiling Value of a Number By Using Math.ceil() Method (Dynamic Input)

Approach:

  • Declare double variables to hold input arguments and take the values of it as user input by using Scanner class.
  • Now by using Math.ceil() find the ceiling values of input arguments.
  • Print the result.

Program:

import java.util.*;
class Main
{
    public static void main(String [] args)
    {
        //Scanner class object created
        Scanner s = new Scanner(System.in);                               
        System.out.println("Enter input argument to find its ceiling value:");
        double a = s.nextDouble();                                           

        //finding ceiling value by using Math.ceil()
        double ceila = Math.ceil(a);
        
        //printing the results
        System.out.println("The ceiling value of  " + a + " is " + ceila);
    }
}


Output:

Enter input argument to find its ceiling value:
5.3
The ceiling value of 5.3 is 6.0

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