In the previous article, we have discussed about Java Program to Find the Sum of Series 1 – x2/2! + x4/4! – x6/6! + …… xn/n
In this article we are going to see how to find sum of the series (x^2 / 1!) + (x^4 / 3!) + (x^6 / 5!) + … N by using Java programming language.
Java Program to Print the Series (x^2 / 1!) + (x^4 / 3!) + (x^6 / 5!) + … N
Let’s understand the series with an example.
Example:
Suppose the value of X = 2 N = 5 Then series is like: (2^2 / 1!) + (2^4 / 3!) + (2^6 / 5!) => 4 + 16/6 + 64/120 = 7.2
Let’s see different ways to find sum of the series (x^2 / 1!) + (x^4 / 3!) + (x^6 / 5!) + … N
Method-1: Java Program to Find the Sum of Series (x2 / 1!) + (x4 / 3!) + (x6 / 5!) + …… + N By Using For Loop
Approach:
- Declare an int variable say ‘x’ which holds the number of whose we will be calculating the sum of the series.
- Declare an int variable say ‘n’ which holds the last exponent value of the series.
- Create Scanner class object.
- Prompt the user to enter values for
aandn. - By using for loop find term and keep track on its sum.
- Print the result
Program:
import java.util.*;
public class Main
{
public static void main(String args[])
{
//creating object of Scanner class
Scanner s = new Scanner(System.in);
//Taking input of number of elements in the series
System.out.println("Enter the value of x ");
int x = s.nextInt();
//Taking input of number of elements in the series
System.out.println("Enter the value of last exponent 'n' ");
int n = s.nextInt();
//for loop to print the series
double sum = 0;
for (int i = 2; i <= 2 * n; i += 2)
{
long b = 1;
for (int j = 1; j <= i - 1; j++)
{
b *= j;
}
double t = Math.pow(x, i) / b;
sum += t;
}
System.out.println("Sum = " + sum);
}
}
Output: Enter the value of x 2 Enter the value of last exponent 'n' 5 Sum = 7.253615520282186
Method-2: Java Program to Find the Sum of Series (x2 / 1!) + (x4 / 3!) + (x6 / 5!) + …… + N By Using While Loop
Approach:
- Declare an int variable say ‘x’ which holds the number of whose we will be calculating the sum of the series.
- Declare an int variable say ‘n’ which holds the last denominator value of the series
- Create Scanner class object.
- Prompt the user to enter values for
aandn. - By using while loop find term and keep track on its sum.
- Print the result.
Program:
import java.util.*;
public class Main
{
public static void main(String args[])
{
//creating object of Scanner class
Scanner s = new Scanner(System.in);
//Taking input of number of elements in the series
System.out.println("Enter the value of x ");
int x = s.nextInt();
//Taking input of number of elements in the series
System.out.println("Enter the value of last exponent 'n' ");
int n = s.nextInt();
//while loop to print the series
double sum = 0;
int i = 2;
while(i <= 2 * n)
{
long b = 1;
for (int j = 1;j <= i - 1;j++)
{
b *= j;
}
double t = Math.pow(x, i) / b;
sum += t;
i += 2;
}
System.out.println("Sum = " + sum);
}
}
Output: Enter the value of x 2 Enter the value of last exponent 'n' 5 Sum = 7.253615520282186
Method-3: Java Program to Find the Sum of Series (x2 / 1!) + (x4 / 3!) + (x6 / 5!) + …… + N By Using User Defined Method
Approach:
- The same logic as method 1 but this time we are moving the for inside a user-defined method
- Create Scanner class object.
- Prompt the user to enter a number for “x”
- Prompt the user to enter the last denominator value for “n”
- Call a method to execute the sum series
- By using for loop find term and keep track on its sum.
- Print the result.
Program:
import java.util.*;
public class Main
{
public static void main(String[] args)
{
// creating object of scanner class
Scanner s = new Scanner(System.in);
//Taking input of number of elements in the series
System.out.println("Enter the value of x ");
int x = s.nextInt();
//Taking input of number of elements in the series
System.out.println("Enter the value of last exponent 'n' ");
int n = s.nextInt();
// calling m1 method to print the series
m1(x,n);
}
public static void m1(int x, int n)
{
//for loop to print the series
double sum = 0;
for (int i = 2; i <= 2 * n; i += 2)
{
long b = 1;
for (int j = 1; j <= i - 1; j++)
{
b *= j;
}
double t = Math.pow(x, i) / b;
sum += t;
}
System.out.println("Sum = " + sum);
}
}
Output: Enter the value of x 5 Enter the value of last exponent 'n' 10 Sum = 371.0160038182103
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