In the previous article, we have discussed about Java Program to Find the Sum of Series 2-4+6-8+…-/+N
In this article we are going to see how to print sum of the series 1 + 22 / a + 32 / a2 + …… to n terms by using Java programming language.
Java Program to Find the Sum of Series 1 +2^2/a + 3^3/a^2 +…… + N
Example:
Suppose
a = 2
n = 3
1 + 22/2 + 33/22
= 1 + 4/2 + 27/4
= 1 + 2 + 6.85
= 9.75
Let’s see different ways to sum of the series 1 + 22 / a + 32 / a2 + …… to n.
Method-1: Java Program to Find the Sum of Series 1 +2^2/a + 3^3/a^2 +…… + N By Using For Loop
Approach:
- Declare an int variable say ‘
a
’ which holds the value of a. - Declare an int variable say ‘
n
’ which holds the nth term of series - Create Scanner class object.
- Prompt the user to enter values for
a
andn
. - Declare an double variable say
sum
and initialize it with 1. - Use a for loop
from i=2 to i<=n
- Inside for loop we will find
pow(i, i) / Math.pow(a, i-1)
and then add each iteration with ‘sum
‘. - Print the result.
Program:
import java.util.*; public class Main { public static void main(String args[]) { //creating object of Scanner class Scanner s = new Scanner(System.in); //Taking input of number of elements in the series System.out.println("Enter the value of a "); int a = s.nextInt(); //Taking input of number of elements in the series System.out.println("Enter the value of nth term 'n' "); int n = s.nextInt(); //for loop to print the series double sum = 1; for (int i = 2; i <= n; i++) sum += Math.pow(i, i) / Math.pow(a, i - 1); System.out.println("Sum of the series is " + sum); } }
Output: Enter the value of a 2 Enter the value of nth term 'n' 3 Sum of the series is 9.75
Method-2: Java Program to Find the Sum of Series 1 +2^2/a + 3^3/a^2 +…… + N By Using While Loop
Approach:
- Declare an int variable say ‘
a
’ which holds the value of a. - Declare an int variable say ‘
n
’ which holds the nth term of series - Create Scanner class object.
- Prompt the user to enter values for
a
andn
. - Declare an double variable say
sum
and initialize it with 1. - Declare an integer variable say
i
and initialize it with 2. - Continue a while loop till
i<=n
- Inside while loop, find
pow(i, i) / Math.pow(a, i-1)
and then add each iteration with ‘sum
‘. And incrementi
by 1. - Print the result.
Program:
import java.util.*; public class Main { public static void main(String args[]) { //creating object of Scanner class Scanner s = new Scanner(System.in); //Taking input of number of elements in the series System.out.println("Enter the value of a "); int a = s.nextInt(); //Taking input of number of elements in the series System.out.println("Enter the value of nth term 'n' "); int n = s.nextInt(); //while loop to print the series double sum = 1; int i = 2; while(i <= n) { sum += Math.pow(i, i) / Math.pow(a, i - 1); i++; } System.out.println("sum of the series is " + sum); } }
Output: Enter the value of a 2 Enter the value of nth term 'n' 3 sum of the series is 9.75
Method-3: Java Program to Find the Sum of Series 1 +2^2/a + 3^3/a^2 +…… + N By Using User Defined Method
Approach:
- Declare an int variable say ‘
a
’ which holds the value of a. - Declare an int variable say ‘
n
’ which holds the nth term of series - Create Scanner class object.
- Prompt the user to enter values for
a
andn
. - Then call a user defined method say
m1()
by passinga
andn
as parameter. - Inside method declare an double variable say
sum
and initialize it with 1. - Use a for loop
from i=2 to i<=n
- Inside for loop we will find
pow(i, i) / Math.pow(a, i-1)
and then add each iteration with ‘sum
‘. - Print the result.
Program:
import java.util.*; public class Main { public static void main(String[] args) { // creating object of scanner class Scanner s = new Scanner(System.in); //Taking input of number of elements in the series System.out.println("Enter the value of a "); int a = s.nextInt(); //Taking input of number of elements in the series System.out.println("Enter the value of nth term 'n' "); int n = s.nextInt(); // calling m1 method to print the series m1(a,n); } public static void m1(int a, int n) { //for loop to print the series double sum = 1; for (int i = 2; i <= n; i++) sum += Math.pow(i, i) / Math.pow(a, i - 1); System.out.println("Sum of the series is " + sum); } }
Output: Enter the value of a 5 Enter the value of nth term 'n' 10 Sum of the series is 6404.109488640001
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