Java Program to Find Sum of all Even Numbers between 0 to N

In the previous article, we have discussed about Java Program to Find Sum of all Odd Numbers between 0 to N

In this article we will see how to find sum of all even numbers between 0 to N by using Java programming language.

Java Program to Find Sum of all Even Numbers between 0 to N

A number is said to be even number if is divisible by 2.

Means, if the number is even then number % 2 will result 0.

For example:

Number = 16, As 16 % 2 = 0, So it is an even number.

Number = 33, As 33 % 2 = 1, So, it is not an even number.

Let’s see different ways to find sum of all even numbers between 0 to N.

By Using Static Input Value
By Using User Input Value
By Using User Defined Method

Method-1: Java Program to Find Sum of all Even Numbers between 0 to N By Using Static Input Value

Approach:

Declare integer variable N and initialize the value of it. It is the number up to which we will check even numbers add will find sum.
Declare integer variable evenSum and initialize value to 0, it will hold the result i.e. sum of all even numbers.
Using for loop, iterate from 0 to N.
For every number i, check whether it is an even number or not. if(i%2 == 0) then i is an even number else odd.
Add all even numbers in a evenSum variable.

Program:

import java.util.*;
 
public class Main
{
    public static void main(String args[]) 
    {
        //Scanner class object created
        Scanner in = new Scanner(System.in);
        
        //integer variable 'N' taken to hold an integer number 
        //upto which we will check even numbers and will find sum
        int N;
        //integer variable 'evenSum' declared and initialized to 0
        int evenSum = 0;
        //value initialized
        N = 30;
        
        //for loop to iterate from 0 to N
        for(int i = 0; i <= N; i++)
        {
            //if number is even then add it to 'evenSum'
            if((i%2) == 0)
            {
                evenSum += i;
            }
        }
        
        //printing result
        System.out.print("Sum of all even numbers between 0 to "+ N + " = " + evenSum);
    }
}

Output:

Sum of all even numbers between 0 to 30 = 240

Method-2: Java Program to Find Sum of all Even Numbers between 0 to N By Using User Input Value

Approach:

Declare integer variable N and take the value of it as user input using Scanner class. It is the number up to which we will check even numbers add will find sum.
Declare integer variable evenSum and initialize value to 0, it will hold the result i.e. sum of all even numbers.
Using for loop, iterate from 0 to N.
For every number i, check whether it is an even number or not. if(i%2 == 0) then i is an even number else odd.
Add all even numbers in a evenSum variable.

Program:

import java.util.*;
 
public class Main
{
    public static void main(String args[]) 
    {
        //Scanner class object created
        Scanner in = new Scanner(System.in);
        
        //integer variable 'N' taken to hold an integer number 
        //upto which we will check even numbers and will find sum
        int N;
        //integer variable 'evenSum' declared and initialized to 0
        int evenSum = 0;
        //taking the number value input from user
        System.out.print("Enter a number: ");
        N = in.nextInt();
        
        //for loop to iterate from 0 to N
        for(int i = 0; i <= N; i++)
        {
            //if number is even then add it to 'evenSum'
            if((i%2) == 0)
            {
                evenSum += i;
            }
        }
        
        //printing result
        System.out.print("Sum of all even numbers between 0 to "+ N + " = " + evenSum);
    }
}

Output:

Enter a number: 5
Sum of all even numbers between 0 to 5 = 6

Method-3: Java Program to Find Sum of all Even Numbers between 0 to N By Using User Defined Method

Approach:

Declare integer variable N and take the value of it as user input using Scanner class. It is the number up to which we will check even numbers add will find sum.
Declare integer variable evenSum and initialize value to 0, it will hold the result i.e. sum of all even numbers.
Then call a user defined method findSum and pass N and evenSum as parameter.
Inside the method, using for loop, iterate from 0 to N.
For every number i, check whether it is an even number or not. if(i%2 == 0) then i is an even number else odd.
Add all even numbers in a evenSum variable.

Program:

import java.util.*;
 
public class Main
{
    public static void main(String args[]) 
    {
        //Scanner class object created
        Scanner in = new Scanner(System.in);
        
        //integer variable 'N' taken to hold an integer number 
        //upto which we will check even numbers and will find sum
        int N;
        //integer variable 'evenSum' declared and initialized to 0
        int evenSum = 0;
        //taking the number value input from user
        System.out.print("Enter a number: ");
        N = in.nextInt();
        
        //calling user defined method findSum()
        findSum(N, evenSum);
    }
    
    public static void findSum(int N, int evenSum)
    {
        //for loop to iterate from 0 to N
        for(int i = 0; i <= N; i++)
        {
            //if number is even then add it to 'evenSum'
            if((i%2) == 0)
            {
                evenSum += i;
            }
        }
        
        //printing result
        System.out.print("Sum of all even numbers between 0 to "+ N + " = " + evenSum);
    }
}

Output:

Enter a number: 10
Sum of all even numbers between 0 to 10 = 30

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