**How to find square root in java: **In the previous article, we have seen Java Program to Find Logarithm of a Number

In this article we are going to see how to find square and square root of a number using java programming language.

## Java Program to Find Square and Square root of a Number

**How to square root a number in java: **Before jumping into the program directly let’s know what is square and square root of a number.

**Square:** When we multiply the number with itself then we get the square value.

For example:

- If number is 10 then square of 10 is 100.
- If number is 5 then square of 5 is 25.
- If number is 16 then square of 16 is 256.

**Square root:** It is the number which is multiplied with itself to find the actual number.

For example:

- If number is 100 then square root of 100 is 10.
- If number is 5 then square root of 5 is 2.236(approx.)
- If number is 16 then square root of 16 is 4.

Let’s see different ways to find square and square root of a number.

- Square By Multiplying With Itself and Square root By Using Math.sqrt() Method
- Find Square By Multiplying With Itself and Square root By Using Babylonian Method

### Method-1: Java Program to Find Square By Multiplying With Itself and Square root By Using Math.sqrt() Method

**Approach:**

- Create scanner class object.
- Take user input for the number.
- To find the square multiply the number with itself.
- To find square root use
`Math.sqrt()`

method

**Program**:

import java.util.Scanner; public class Main { public static void main(String[] args) { // find the square of a number Scanner sc = new Scanner(System.in); System.out.print("Enter a number to find square: "); double number = sc.nextDouble(); double square = number * number; System.out.println("The square of " + number + " is " + square); // find the square root of a number System.out.print("Enter a number to find square root: "); number = sc.nextDouble(); square = Math.sqrt(number); System.out.println("The square root of " + number + " is " + square); } }

### Method-2: Java Program to Find Square By Multiplying With Itself and Square root By Using Babylonian Method

**Approach:**

- Create scanner class object.
- Take user input for the number.
- To find the square multiply the number with itself.
- To find square root use Babylonian method.

**Program**:

import java.util.Scanner; public class Main { public static void main(String[] args) { // find the square of a number Scanner sc = new Scanner(System.in); System.out.print("Enter a number to find square: "); double number = sc.nextDouble(); double square = number * number; System.out.println("The square of " + number + " is " + square); // find the square root of a number System.out.print("Enter a number to find square root: "); number = sc.nextDouble(); //finding square root by calling square_Root() user defined method System.out.println("The square root of " + number + " is " + square_Root(number)); } //method to find square root public static double square_Root(double num) { double a = num; double b = 1; double e = 0.000001; while (a - b > e) { a = (a + b) / 2; b = num / a; } return a; } }

Output: Enter a number to find square: 5 The square of 5.0 is 25.0 Enter a number to find square root: 16 The square root of 16.0 is 4.000000000000051

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